98 :2+31
200 - 18 : (372:3.x-1)-28=166
(100-99+98-97+96-95+...+4-3+2-1):50+2010-12.x=91
x-(31/3+31/15+31/35+31/63+31/99+31/143)=9/13
#)Giải :
\(200-18:\left(372:3x-1\right)-28=166\)
\(\Leftrightarrow200-18:\left(372:3x-1\right)=194\)
\(\Leftrightarrow18:\left(372:3x-1\right)=6\)
\(\Leftrightarrow372:3x-1=3\)
\(\Leftrightarrow3x-1=124\)
\(\Leftrightarrow3x=125\)
\(\Leftrightarrow x=\frac{125}{3}\)
200 - 18 : (372 : 3 . x - 1) - 28 = 166
=> 200 - 18 : (372 : 3.x - 1) = 166 + 28
=> 200 - 18 : (372 : 3.x) - 1) = 194
=> 18 : (372 : 3.x - 1) = 200 - 194
=> 18 : (372 : 3.x - 1) = 6
=> 372 : 3.x - 1 = 18 : 6
=> 372 : 3.x - 1 = 3
=> 372 : 3.x = 3 + 1
=> 372 : 3.x = 4
=> 3.x = 372 : 4
=> 3.x = 93
=> x = 93 : 3
=> x = 31
#)Next:
\(\left(100-99+98-97+...+2-1\right):50+2010-12x=91\)
\(\Leftrightarrow\left[\left(100-99\right)+\left(98-97\right)+...+\left(2-1\right)\right]:50+2010-12x=91\)
\(\Leftrightarrow\left[1+1+...+1\right]:50+2010-12x=91\)
\(\Leftrightarrow50:50+2010-12x=91\)
\(\Leftrightarrow1+2010-12x=91\)
\(\Leftrightarrow2011-12x=91\)
\(\Leftrightarrow12x=1920\)
\(\Leftrightarrow x=160\)
tính (tính nhanh nếu có thể)
27 x 31 + 31 x 73
16 x 98 + 16 x 2
27 x 31 + 31 x 73
= 31 x ( 27 x 73 )
= 31 x 100
= 3100
16 x 98 + 16 x 2
= 16 x ( 98 + 2 )
= 16 x 100
= 1600
31*(27+73)=31*100=3100
16*(98+2)=16*100=1600
k mik
27 x 31 + 31 x 73
=31x(27+73)
=31x100
=3100
16x98+16x2
=16x(98+2)
=16x100
=1600
tk nha bạn
thank you bạn
(^_^)
ctr a=1+5+5^2+5^3+...+5^97+5^98 chia het cho 31
= ( 1 + 5 + 5^ 2 ) + ( 5^3 + 5^4 + 5^5 ) + ..............+ (5^96 +5^97 + 5^98 )
= 31 + 5^3 . (1 + 5 + 5^2) + ...............+ 5^96 . ( 1 + 5 + 5^2 )
= 31 + 5^ 3 . 31 + .............+ 5^96 . 31
= 31 . ( 1 + 5^3 +...+ 5^96) chia hết cho 31
suy ra A chia hết ch 31
=
=[1+5+52 ] +[53+54+55 ] +......+[596+597+598]
=1*[1+5+52 ] +53*[1+5+52] + ..... +] 596*[1+5+52 ]
=1*31+53*31+56*31+.....+596*31
=31*[1+53+56+.....+596 ] chia hết cho 31
chứng minh rằng:1+5^2+...+5^97+5^98+5^99 chia hét cho 31
bạn kham khỏa link này nha https://olm.vn/hoi-dap/detail/67005481974.html
98*31+62=
a) 98 x 31 + 62
b) 635 x 2
c) 375 x 4
a) 98 x 31 + 62
= 31 x ( 98 + 2 )
=31 x 100
= 3100
b) 635 x 2 =1270
c) 375 x 4 =1500
a) \(98.31+62=98.31+31.2=31.\left(98+1\right)=31.100=3100\)
b) \(635.2=1270\)
c) \(375.4=1500\)
a) 98 x 31 + 62 = 3038 + 62
= 3100 .
b) 635 x 2 = 1270 .
c) 375 x 4 = 1500 .
cho A=1+5^2+5^3+,,,+5^98+5^99 tim so du khi chia A cho 31
Bạn ghi sai đề à
Mình chữa nhé
A=5^1+5^2+5^3+.......+5^98+5^99
5A=5^2+5^3+5^4+......+5^98+5^99+5^100
5A-A=
(5^2+5^3+5^4+.....+5^98+5^99+5^100)-(5^1+5^2+5^3+......+5^98+5^99)
4A=5^100-5^1
A=5^100-5^1:4
cho A=1+5^2+5^3+,,,+5^98+5^99 tim so du khi chia A cho 31
A=(1+5+52)+....+(5+1+52).597+599A=(1+5+52)+....+(5+1+52).597+599A=31+....+597.31+599A=31+....+597.31+599
ta thấy 599=12533599=12533
mà 125 chia 31 dư 1
suy ra 125^33 chia 31 dư 1
suy ra 5^99 chia 31 dư 1
Vậy A chia 31 dư 1
Chứng tỏ rằng: A=1+5+52+...+598 Chia hết cho 31
A = 1 + 5 + 52 + ... + 598
A = (1 + 5 + 52) + (53 + 54 + 55) + ... + (596 + 597 + 598)
A = (1 + 5 + 52) + 53.(1 + 5 + 52) + ... + 596.(1 + 5 + 52)
A = 31 + 53.31 +.... + 596.31
A = 31.(1 + 53 + ... + 596) chia hết cho 31.
Vậy suy ra điều phải chứng minh.