\(\left(x-1\right)^3=125\)

\(\left(x-1\right)^3=5^3\)

\(=>x-1=5\)

\(x=6\)

Tương tự các câu cn lại

a) ( x - 1 ) ³ = 125

( x - 1 ) ³ = 5³

x - 1 = 5

x = 5 + 1

 x = 6

tích nha

Bạn giúp mình làm hết với !  Mình còn nhiều bài tập chưa làm nữa. 

a) \(\left(x-1\right)^3=125\)

\(\Leftrightarrow\left(x-1\right)^3=5^3\)

\(\Leftrightarrow x-1=5\)

\(\Leftrightarrow x=5+1\)

\(\Leftrightarrow x=6\)

Vậy \(x=6\)

b) \(2^{x+2}-2^x=96\)

\(\Leftrightarrow\left(2^2-1\right)\cdot2^x=96\)

\(\Leftrightarrow\left(4-1\right)\cdot2^x=96\)

\(\Leftrightarrow3\cdot2^x=96\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)

Vậy \(x=5\)

c) \(\left(2x+1\right)^3=343\)

\(\Leftrightarrow\left(2x+1\right)^3=7^3\)

\(\Leftrightarrow2x+1=7\)

\(\Leftrightarrow2x=7-1\)

\(\Leftrightarrow2x=6\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\)

d) \(720:\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=2^3\cdot5\left(đk:x\ne23\right)\)

\(\Leftrightarrow720:\left(41-2x+5\right)=8\cdot5\)

\(\Leftrightarrow720:\left(46-2x\right)=40\)

\(\Leftrightarrow\dfrac{720}{46-2x}=40\)

\(\Leftrightarrow\dfrac{720}{2\left(23-x\right)}=40\)

\(\Leftrightarrow\dfrac{360}{23-x}=40\)

\(\Leftrightarrow360=40\left(23-x\right)\)

\(\Leftrightarrow9=23-x\)

\(\Leftrightarrow x=23-9\)

\(\Leftrightarrow x=14\left(đk:x\ne23\right)\)

\(\Leftrightarrow x=14\)

Vậy \(x=14\)

e) \(2^x\cdot7=224\)

\(\Leftrightarrow7\cdot2^x=224\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)

Vậy \(x=5\)

f) \(\left(3x+5\right)^2=289\)

\(\Leftrightarrow3x+5=\pm17\)

\(\Leftrightarrow\left[{}\begin{matrix}3x+5=17\\3x+5=-17\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{22}{3}\end{matrix}\right.\)

Vậy \(x_1=-\dfrac{22}{3};x_2=4\)

a)\(\left(x-1\right)^3=125\Leftrightarrow\left(x-1\right)^3=5^3\Leftrightarrow x-1=5\Leftrightarrow x=6\)b)\(2^{x+2}-2^x=96\Leftrightarrow2^x.2^2-2^x=96\Leftrightarrow2^x\left(2^2-1\right)=96\Leftrightarrow2^x.3=96\Leftrightarrow2^x=32\Leftrightarrow x=5\)c)\(\left(2x-1\right)^3=343\Leftrightarrow\left(2x-1\right)^3=7^3\Leftrightarrow2x-1=7\Rightarrow2x=8\Rightarrow x=4\)d)\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(720:\left[41-\left(2x-5\right)\right]=40\Leftrightarrow\left[41-\left(2x-5\right)\right]=720:40=18\)

\(\Leftrightarrow41-2x+5=18\Leftrightarrow36-2x=18\Leftrightarrow2x=18\Leftrightarrow x=9\)

e)\(2^x.7=224\Leftrightarrow2^x=224:7=32\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)

f) \(\left(3x+5\right)^2=289\Leftrightarrow\left(3x+5\right)=17^2\Leftrightarrow3x+5=17\Leftrightarrow3x=12\Leftrightarrow x=4\)

[X-1]^3=125

[x-1]^3=5^3

x-1=5

x=5+1

x=6

Vậy x=6

a) \(\left(x-1\right)^3=125\)

\(\Rightarrow x-1=5\)

\(\Rightarrow x=6\)

b) \(2^{x+2}-2^x=96\)

\(\Rightarrow2^x.2^2-2^x=96\)

\(\Rightarrow2^x.3=96\)

\(\Rightarrow2^x=32=2^5\)

\(\Rightarrow x=5\)

c) \(\left(2x+1\right)^3=343=7^3\)

\(\Rightarrow2x+1=7\)

\(\Rightarrow x=3\)

\(\left(x-1\right)^3=125\)\(\Rightarrow\left(x-1\right)^3=5^3\Rightarrow x-1=5\)

\(\Rightarrow x=5+1=6\)

\(\left(2x+1\right)^3=343\Rightarrow\left(2x+1\right)^3=7^3\Rightarrow2x+1=7\)

\(2x=7-1=6\Rightarrow x=6:2=3\)

(2x+1)^2=5^2

2x+1=5

x=2

(x-1)^3=-125

x-1=-5

x=-4

a)

(2x+1)²=25

^=> \(\left[\begin{array}{nghiempt}2x+1=5\\2x+1=-5\end{array}\right.\)

=>\(\left[\begin{array}{nghiempt}2x=4\\2x=-6\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=2\\x=-3\end{array}\right.\)

d)

(x-1)³=-125

=> x-1=-5

=> x=-4

còn câu b và c bạn viết đề rõ hơn nha

a) \(2^x\cdot2^2-2^x=96\)

\(2^x\cdot\left(4-1\right)=96\)

\(2^x=32=2^5\)

=> x = 5

b) \(\left(2x+1\right)^3=7^3\)

=> 2x +1 = 7

=> 2x = 6

=> x = 3

Vậy,..........

a. 2^x+2 - 2^x = 96

2^x . 2² - 2^x  = 96

2^x. (2² - 1)  = 96

2^x                = 96 : 3

2^x                = 32

2^x                = 2⁵

x                  = 5

b. (2x + 1)³ = 343

(2x + 1)³     = 7³

2x + 1         = 7

2x               = 7 - 1

x                 = 6 : 2

x                 = 3

a) \(2^{x+2}\)−\(2^x\)=96

\(\Rightarrow\)\(2^x\)·(4−1)=96

\(\Rightarrow2^x\)=32=\(2^5\)

\(\Rightarrow\)\(x=5\)

b) (2x+1)\(^3\)=343

\(\Rightarrow2x+1=7\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

a)\(\left(x-1\right)^3=8\)

\(\Leftrightarrow\left(x-1\right)^3=\left(2\right)^3\)

\(\Leftrightarrow x-1=2\)

\(\Leftrightarrow x=3\)

b)\(2^{x+2}-2^x=96\)

\(\Leftrightarrow2^x.2^2-2^x=96\)

\(\Leftrightarrow2^x\left(2^2-1\right)=96\)

\(\Leftrightarrow2^x=32=2^5\)

\(\Leftrightarrow x=5\)

c)\(\left(2x+1\right)^3=343\)

\(\Leftrightarrow\left(2x+1\right)^3=7^3\)

\(\Leftrightarrow\left(2x+1\right)=7\)

\(\Leftrightarrow x=3\)

d)\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[46-2x\right]=40\)

\(\Leftrightarrow46-2x=18\)

\(\Leftrightarrow2x=28\)

\(\Leftrightarrow x=14\)

a/( X-1)³ =125

=> (X-1)³ =5³

=> X-1=5 => X=6

câu b sai đề rồi bạn