( -2 ) 3 . (\(\frac{3}{4}\)- 0,25 ) : ( 2\(\frac{1}{4}\)- 1\(\frac{1}{6}\))
GIÚP MK NHÉ
Tính: \(A=\left(0,25\right)^{-1}\cdot\left(\frac{1}{4}\right)^{-2}\cdot\left(\frac{4}{3}\right)^{-2}\cdot\left(\frac{5}{4}\right)^{-1}\cdot\left(\frac{2}{3}\right)^{-3}\)
kết bn vs mk nhé, mk thấy cô đơn lắm! :((( T_T
Thực hiện phép tính một cách hợp lí:
a)\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}\)
b)\(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
Giải đầy đủ giúp mk nha, cảm ơn nhìu
thực hiện phép tính :
a, \(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{\frac{7}{6}-58+5+0,7}\)
b, \(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)
c, \(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\)
Mong các bạn giúp đỡ nhé
tính
1/\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{9}}{\left(\frac{1}{4}+\frac{1}{7}-\frac{-3}{35}\right).\left(-1\frac{1}{3}\right)}\)
2/\(\frac{0,6-\frac{1}{3}+\frac{3}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
các bn lm giúp mk vs!!!!
mk đang cần gấp lắm nha!!!!!!!!!
ai lm nhanh nhất đúng đủ trình bày khoa học mk tick cho !!!!!!!1
Chứng minh rằng M < 6 biết:
M = \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{62}+\frac{1}{63}\)
Giúp mk nhé Mai.
\(M=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{62}+\frac{1}{63}\)
\(M=1+\left(\frac{1}{2}+\frac{1}{3}\right)+\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}\right)+\left(\frac{1}{8}+\frac{1}{9}+...+\frac{1}{15}\right)+\left(\frac{1}{16}+\frac{1}{17}+...+\frac{1}{31}\right)+\left(\frac{1}{32}+\frac{1}{33}+...+\frac{1}{63}\right)\)
\(M< 1+\frac{1}{2}.2+\frac{1}{4}.4+\frac{1}{8}.8+\frac{1}{16}.16+\frac{1}{32}.32\)
\(M< 1+1+1+1+1+1\)
\(M< 1.6=6\left(đpcm\right)\)
\(-4\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{6}\right)\le x\le\frac{-2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)
Các bn ơi giúp mk với mk cần gấp!!!!!!!!1
\(-4\frac{1}{2}\left(\frac{1}{2}-\frac{1}{6}\right)\le x\le\frac{-2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)
<=> \(-1,5\le x\le\frac{11}{18}\)
đến đây tự làm
mk k biết điều kiện của x nên giúp đến đó
thực hiện phép tính
a/ \(\frac{15}{34}\)+ \(\frac{7}{21}\)+ \(\frac{19}{34}\)- 1\(\frac{15}{17}\)+ \(\frac{2}{3}\)
b/ 16\(\frac{2}{7}\): (\(\frac{-3}{5}\)) - 28\(\frac{2}{7}\): (\(\frac{-3}{5}\))
c/ ( -2 ) 3 . (\(\frac{3}{4}\)- 0,25 ) : ( 2\(\frac{1}{4}\)- 1\(\frac{1}{6}\))
GIÚP MK NHÉ , ARIGATO , CÁM ƠN RẤT NHIỀU
a/ \(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{32}{17}+\frac{14}{21}=\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{7}{21}+\frac{14}{21}\right)-\frac{32}{17}=1+1-\frac{32}{17}=\frac{2}{17}\)
a) \(\frac{15}{34}\)+ \(\frac{7}{21}\)+ \(\frac{19}{34}\)- \(1\frac{15}{17}\)+ \(\frac{2}{3}\)
= ( \(\frac{15}{34}\)+ \(\frac{19}{34}\)) + ( \(\frac{7}{21}\)+ \(\frac{2}{3}\)) - \(\frac{32}{17}\)
= \(\frac{34}{34}\)+ ( \(\frac{7}{21}\)+ \(\frac{14}{21}\)) - \(\frac{32}{17}\)
= 1 + \(\frac{21}{21}\)- \(\frac{32}{17}\)
= 1+1-\(\frac{32}{17}\)
= 2-\(\frac{32}{17}\)
= \(\frac{34}{17}\)-\(\frac{32}{17}\)
= \(\frac{2}{17}\)
Tính nhah ---- giúp mik giải nâ các bn thank nhiều nhiều
a)\(\frac{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}}{1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}}:\frac{3+\frac{3}{2}+\frac{3}{3}+\frac{3}{4}}{2-\frac{2}{2}+\frac{2}{3}-\frac{2}{4}}+\frac{1}{3}\)
b) \(\frac{\frac{1}{3}-\frac{1}{5}-\frac{1}{7}}{\frac{2}{3}-0,4-\frac{2}{7}}+\frac{\frac{3}{8}-\frac{3}{16}-\frac{3}{32}+\frac{3}{64}}{\frac{1}{4}-\frac{1}{8}-\frac{1}{16}+\frac{1}{32}}\)
c) \(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
giúp mình nhé
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}-\frac{3}{2}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{6}{5}\)
\(=-8+\left(\frac{3}{2}-\frac{3}{2}\right)+1+\frac{6}{5}\)
\(=-7+\frac{6}{5}\)
\(=\frac{-35}{5}+\frac{6}{5}=-\frac{29}{5}\)