Tìm x :
12 + 24 = x + 34
Tìm X biết :
( 28 x 15 - 34 x 12 ) x X : 6 + 8 = 24
\((28\times15-34\times12)\times a:6+8=24\)
\(\Rightarrow12\times a:6=24-8\)
\(\Rightarrow2\times a=16\)
\(\Rightarrow a=16:2=8\)
\(\left(28\times15-34\times12\right)\times x\div6+8=24\)
\(\left(420-408\right)\times x\div6+8=24\)
\(12\times x\div6+8=24\)
\(12\times x\div6=24-8\)
\(12\times x\div6=16\)
\(12\times x=16\times6\)
\(12\times x=96\)
\(x=96\div12\)
\(x=8\)
Tính giá trị biểu thức
A = ( − 10 ) + ( − 34 ) + 40 B = − 5 + − 12 + − 12 + 5 + − 5 + 12 x + ( − 12 ) + ( − 24 ) , x = 30 x + ( − x ) + ( − 18 ) , x = 4
Tính hợp lý nếu có thể:
a. -54.76+12.(-76)+76.(-34)
b. 37.(63-24)-63.(24+37)
Tìm số nguyên x (và y):
a. x+(-17)=-23-x
b. xy+2x-y=15
1a) -54 . 76 + 12 .(-76) + 76.(-34)
= (-54 - 12 - 34).76
= -100 . 76
= -176
b) 37.(63 - 24) - 63.(24 + 37)
= 37 . 63 - 37 . 24 - 63.24 - 63 . 37
= (37.63 - 63.37) - (37 + 63) . 24
= 0 - 100 . 24
= - 2400
2a) x + (-27) = -23 - x
=> x + x = -23 + 27
=> 2x = 4
=> x = 4 : 2
=> x = 2
b) xy + 2x - y = 15
=> x(y + 2) - y = 15
=> x(y + 2) - (y + 2) = 13
=> (x - 1)(y + 2) = 13 = 1 . 13 = 13 . 1
Lập bảng :
x - 1 | 1 | -1 | 13 | -13 |
y + 2 | 13 | -13 | 1 | -1 |
x | 2 | 0 | 14 | -12 |
y | 11 | -15 | -1 | -3 |
Vậy ...
bài 19: tìm x
c) ( 34 - 2x ) . ( 2x - 6 ) = 0
d) ( 2019 - x ) . ( 3x - 12 ) 0
e) 57 . ( 9x - 27 ) = 0
f) 25 + ( 15 - x ) = 30
g) 43 - ( 24 - x ) = 20
h) 2 . ( x - 5 ) - 17 = 25
i) 3 . ( x + 7 ) - 15 = 27
j) 15 + 4 . ( x - 2 ) = 95
k) 20 - ( x + 14 ) = 5
l) 14 + 3 . ( 5 - x ) = 27
nhanh nha, mik tick cho, ccau trình bày dễ hiểu, ko cần ''hoặc''
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6-0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
f) \(25+\left(15-x\right)=30\)
\(\Rightarrow25+15-x=30\)
\(\Rightarrow40-x=30\)
\(\Rightarrow x=40-30\)
\(\Rightarrow x=10\)
g) \(43-\left(24-x\right)=20\)
\(\Rightarrow43-24+x=20\)
\(\Rightarrow19+x=20\)
\(\Rightarrow x=20-19\)
\(\Rightarrow x=1\)
h) \(2\left(x-5\right)-17=25\)
\(\Rightarrow2\left(x-5\right)=17+25\)
\(\Rightarrow x-5=21\)
\(\Rightarrow x=21+5\)
\(\Rightarrow x=26\)
i) \(3\left(x+7\right)-15=27\)
\(\Rightarrow3\left(x+7\right)=27+15\)
\(\Rightarrow x+7=14\)
\(\Rightarrow x=14-7\)
\(\Rightarrow x=7\)
j) \(15+4\left(x-2\right)=95\)
\(\Rightarrow4\left(x-2\right)=95-15\)
\(\Rightarrow4\left(x-2\right)=80\)
\(\Rightarrow x-2=20\)
\(\Rightarrow x=20+2\)
\(\Rightarrow x=22\)
k) \(20-\left(x+14\right)=5\)
\(\Rightarrow x+14=20-5\)
\(\Rightarrow x+14=15\)
\(\Rightarrow x=15-14\)
\(\Rightarrow x=1\)
l) \(14+3\left(5-x\right)=27\)
\(\Rightarrow3\left(5-x\right)=27-14\)
\(\Rightarrow3\left(5-x\right)=13\)
\(\Rightarrow5-x=\dfrac{13}{3}\)
\(\Rightarrow x=5-\dfrac{13}{3}\)
\(\Rightarrow x=\dfrac{2}{3}\)
Tìm các số tự nhiên X biết :
a, ( X-12)x1000=0
b,( 23-X )x34=34
c, ( X-5)x6=24
d,2 X +3=15
e, 6(7X+1)=48
g, ( X -6)(X-34)=0
h, (X-4)(X+2)=0
i, X(X+1)(X+2)=3
\(a,\left(x-12\right)\times1000=0\)
\(x-12=0\)
\(x=0+12\)
\(x=12\)
\(b,\left(23-x\right)\times34=34\)
\(23-x=34:34\)
\(23-x=1\)
\(x=23-1\)
\(x=22\)
\(c,\left(x-5\right)\times6=24\)
\(x-5=24:6\)
\(x-5=4\)
\(x=4+5\)
\(x=9\)
\(d,2x+3=15\)
\(2x=15-3\)
\(2x=12\)
\(x=12:2\)
\(x=6\)
\(e,6\left(7x+1\right)=48\)
\(7x+1=48:6\)
\(7x+1=8\)
\(7x=7\)
\(x=1\)
\(g,\left(x-6\right)\left(x-34\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\x-34=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=6\\x=34\end{cases}}\)
\(h,\left(x-4\right)\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}\)
Bài làm
a) \(\left(x-12\right).1000=0\)
Vì 1000 > 0 \(\Rightarrow x-12=0\Rightarrow x=12\)
b) \(\left(23-x\right).34=34\)
\(\Rightarrow23-x=1\Rightarrow x=22\)
c) \(\left(x-5\right).6=24\Rightarrow x-5=4\Rightarrow x=9\)
d) \(2x+3=15\Rightarrow2x=12\Rightarrow x=6\)
e) \(6\left(7x+1\right)=48\Rightarrow7x+1=8\)
\(\Rightarrow7x=7\Rightarrow x=1\)
g) \(\left(x-6\right).\left(x-34\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\x-34=0\end{cases}\Rightarrow\orbr{\begin{cases}x=6\\x=34\end{cases}}}\)
Vậy x= 6 hoặc x= 34
h)\(\left(x-4\right).\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}}\)
Vậy x=4 hoặc x= -2
i) \(x\left(x+1\right).\left(x+2\right)=3\)
..........
Cậu có thể tam khảo bài làm trên đây ạ, học tốt nha ^^
Tìm x, biết:
a ) | x | − 1 2 = 3 4 ; b ) x − 1 2 = 1 c ) x − 1 2 − 3 4 = 1 4 ; d ) 1 20 − 3 2 − x = 1 40 e ) x + 1 3 2 − 4 9 = 0 f ) x + 1 3 2 + 4 9 = 8 9
a ) x = 5 4 x = − 5 4 b ) x = 3 2 x = − 1 2 c ) x = 3 2 x = − 1 2
d ) x = 59 40 x = 61 40 e ) x = 1 3 x = − 1 f ) x = 1 3 x = − 1
Tìm x thuộc Z
A, -21+(4-x)=-17+(-20)+5
B, (15-x)-(+9)=34-(-31)
C, (17+x)-(-12)=-14-(-10)
D, (x+24)+15=8-17
Giúp mình với mình tick ạ
a) -21 + (4 - x) = -17 + (-20) + 5
=>-21 + 4 - x = -32
=> -17 - x = -32
=> x = -17 + 32
=> x = 15
b) (15 - x) - (+9) = 34 - (-31)
=> 15 - x - 9 = 34 + 31
=> 6 - x = 65
=> x = 6 - 65
=> x = -59
c) (17 + x) - (-12) = -14 - (-10)
=> 17 + x + 12 = -14 + 10
=> 29 + x = -4
=> x = -4 - 29
=> x = -33
c) (x + 24) + 15 = 8 - 17
=> x + 24 + 15 = -9
=> x + 39 = -9
=> x = -9 - 39
=> x = -48
A -21+ ( 4 - x ) = - 17 + ( -20 ) + 5
-21 + 4 - x = - 37 + 5
- 17 - x = - 32
-x = - 17 - ( - 32 )
-x = - 17 + 32
- x = 15
=> x = -15
B ( 15 - x ) - ( + 9 ) = 34 - ( - 31 )
15 - x - 9 = 34 + 31
15 - 9 - x = 65
6 - x = 65
x = 6 - 65
x = -59
C , ( 17 + x ) - ( - 12 ) = - 14 - ( - 10 )
17 + x + 12 = - 14 + 10
29 + x = - 4
x = - 4 - 29
x = - 33
D , ( x + 24 ) + 15 = 8 - 17
x + 24 + 15 = - 9
x + 39 = -9
x = - 9 - 39
x = - 48
bài 19: tìm x
c) ( 34 - 2x ) . ( 2x - 6 ) = 0
d) ( 2019 - x ) . ( 3x - 12 ) 0
e) 57 . ( 9x - 27 ) = 0
f) 25 + ( 15 - x ) = 30
g) 43 - ( 24 - x ) = 20
h) 2 . ( x - 5 ) - 17 = 25
i) 3 . ( x + 7 ) - 15 = 27
j) 15 + 4 . ( x - 2 ) = 95
k) 20 - ( x + 14 ) = 5
l) 14 + 3 . ( 5 - x ) = 27
nhanh nha, mik tick cho, ccau trình bày dễ hiểu, ko cần ''hoặc''
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
bài 19: tìm x
a) 5 . ( x - 7 ) = 0
b) 25 ( x - 4 ) = 0
c) ( 34 - 2x ) . ( 2x - 6 ) = 0
d) ( 2019 - x ) . ( 3x - 12 ) 0
e) 57 . ( 9x - 27 ) = 0
f) 25 + ( 15 - x ) = 30
g) 43 - ( 24 - x ) = 20
h) 2 . ( x - 5 ) - 17 = 25
i) 3 . ( x + 7 ) - 15 = 27
j) 15 + 4 . ( x - 2 ) = 95
k) 20 - ( x + 14 ) = 5
l) 14 + 3 . ( 5 - x ) = 27
a) \(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b) \(25\left(x-4\right)=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=4\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 5.(x-7)=0⇔x-7=0⇔x=7
b) 25(x-4)=0⇔x-4=0⇔x=4
c) (34-2x).(2x-6)=0
⇔ 34-2x=0 hoặc 2x-6=0
⇔2x=34 hoặc 2x=6
⇔ x=17 hoặc x=3
d) (2019-x).(3x-12)=0
⇔ 2019-x=0 hoặc 3x-12=0
⇔ x=2019 hoặc x=4
e) 57.(9x-27)=0
⇔ 9x-27=0
⇔ x=3
f) 25+(15-x)=30
⇔ 15-x=5
⇔ x=10
g) 43-(24-x)=20
⇔ 24-x=23
⇔ x=1
h) 2.(x-5)-17=25
⇔ 2(x-5)=42
⇔x-5=21
⇔ x=26
i) 3(x+7)-15=27
⇔ 3(x+7)=42
⇔ x+7=14
⇔ x=7
j) 15+4(x-2)=95
⇔ 4(x-2)=80
⇔ x-2=20
⇔ x=22
k) 20-(x+14)=5
⇔ x+14=15
⇔ x=1
l) 14+3(5-x)=27
⇔ 3(5-x)=13
⇔ 5-x=13/3
⇔ x=5-13/3
⇔ x=2/3