36-4x9 = 36 - 36 = 0 Vì số nào nhân với 0 thì cũng bằng 0 nên phép tính đó bằng 0

[1+3+...+13+15] x[16 x2+4x16-32x3]                                                                                                                                                                =[1+3+...+13+15] x 0                                                                                                                                                                        =0

( 1 + 3 + .... + 13 + 15 ) x ( 16 * 2 + 4 * 16 - 32 * 3 )

= ( 1+ 3 + ... + 13 + 15) x ( 16 * 2 + 4 * 16 - 16 * 2 * 3)

= ( 1 + 3 + ...+ 13 + 15) x { [ 16 * ( 2 + 4 -  2 * 3 ) ] }

= ( 1 + 3 + ... + 13 + 15 ) x  16 * 0

= ( 1 + 3 + .... +13 +15 ) x 0

=0

(7/15 + 8/15) + (9/16 + 7/16)

= 15/15 + 16/16

= 1 + 1

= 2

đề bài sai sao ý 9/15 mà nếu 9/ 16 thì ko tính thận tiện đc

\(\dfrac{10}{15}\)x\(\dfrac{9}{16}+\dfrac{7}{15}\)x\(\dfrac{10}{15}\)

=> \(\dfrac{10}{15}\)x\(\left(\dfrac{9}{16}+\dfrac{7}{15}\right)\)

=> \(\dfrac{10}{15}\)x\(\dfrac{247}{240}\)

=> \(\dfrac{247}{360}\)

\(\dfrac{9}{4}\times\dfrac{15}{11}+\dfrac{3}{4}:\dfrac{11}{7}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times3\times\dfrac{15}{11}+\dfrac{3}{4}\times\dfrac{7}{11}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times\dfrac{45}{11}+\dfrac{3}{4}\times\dfrac{7}{11}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times\left(\dfrac{45}{11}+\dfrac{7}{11}-\dfrac{8}{11}\right)\)
\(=\dfrac{3}{4}\times4\)
\(=3\)

`9/4xx15/11+3/4:11/7-3/4xx8/11`

`=3/4xx15/11xx3+3/4xx7/11-3/4xx8/11`

`=3/4xx45/11+3/4xx7/11-3/4xx8/11`

`=3/4xx(45/11+7/11-8/11)`

`=3/4xx4`

`=3`

1111+2517536251673521735123517338276349-24546575643356435321=

15 x 6= 90

+ 48= 138 nha 

=15/17 x (4/7 + 3/7) - 1/3
=15/17 x 1 - 1/3
=15/17 x (3/3 - 1/3)
=15/17 x 2/3
=30/51