5/6=1-1/6; 1/2=1-1/2; 3/4=1-1/4; 2/3=1-1/3; 4/5=1-1/5; 12/13=1-1/13; 11/12=1-1/12

1/2>1/3>1/4>1/5>1/6>1/12>1/13

=>1/2<2/3<3/4<4/5<5/6<11/12<12/13<1<33/32<34/33

a 5/9<11/18<11/15<14/15 b 11/14<12/13<33/32<34/31 C 152/253<215/253<26/15<10/10<26/11 đ 1/2<2/3<3/4<4/5<5/6

a) -12,13; -2,4; -2,3; 0,5; 2,4

b) 2,999; 2,9; -2,9; -2,999

a) -12,13; -2,4; -2,3; 0,5; 2,4

b) 2,999; 2,9; -2,9; -2,999

a) - 12,13; - 2,4; - 2,3; 0,5; 2,4

b) 2,999; 2,9; - 2,9; - 2,999

a) -12,13; -2,4; -2,3; 0,5; 2,4

b) 2,999; 2,9; -2,9; -2,999

a) -97 , -16 , -2 , 0 , 5 , 18

b)  I-2018I , 100 , 12 , 0 ,-15 , -40 ,-100

CHÚC BẠN HỌC TỐT

a) Ta có:

\(6 = \sqrt {36} ; - 1,7 =  - \sqrt {2,89} \)

Vì 0 < 2,89 < 3 nên 0> \( - \sqrt {2,89}  >  - \sqrt 3 \) hay 0 > -1,7 > \( - \sqrt 3 \)

Vì 0 < 35 < 36 < 47  nên \(0 < \sqrt {35}  < \sqrt {36}  < \sqrt {47} \) hay 0 < \(\sqrt {35}  < 6 < \sqrt {47} \)

Vậy các số theo thứ tự tăng dần là: \( - \sqrt 3 ; - 1,7;0;\sqrt {35} ;6;\sqrt {47} \)

b) Ta có:

\(\sqrt {5\frac{1}{6}}  = \sqrt {5,1(6)} ; - \sqrt {2\frac{1}{3}}  =  - \sqrt {2,(3)} \); -1,5 = \( - \sqrt {2,25} \)

Vì 0 < 2,25 < 2,3 < 2,(3) nên 0> \( - \sqrt {2,25}  >  - \sqrt {2,3}  >  - \sqrt {2,(3)} \) hay 0 > -1,5 > \( - \sqrt {2,3}  >  - \sqrt {2\frac{1}{3}} \)

Vì 5,3 > 5,1(6) > 0 nên \(\sqrt {5,3}  > \sqrt {5,1(6)} \)> 0 hay \(\sqrt {5,3}  > \sqrt {5\frac{1}{6}}  > 0\)

Vậy các số theo thứ tự giảm dần là: \(\sqrt {5,3} ;\sqrt {5\frac{1}{6}} ;0\); -1,5; \( - \sqrt {2,3} ; - \sqrt {2\frac{1}{3}} \)

\(\dfrac{1}{2}=1-\dfrac{1}{2}\)

\(\dfrac{2}{3}=1-\dfrac{1}{3}\)

\(\dfrac{3}{4}=1-\dfrac{1}{4}\)

\(\dfrac{4}{5}=1-\dfrac{1}{5}\)

\(\dfrac{1}{2}>\dfrac{1}{3}>\dfrac{1}{4}>\dfrac{1}{5}\)

=>\(-\dfrac{1}{2}< -\dfrac{1}{3}< -\dfrac{1}{4}< -\dfrac{1}{5}\)

=>\(1-\dfrac{1}{2}< 1-\dfrac{1}{3}< 1-\dfrac{1}{4}< 1-\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{1}{2}< \dfrac{2}{3}< \dfrac{3}{4}< \dfrac{4}{5}\)

=>\(-\dfrac{1}{2}>-\dfrac{2}{3}>-\dfrac{3}{4}>-\dfrac{4}{5}\)