Tinh S = 0.2+2.4+4.6+........+98.100
nhanh giùm nhé
tinh tổng :
a. S = 0.2 + 2.4 + 4.6 +.......+ 98.100
b. S= 0.2+ 2.4 + 4.6 + .........+ 2n. ( 2n +2 )
Tinh:
a/S=0.2+2.4+4.6+......+98.100
b/ A= 0.2+2.4+4.6+......+ 2n(2n+2)
S=0.2+2.4+4.6+.....+2n ( 2n+2 )
Mk ko hiểu đề bài bn ghi gì Nguyễn Như Quỳnh
tinh tong
S=0.2+2.4+4.6+.....+2n ( 2n+2 )
tính S=0.2+2.4+4.6+...............+2n(2n+2)
\(S=0.2+2.4+4.6+...+2n\left(2n+2\right)\)
\(6S=2.4.6+4.6.\left(8-2\right)+...+2n\left(2n+2\right)\left[\left(2n+4\right)-\left(2n-2\right)\right]\)
\(=2.4.6+4.6.8-2.4.6+...+2n\left(2n+2\right)\left(2n+4\right)-\left(2n-2\right).2n.\left(2n+2\right)\)
\(=2n\left(2n+2\right)\left(2n+4\right)\)
Suy ra \(S=\frac{2n\left(2n+2\right)\left(2n+4\right)}{6}\)
Tính: S=0.2+2.4+4.6+.....+2n ( 2n+2 )
0.2 + 2.4 + 4.6 + .... + 98 + 100
NHANH LÊN MÌNH TICK
cái đề bài của bạn kiểu gì vậy hình như sai rồi
Mình gửi lại câu hỏi nhé:
S = 1/2022 - 5/2.4 - 5/4.6 - ... - 5/2020.2022
(Dấu (.) là dấu nhân các bạn nhé)).
\(S=\frac{1}{2022}-\left(\frac{5}{2.4}+\frac{5}{4.6}+...+\frac{5}{2020.2022}\right)\)
\(A=\frac{5}{2.4}+\frac{5}{4.6}+...+\frac{5}{2020.2022}\)
\(A=\frac{5}{2}\left(\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{2020.2022}\right)\)
\(A=\frac{5}{2}\left(\frac{4-2}{2.4}+\frac{6-4}{4.6}+...+\frac{2022-2020}{2020.2022}\right)\)
\(A=\frac{5}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{2020}-\frac{1}{2022}\right)\)
\(A=\frac{5}{2}\left(\frac{1}{2}-\frac{1}{2022}\right)\)
\(S=\frac{1}{2022}-A=\frac{1}{2022}-\frac{5}{2}\left(\frac{1}{2}-\frac{1}{2022}\right)=-\frac{1262}{1011}\)
1/2.4 + 1/4.6 + 1/6.8 + ... + 1/98.100
có bn nào lm giùm mik vs
\(\frac{1}{2\cdot4}+\frac{1}{4\cdot6}+....+\frac{1}{98\cdot100}\)
\(=\frac{1}{2}\left(\frac{2}{2\cdot4}+\frac{2}{4\cdot6}+.......+\frac{2}{98\cdot100}\right)\)
\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+......+\frac{1}{98}-\frac{1}{100}\right)\)
\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{100}\right)=\frac{49}{200}\)
Đặt A = 1/2.4 + 1/4.6 + .... +1/98.100
\(2A=\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{98.100}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{98}-\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{100}\)
\(=\frac{49}{100}\)
\(\Rightarrow A=\frac{49}{100}\div2=\frac{49}{200}\)
bai1:tinh tong S=1.3+3.5+5.7+...+99.101
bai2 :tinh tong S=1.4+4.7+7.10+...+2017.2020
bai 3: tinh tong N=2.4+4.6+6.8+..+100.102
bai 4: tinh tóng=2.6+6.10+10.14+14.18+...+42.46+50.54
bai 5:tinh tongB=2^2+4^2+6^2+...+100^2
bai 6:C=1^2+3^2+...+100^2
bai7: biet 1^2+2^2+3^2+...+10^2=385 tinh tong 2^2+4^2+6^2+...+20^2
bai 8: tinh tong s=1^2+2^2+3^2+...+99^2
Bài 1 :
\(S=1.3+3.5+5.7+...+99.101=3+15+35+...9999\)
Ta thấy :
\(3=2^2-1\)
\(15=4^2-1\)
\(35=6^2-1\)
.....
\(9999=100^2-1\)
\(\Rightarrow S=2^2+4^2+...+100^2-\left(1\right).\left(\left(100-2\right):2+1\right)\)
\(\Rightarrow S=\dfrac{100.\left(100+1\right)\left(2.100+1\right)}{6}-51\)
\(\Rightarrow S=\dfrac{100.101.201}{6}-51=338299\)
nhanh len nhé mik đang cần gấp ai lam trước mik tích cho
Bài 6 :
\(C=1^2+2^2+...+100^2=\dfrac{100.\left(100+1\right)\left(2.100+1\right)}{6}=\dfrac{100.101.201}{6}=338350\)
Bài 9 :
\(S=1^2+2^2+3^2+...+99^2=\dfrac{99.\left(99+1\right)\left(2.99+1\right)}{6}=\dfrac{99.100.199}{6}=328350\)