\(\frac{43^3+17^3}{43^3+26^3}=\frac{43^3+17^3}{43^3+\left(9+17\right)^3}=\frac{43^3+17^3}{43^3+9^3+17^3}=\frac{43^3+17^3}{\left(43^3+17^3\right)+9^3}=\frac{1}{9^3}=\frac{1}{729}\)

             Ủng hộ mk nha!!!

\(\frac{43^3+17^3}{43^3+26^3}=\frac{43^3+17^3}{43^3+\left(9+17\right)^3}\)=\(\frac{43^3+17^3}{43^3+9^3+17^3}\)=\(\frac{43^3+17^3}{\left(43^3+17^3\right)+9^3}=\frac{1}{9^3}=\frac{1}{729}\)

a) \(3\cdot4\cdot25\cdot8\cdot125\)

\(=\left(125\cdot8\right)\cdot\left(4\cdot25\right)\cdot3\)

\(=1000\cdot100\cdot3\)

\(=300000\)

b) \(36\cdot63+64\cdot663\)

\(=63\cdot\left(36+64\right)\)

\(=63\cdot100\)

\(=6300\)

c) \(45\cdot129+71\cdot129\)

\(=129\cdot\left(129+71\right)\)

\(=129\cdot200\)

\(=25800\)

d) \(26\cdot\left(43+57\right)+74\cdot\left(43+57\right)\)

\(=26\cdot100+74\cdot100\)

\(=2600+7400\)

\(=10100\)

a) 3.4.25.8.125

=3(4.25).(8.125)

=3.100.1000

300000

b) 36.63+ 64.63

=(36+64).63

=100.63

=6300
c) 45.129+ 71.45 

=45.(129+71)

=45.200

=9000              

d) 26. (43+ 57)+ 74(57 +43)

=26.43+26.57 + 74.57 + 74.43

=(26.43+74.43)+(26.57 + 74.57 )

= [43.(26+74)]+[ (26+74).57]

=[43.100]+[100.57]

=4300+5700

= 10000

A = \(\dfrac{18}{26}\) + (-\(\dfrac{5}{27}\)) + (-\(\dfrac{22}{86}\)) + \(\dfrac{12}{39}\) - \(\dfrac{32}{43}\)

A = \(\dfrac{9}{13}\) - \(\dfrac{5}{27}\) -  \(\dfrac{11}{43}\) + \(\dfrac{4}{13}\) - \(\dfrac{32}{43}\)

A = (\(\dfrac{9}{13}\) + \(\dfrac{4}{13}\)) - (\(\dfrac{11}{43}\) + \(\dfrac{32}{43}\)) - \(\dfrac{5}{27}\)

A = \(\dfrac{13}{13}\) - \(\dfrac{43}{43}\) - \(\dfrac{5}{27}\)

A = 1 - 1 - \(\dfrac{5}{27}\)

A = 0 - \(\dfrac{5}{27}\)

A = - \(\dfrac{5}{27}\)

B = -\(\dfrac{10}{12}\) + \(\dfrac{8}{15}\) - \(\dfrac{19}{56}\) + \(\dfrac{3}{-18}\) + \(\dfrac{28}{60}\)

B = - \(\dfrac{5}{6}\) + \(\dfrac{8}{15}\) - \(\dfrac{19}{56}\) - \(\dfrac{1}{6}\) + \(\dfrac{7}{15}\)

B = -(\(\dfrac{5}{6}\) + \(\dfrac{1}{6}\)) - \(\dfrac{19}{56}\) + (\(\dfrac{8}{15}\) + \(\dfrac{7}{15}\))

B = -1  - \(\dfrac{19}{56}\) + 1

B = - \(\dfrac{19}{56}\) 

\(VT=\frac{\left(43+17\right)\left(43^2-43.17+17^2\right)}{\left(43+26\right)\left(43^2-43.26+26^2\right)}=\frac{\left(43+17\right)\left[43^2-17\left(43-17\right)\right]}{\left(43+26\right)\left[43^2-26\left(43-26\right)\right]}.\)

\(VT=\frac{\left(43+17\right)\left(43^2-17.26\right)}{\left(43+26\right)\left(43^2-26.17\right)}=\frac{43+17}{43+26}=VP\left(dpcm\right)\)

\(\frac{43^3+17^3}{43^3+26^3}=\frac{\left(43+17\right)\left(43^2-43×17+17^2\right)}{\left(43+26\right)\left(43^2-43×26+26^2\right)}=\frac{\left(43+17\right)×1407}{\left(43+26\right)×1407}=\frac{43+17}{43+26}\left(dpcm\right)\)

hãy quy đồng các phân số sau

A = 18/26 + -5/27 + -22/86 + 12/39 + -32/43 

A = 9/13 + -5/27 + -11/43 + 4/13 + -32/43

A = -5/27 + ( 9/13 + 4/13 ) + ( -11/43 + -32/43 )

A = -5/27 + 1 + ( -1)

A = -5/27 + 0 

A = 0

B = -10/12 + 8/15 + -19/56 + 3/-18 + 28/60

B = -5/6 + 8/15 + -19/56 + -1/6 + 7/15

B = -19/56 + ( -5/6 + -1/6 ) + ( 8/15 + 7/15 ) 

B = -19/56 + ( -1 ) + 1

B = -19/56 + 0

B = 0

Thông cảm ...Vì không biết sử dụng phân số nên đành viết bằng dấu gạch chéo

Muốn giải lắm nhưng mới lớp 7 thôi, bạn có thể hỏi vào sáng mai 

các bạn siêng thiệt 12h04' mà còn thức để lên online math