a. 4.37.25.50.12

  =(4.25).(50.12).37

  =100.600.37

  =2220000

\(a.\left(4.50\right).\left(25.12\right).37\)

\(=200.300.37=2220000\)

\(b.\left(46+54\right)+\left(17+83\right)\)

\(=100+100=200\)

\(c.87.\left(36+69\right)=87.105=9135\)

\(d.\left(135+65\right)+\left(360+40\right)\)

\(=200+400=600\)

\(e.\left(463+137\right)+\left(318+22\right)\)

\(=600+340=940\)

a,4x37x25x50x12=(50.4).(25.12).37=200.300.37=2220000

b,46+17+54+83=(46+54)+(17+83)=100+100=200

c,87.36+87.69=87.(36+69)=87.105=9135

d,135+65+360+40=(135+65)+(360+40)=200+400=600

e,463+318+137+22=(463+137)+(318+22)=600+340=940

A=17x32+64x83+36x83+68x17

   A=17x32+17x68+64x83+36x83

A=17x(32+68)+83x(64+36)

A=17x100+83x100

A=100x(83+17)

A=100x100

A=10000

A=17x32+64x83+36x83+68x17

  = 17x32+68x17+ 64x83+36x83

  = 17 x (32 +68) +83x(64+36)

  =  17x100 + 83x100

  =      1700 + 8300

  =             10000

*k cho mình nha

a)135-35.(-37)+37.(-42-48)=-4490

b)-65.(87-17)-87.(17-65)=-374

1.a. 86+357+14 = (86+14)+357 = 100+357 = 457

b. 72+69+128 = (72+128) +69 = 200+69 = 269

c. 25.5.4.27.2 = (25.4).(5.2).27=100.10.27=1000.27=27000

d. 28.64+28.36=28.(64+36)=28.100=2800

2. a. 135+360+65+40= (135+65)+(360+40)=200+400=600

b. 463+318+137+22 = (463+137)+(318+22)=600+340=940

c. = (20+30)+(21+29)+...+(24+26)+25

= 50+50+50+50+25

= 225

7)    \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)

\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+36}{65}+1+\frac{x+40}{60}+1\)

\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)

\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)

\(\Leftrightarrow\)\(x+100=0\)            (vì 1/75 + 1/70 - 1/65 - 1/60  \(\ne\)0)

\(\Leftrightarrow\)\(x=-100\)

Vậy.....

7)    \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)

\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+35}{65}+1+\frac{x+40}{60}+1\)

\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)

\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)

\(\Leftrightarrow\)\(x+100=0\)    (1/75 + 1/70 - 1/65 - 1/60 \(\ne\)0)

\(\Leftrightarrow\)\(x=-100\)

Vậy...

11+12+13+14+15+16+17+18+19+...+89+88+87+86+85+84+83+82

=( 11 + 89 )+(12+88)+(13+87)+(14+86)+(15+85)+(16+84)+(17+83)+(18+82)+19

=100+100+100+100+100+100+100+100+19

=800+19

=819

9: \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)

=>x-99=0

hay x=99

7: \(\Leftrightarrow\left(\dfrac{x+25}{75}+1\right)+\left(\dfrac{x+30}{70}+1\right)=\left(\dfrac{x+35}{65}+1\right)+\left(\dfrac{x+40}{60}+1\right)\)

=>x+100=0

hay x=-100

8:

Sửa đề: \(\dfrac{99-x}{101}+\dfrac{97-x}{103}+\dfrac{95-x}{105}+\dfrac{93-x}{107}=-4\) 

\(\Leftrightarrow\left(\dfrac{99-x}{101}+1\right)+\left(\dfrac{97-x}{103}+1\right)+\left(\dfrac{95-x}{105}+1\right)+\left(\dfrac{93-x}{107}+1\right)=0\)

=>200-x=0

hay x=200

13 + 21.5 - (198 : 11 - 8)

= 13 + 105 - 10

= 108

272 : 16 - 5 +4 (30 - 5 - 255 : 17)

= 17 - 5 + 4. ( 30 - 5 - 15 )

= 16 . 10

= 160

15.24 - 14.5 (145 : 5 - 27)

= 360 - 70 ( 29 - 27 )

= 290 . 2

= 580

18.3 - 18.2 + 3 (51 : 17)

= 54 - 36 + 3 . 3

= 54 - 36 + 9

= 27

(64 + 115 + 36) - 25.8

= 215 - 200 

= 15

15.8 - (17 - 30 + 83) - 144 : 6

= 120 - 70 - 24

= 26

250 : 50 - (46 - 75 + 54) : 5

= 5 - 25 : 5 

= 5 - 5

= 0

13 (17 - 95 + 83) : 5 - 18 : 9

= 13. 5 : 5 - 2

= 65 : 5 - 2

= 13 - 2

= 11

140 - 180(47 - 90 + 43) + 7

= 140 - 180 . 0 + 7

= 140 + 7

= 147

24 (15 + 30 + 85 - 120):10

= 24. 10 : 10 

= 240 : 10

= 24

27 + 73 - 30 : (25 -10)

= 27 + 73 - 30 : 15

= 27 + 73 - 2

= 98

18 - 4 (27 - 90 + 73) : 10

= 18 - 4. 10 : 10

= 18 - 40 : 10

= 18 - 4

= 14

Bài 2: Tính

140 - [ 25 : (4 mũ 2 - 11) + 4 ]

= 140 - [25 : (16 - 11) + 4 ]

= 140 - [ 25 : 5 + 4 ]

= 140 - [ 5 + 4]

= 140 - 9 

= 131