=> x-11+x=-48:(x-12)

=> 2x-11=-48:(x-12)

=> (2x-11).(x-12) = 48

Đến đó bạn dùng quan hệ ước bội mà giải nha

Tk mk nha

X=-0,326 mik ko chac dau nhung ....k cho mik nha

a)x-(11-x)=48+(-12+x)                                       b)(15-x)+(x-12)=7-(-8+x)

  x-11+x =48-12+x                                                15-x+x-12  =7+8-x

  2x-11   =36+x                                                                 3  =15-x 

   x-11   =36                                                                     x  =15-3 

   x        =36+11                                                              x   =12

   x        47

x – (11 – x) = -48 + (-12 + x)

=> x−11+x=−48+−12+x

=> −11+x=−48−12

=> -11+x=-60

=> x=-49

Vậy x=-49

\(x-\left(11-x\right)=-48+\left(-12+x\right)\)

\(\Leftrightarrow x-11+x=-48-12+x\)

\(\Leftrightarrow x=-49\)

Vậy x = -49

x - ( 11 - x ) = -48 + ( -12 + x )

⟺ x - 11 + x = -48 - 12 + x 

⟺ x = -49

Vậy x = -49

#Học tốt#

\(\frac{12x-15y}{7}=\frac{20z-12x}{9}=\frac{15y-20z}{11}=\frac{12x-15y+20z-12x+15y-20z}{7+9+11}=0\)

\(12x-15y=0\Rightarrow4x=5y\Rightarrow\frac{x}{5}=\frac{y}{4}\)

\(20z-12x=0\Rightarrow5z=3x\Rightarrow\frac{z}{3}=\frac{x}{5}\)

\(15y-20z=0\Rightarrow3y=4z\Rightarrow\frac{y}{4}=\frac{z}{3}\)

\(\Rightarrow\frac{x}{5}=\frac{y}{4}=\frac{z}{3}=\frac{x+y+z}{5+4+3}=\frac{48}{12}=4\)

ta có;x=4x5=20

y=4x4=16

z=4x3=12

Áp dụng tính chất dãy tỉ số bằng nhau , ta có :

\(\frac{12x-15y}{7}=\frac{20z-12}{9}=\frac{15y-20z}{11}=\frac{\left(12-15-20\right)\left(x+y+z\right)}{7+9+11}=\frac{48}{-23}=25\)

Suy ra :

bạn tự làm

a) x - (11 - x) = -48 + (-12 + x)

x - 11 + x = -48 + (-12) + x

x + x - x = -48 + (-12) + 11

x + 0 = (-60) + 11

x = -49

b) (15 - x) + (x - 12) = 7 - (-8 + x)

15 - x + x - 12 = 7 + 8 + x

15 - x + x - 12 = 15 + x

x + x - x = 15 - 15 + 12

x + 0 = 0 + 12

x = 12

c) (x - 12) - (2x + 31) = -6 - 5

x - 12 - 2x - 31 = -1

x - 12 - 2x = -1 + 31

x - 12 - 2x = 30

x - 2x = 30 + 12

-1x = 42

=> x = -42

d) |x + 5| - (-17) = 20

=> |x + 5| + 17 = 20

=> |x + 5| = 20 - 17

=> |x + 5| = 3

=> \(\orbr{\begin{cases}x+5=3\\x+5=-3\end{cases}}\)

=> \(\orbr{\begin{cases}x=3-5\\x=-3-5\end{cases}}\)

=> \(\orbr{\begin{cases}x=-2\\x=-8\end{cases}}\)

12x² - 3x = 0

=> 12x² - 3x = (2² . 3x²) - 3x = 0

=> 3x . (4x - 1) = 0

=> 3x . 4x - 3x . 1 = 0

=> 3x . 4x - 3x = 0

=> 12x - 3x = 0

=> 4x  =0

=> x = 0

x=0 chac chan

Thanks bạn nhìu!

=>x^2+x-x+2=11

=>x^2=9

=>x=3 hoặc x=-3

\(x\left(x+1\right)-\left(x-2\right)=11\)

\(\Rightarrow x^2+x-x+2=11\)

\(\Rightarrow x^2+2=11\)

\(\Rightarrow x^2=11-2\)

\(\Rightarrow x^2=9\)

\(\Rightarrow x^2=3^2\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)