Cho S=1+2+4+8+16+32+64+.............
Ở đây,S rõ ràng là số dương
S-1=2+4+8+16+32+64+...........
2S=2+4+8+16+32+64+.........
suy ra 2S=S-1
S=-1
Vậy lỗi sai nằm ở đâu ?
Gợi ý: hãy tìm hiểu khái niệm của chuỗi hội tụ
a) 128:8:4=16:4=4 Đ hay S
b) 128:8:4=128:2=64 Đ hay S
c) 32:4×2=8×2=16 Đ hay S
d) 32:4×2=32×8=256 Đ hay S
EM CẦN GẤP, GIÚP EM VỚI
a) \(128:8:4=16:4=4\) Đúng
b) \(128:8:4=128:2=64\) Sai
c) \(32:4\) x \(2=8\) x \(2=16\) Đúng
d) \(32:4\) x \(2=32\) x \(8=256\) Sai
1+1+2+2+4+4+8+8+16+16+32+32+64+64=?
bk nha@ >_0
1+1+2+2+4+4+8+8+16+16+32+32+64+64=254
Tính tổng: S= 1/2+1/4+ 1/8+ 1/16+1/32+1/64+1/128
Cộng thêm 1/2 vào biểu thức đã cho, có:
S + 1/2= 1/2+1/4+ 1/8+ 1/16+1/32+1/64+1/128
Nhận xét:
tính nhanh p/s 1+ 5/4 + 5/8 + 5/16 + 5/32 + 5/64
b) 1/3 +1/9 + 1/27 + 1/81 +...........+ 1/59049
c) 3/2 + 3/8 + 3/32 +3/128 + 3/512
d) 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 giúp mình với
b: A=1/3+1/9+...+1/3^10
=>3A=1+1/3+...+1/3^9
=>A*2=1-1/3^10=(3^10-1)/3^10
=>A=(3^10-1)/(2*3^10)
c: C=3/2+3/8+3/32+3/128+3/512
=>4C=6+3/2+...+3/128
=>3C=6-3/512
=>C=1023/512
d: A=1/2+...+1/256
=>2A=1+1/2+...+1/128
=>A=1-1/256=255/256
S=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
hỏi S bằng bao nhiêu ?
1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
= 1 – 1/2 + 1/2- 1/4 + 1/4 – 1/8 + 1/8 – 1/16 + 1/16 – 1/32 + 1/32 – 1/64 + 1/64 – 1/128 + 1/128 – 1/256 – 1/256 – 1/512
= 1 – 1/512
= 511/512
1+1
2+2
4+4
8+8
16+16
32+32
64+64
128+128
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
tk m nhé
S=1/4+1/8+1/16+1/32+1/64+1/128
S=1/4+1/8+1/16+1/32+1/64+1/128
\(S=\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\)
\(2S=2\left(\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)
\(2S=\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^6}\)
\(2S-S=\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^6}\right)-\left(\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)
\(S=\frac{1}{2}-\frac{1}{2^7}\)
S=(1/2-1/4)+(1/4-1/8)+(1/8-1/16)+(1/16-1/32)+(1/32-1/64)+(1/64-1/128)
S=1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64+1/64-1/128
S=1/2-(1/4-1/4)+(1/8-1/8)+(1/16-1/16)+(1/32-1/32)+(1/64-1/64)-1/128
S=1/2-1/128
S=63/128
1+1=?
2+2=?
4+4=?
8+8=?
16+16=?
32+32=?
64+64=?
128+128=?
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
1+1=2
2+2=44+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
tính tổng :
S = 1/2 + 1/4 +1/8 + 1/16 +1/32 +1/64 . ( bài tính nhanh đấy , giúp mình nhé )
S=1/2+1/4+1/8+1/16+1/32+1/64
S=1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64
S=1-1/64
S=63/64
S = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
2S = 1/2 x 2 +1/4 x 2 + 1/8 x 2 + 1/16 x 2 + 1/32 x 2 + 1/64 x 2
2S =1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32
2S - S = ( 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 ) - ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 )
S = 1 - 1/64
S = 63/64