Ta có:

\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)

\(\Rightarrow M=20\left(\frac{1}{8.14}+\frac{1}{14.20}+\frac{1}{20.26}+\frac{1}{26.32}\right)\)

\(\Rightarrow M=\frac{20}{6}\left(\frac{6}{8.14}+\frac{6}{14.20}+\frac{6}{20.26}+\frac{6}{26.32}\right)\)

\(\Rightarrow M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)

\(\Rightarrow M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{32}\right)\)

\(\Leftrightarrow M=\frac{10}{3}.\frac{3}{32}=\frac{5}{16}\)

Vậy \(M=\frac{5}{16}\)

là sao bạn ?

Tính M à bạn ?

\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)

\(M=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)

\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{14}\right)+\frac{10}{3}.\left(\frac{1}{14}-\frac{1}{20}\right)+\frac{10}{3}.\left(\frac{1}{20}-\frac{1}{26}\right)+\frac{10}{3}.\left(\frac{1}{26}-\frac{1}{32}\right)\)

\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)

\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{32}\right)\)

\(M=\frac{10}{3}.\frac{3}{32}\)

\(M=\frac{5}{16}\)

M =20/8.14 +20/14.20 +20/20.26 +20/26.32

M= 20/6 .(1/8-1/14 +1/14-......+1/26-1/32)

M  = 20/6 .(1/8 -1/32)

M=20/6 .3/32

M=5 /16

=5/16

t.i.c.k nha

M = \(\frac{5}{16}\) 

Ai thấy mk làm đúng nhớ li-ke nha! Thanks!!! Chúc các bạn học tốt nhé! Kì thi cuối học kì 2 cũng đã tới, em xin chúc các anh chị Trung học, chị chúc các em Tiểu học và mình cũng chúc các bạn thi đạt điểm cao nhé! (Đặc biệt các bạn lớp 5 nhớ thi được điểm cao để vào lớp chọn nha!)

\(\frac{20}{8\cdot14}+\frac{20}{14\cdot20}+\frac{20}{20\cdot26}+\frac{20}{26\cdot32}\)\(\Rightarrow\frac{10}{3}\left(\frac{6}{8\cdot14}+\frac{6}{14\cdot20}+\frac{6}{20\cdot26}+\frac{6}{26+32}\right)\)

\(M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)\(\Rightarrow M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{32}\right)=\frac{10}{3}\cdot\frac{3}{32}=\frac{10}{32}\)

k cho mình nha!

\(M=\frac{15}{56}+\frac{1}{14}+\frac{1}{26}+\frac{5}{208}\)

\(M=\frac{15}{56}+\frac{4}{56}+\frac{8}{208}+\frac{5}{208}\)

\(M=\frac{19}{56}+\frac{13}{208}=\frac{45}{112}\)

mai anh là ai

\(M=\frac{15}{56}+\frac{4}{56}+\)

\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)

\(M=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)

\(M=\frac{20}{6}.\left(\frac{6}{8.14}+\frac{6}{14.20}+\frac{6}{20.26}+\frac{6}{26.32}\right)\)

\(M=\frac{20}{6}.\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)

\(M=\frac{20}{6}.\left(\frac{1}{8}-\frac{1}{32}\right)\)

\(M=\frac{20}{6}.\frac{3}{32}\)

\(M=\frac{5}{16}\)

\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)

\(\Rightarrow\frac{1}{M}=\frac{112}{20}+\frac{280}{20}+\frac{520}{20}+\frac{832}{20}\)

\(\Rightarrow\frac{1}{M}=\frac{1744}{20}=\frac{436}{5}\)

\(\Rightarrow M=\frac{5}{436}\)

\(2A=2\left(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2012}}\right)=2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2011}}\)

\(2A-A=\left(2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2011}}\right)-\left(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2012}}\right)\)

\(A=2-\frac{1}{2^{2012}}\)

k nha

Nhân 2A lên rồi lấy 2A-A là ra kết quả

\(A=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2012}}\)

\(\Rightarrow2A=2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2011}}\)

\(\Rightarrow A=2A-A\)

\(\Rightarrow A=2-\frac{1}{2^{2012}}\)

\(S=3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\)=> \(2S=6+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^8}\)

=>\(2S-S=\left(6+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\right)\)

=>\(S=3+\frac{3}{2}-\frac{3}{2^9}\) tự tính nốt