a)A = (a - b) – (a – b + c)

A=a-b-a+b-c

A=(a-a)+(b-b)-c

A=-c

b)B = (a + b + c) – (a + b - 5)

B=a+b+c-a-b+5

B=(a-a)+(b-b)+(c+5)

B=c+5

a) A = (a - b) - (a - b + c)

A = a - b - a + b - c

A = -c

b) B = (a + b + c) - (a + b - 5)

= a + b + c - a - b + 5

= c + 5

a) A = (a - b) - (a - b + c)

    A = (a - b) - (a - b) + c

    A = 0 + c

    A = c

b) B = (a + b + c) - (a + b - 5)

    B = c - (-5)

    B = c + 5

B1:

a,  a+b+(-a)+b+a+(-c)+(-a)+(-c)=[a+(-a)+a+(-a)]+(b+b)+[(-c)+(-c)]=0+2.b+(-2).c

b,  a+b+(-c)+a+(-b)+c+(-b)+(-c)+a+(-a)+b+c=[a+a+a+(-a)]+[b+(-b)+(-b)+b]+[(-c)+c+(-c)+c]=2.a+0+0=2a

B2:

N=(a+b)-(a-b)+(a+b)=a+b+(-a)+b+a+b=[a+(-a)+a)+(b+b+b)=a+3.b

NẾU CẬU KHÔNG HIỂU THÌ CỨ HỎI NHÉ!

rút gọn biểu thức

a,A=(a-b)-(a-b+c)

b,B=-(a+b+c)-(a+b-5)

uk nha bạn

1) \(=ac+ad+bc+bd-ab-ac-db-dc=ad+bc-dc-ab=d\left(a-c\right)-b\left(a-c\right)=\left(a-c\right)\left(d-b\right)\)

2) \(=ac-ad+bc-bd-ac-ad+bc+bd=2bc-2ad=2\left(bc-ad\right)\)

3) \(\left(a+b\right)\left(a+b\right)-\left(a-b\right)\left(a-b\right)=a^2+2ab+b^2-a^2+2ab-b^2=4ab\)

a) `A=(a+b)-(a-b)+(a-c)-(a+c)`

`=a+b-a+b+a-c-a-c`

`=2b-2c`

b) `B=(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)`

`=a+b-c+a-b+c-b-c+a-a+b+c`

`=2a`

\(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)

\(A=a+b-a+b+a-c-a-c\)

\(A=2b-2c\)

\(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\)

\(B=a+b-c+a-b+c-b-c+a-a+b+c\)

\(B=2a\)

a) \(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\) 

\(A=a+b-a+b+a-c-a-c\) 

\(A=\left(a-a+a-a\right)+\left(b+b\right)+\left(-c-c\right)\) 

\(A=0+2b+-2c\) 

\(A=2b-2c\) 

b) \(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\) 

\(B=a+b-c+a-b+c-b-c+a-a+b+c\) 

\(B=\left(a+a+a-a\right)+\left(b-b-b+b\right)+\left(-c+c-c+c\right)\) 

\(B=2a+0+0\) 

\(B=2a\)

a, -( -a + c - d) - ( c - d + d) =  a - c + d - c + d - d =  a + d

b, - ( a+b-c+d) + (a-b-c-d) = -a -b+c-d + a-b-c-d = -2b + (-2c)= -2(b+c)