=(-1)

học 

tốt 

nha

FF = \(\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)

F = \(\frac{-1}{3}+\frac{6}{15}+\frac{-2}{3}+\frac{-3}{5}+\frac{3}{15}\)

F = \((\frac{-1}{3}+\frac{-2}{3})+(\frac{6}{15}+\frac{3}{15})+\frac{-3}{5}\)

F = \(\frac{-3}{3}+\frac{9}{15}+\frac{-3}{5}\)

F = \(-1+\frac{3}{5}+\frac{-3}{5}\)

F =\(-1+0\)

F = \(-1\)

Vậy F = \(-1\)

- 1  đúng thì tik nha

Cách giải bn ơi

    \(\dfrac{-4}{12}+\dfrac{18}{45}+\dfrac{-6}{9}+\dfrac{-21}{35}+\dfrac{6}{30}\)
\(=\dfrac{-1}{3}+\dfrac{2}{5}+\dfrac{-2}{3}+\dfrac{-3}{5}+\dfrac{1}{5}\)
\(=\left(\dfrac{-1}{3}+\dfrac{-2}{3}\right)+\left(\dfrac{2}{5}+\dfrac{-3}{5}+\dfrac{1}{5}\right)\)
\(=-1+0\)
\(=-1\)

\(\#PeaGea\)

\(E=\dfrac{-1}{3}-\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{1}{5}=-1\)

\(B=\dfrac{-4}{12}+\dfrac{18}{45}+\dfrac{-6}{9}+\dfrac{-21}{35}+\dfrac{6}{30}=\dfrac{-1}{3}-\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{1}{5}=-1\)

-4/12 + 18/45 - 6/9 - 21/35 + 6/30

= -1/3 + 2/5 - 2/3 - 3/5 + 1/5

= (2/5 - 3/5 + 1/5) - (1/3 + 2/3)

= 0 - 1

= -1

\(=-\frac{1}{3}+\frac{2}{5}-\frac{2}{3}-\frac{3}{5}+\frac{1}{5}\)

\(=\left(-\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{2}{5}-\frac{3}{5}+\frac{1}{5}\right)\)

\(=-1+0\)

\(=-1\)

=.= hk tốt!!

\(A=\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}\)

\(A=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}\)

\(A=-1+1+\frac{-1}{5}\)

\(A=\frac{-1}{5}\)

\(B=\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)

\(B=\frac{-1}{3}+\frac{2}{5}+\frac{-2}{3}+\frac{-3}{5}+\frac{1}{5}\)

\(B=\left(\frac{-1}{3}+\frac{-2}{3}\right)+\left(\frac{2}{5}+\frac{-3}{5}+\frac{1}{5}\right)\)

\(B=-1+0\)

\(B=-1\)