66 -55 - 11 - 0 - 0 -0 - 0 - 0 - 0 - 2
66 x 1
11.x=-55
-3x=-12
0 . x=4
-(-2).x=6
(x+5) . (x-4) = 0
(x-1) . (x-3)=0
(3-x)-(x-3)=0
x. (x+1)=0
Giúp mik
a) x = .5
b) x = 4
c) x không tồn tại
d) x = 3
e) \(\orbr{\begin{cases}x=-5\\x=4\end{cases}}\)
g) \(\orbr{\begin{cases}x=1\\x=3\end{cases}}\)
h) x = 3
i) 0
11 . x = -55
x = -55 : 11
x = -5
-3x = -12
x = -12 : -3
x = 4
0 . x = 4
x = 4 : 0
x = 0
Sorry , mình làm lại .
a, 11 . x = -55
x = -55 : 11
x = -5
b, -3x = -12
x = -12 : -3
x = 4
c, 0 . x = 4
\(\Rightarrow x\in\varnothing\)
d, - ( -2 ) . x = 6
x = 6 : [ - ( - 2 ) ]
x = 3
1 tính nhanh
1, 66.(-55) +33 . (-90)
2.tìm x
1 (x-11).(x+5)=0
2.(x-2).(x+4)=0
3 (x-2).(x+15)=0
4.(7-x).(x+19)=0
5.-5<x<1
6|x|<3
7 (x-3).(x-3) <3
bài 3 tính tổng các số nguyên x thõa mãn
|x|<2013
1 tính nhanh
1, 66.(-55) +33 . (-90) = 33.2.(-55) + 33 . (-90) = 33.(-110) + 33 . (-90) = 33. (-110 - 90) = 33. (-200) = -6600
2.tìm x
1 (x-11).(x+5)=0
TH1 : x - 11 = 0
=> x = 11
TH2 : x + 5 = 0
=> x = -5
Vậy x = 11 hoặc -5
2.(x-2).(x+4)=0
TH1 : x - 2 = 0
=> x = 2
TH2 : x + 4 = 0
=> x = -4
Vậy x = 2 hoặc -4
3 (x-2).(x+15)=0
TH1 : x - 2 = 0
=> x = 2
TH2 : x + 15 = 0
=> x = -15
Vậy x = 2 hoặc -15
4.(7-x).(x+19)=0
TH1 : 7- x = 0
=> x = 7
TH2 : x + 19 = 0
=> x = -19
Vậy x = 7 hoặc -19
5.-5<x<1
\(\Rightarrow x\in\left\{-4;-3;-2;-1;0\right\}\)
6. |x|<3
\(\Rightarrow x\in\left\{-2;-1;0;1;2\right\}\)
bài 3 tính tổng các số nguyên x thõa mãn
|x|<2013
Ta có: | x | < 2013
=> x \(\in\left\{\text{-2012;-2011;-2010;...;2010;2011;2012}\right\}\)
Tổng tất cả các số nguyên x là:
(-2012 + 2012) + (-2011 + 2011) + (-2010 + 2010) +...+ (-1 + 1) + 0
= 0 + 0 + 0 +... + 0 + 0 = 0
Vậy tổng tất cả các số nguyên x bằng 0
tìm x
a) ( x-55). 17=0
b) 25.(x-75)=25
c) (x-5)(x-7)=0
d)(x-11)(x+17)=0
a) ( x- 55 ) . 17 = 0
x - 55 = 0 : 17
x - 55 = 0
x = 0 + 55
x = 55
Vậy x = 55
b) 25 . ( x - 75 ) = 25
x - 75 = 25 : 25
x - 75 = 1
x = 1 + 75
x = 76
Vậy x = 76
c) ( x - 5 ) ( x - 7 ) = 0
=> x - 5 = 0 hoặc x - 7 = 0
x = 0 + 5 x = 0 + 7
x = 5 x = 7
Vậy \(x\in\left\{5;7\right\}\)
d) ( x -11 ) ( x + 17 ) = 0
=> x - 11 = 0 hoặc x + 17 = 0
x = 0 + 11 x = 0 - 17
x = 11 x = -17
Vậy \(x\in\left\{11;-17\right\}\)
a,( x-55).17=0
x-55=0:17
x-55=0
x=0+55
x=55
b,25.(x-75)=25
x-75=25:25
x-75=1
x=75+1
x=76
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13 Tìm x
a) 11 . x = 55
b) 5 . 12 x = 144
c) - 3 x = 12
d) 0 . x = 9
e ) 2 x = -6
g) ( x + 5 ) : x = x -4
h ) ( x - 1 ). ( x -3 ) = 0
i) (3 - x ) -3 = 0
n ) x ( + 1 ) = 0
Bạn đối chiếu các bài vs nhau nha. Chúc bạn học tốt
Tim x thuộc Z :
A )(x +5)(3y - 12)>0
B)(2x +1)(3y -2)=-55
C)(x -7)(xy +1)=9
D) x(x -5)=0
E)|2x -5|=13
F) ( x -2)(5-x)=0
G)|7x +3|=66
1. Tìm x€ Z, biết
a/ |7x+3|=66
b/ |5x-2| <=0
c/ (x-7)×(x+3)<0
2. Tìm x, y€ Z, biết
a/(x-3)×(2y-2)=7
b/(2x+1)×3(3y-2)=-55
a) \(\left|7x+3\right|=66\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}7x+3=66\\7x+3=-66\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}7x=63\\7x=-69\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=9\left(N\right)\\x=-\frac{69}{7}\left(L\right)\end{cases}}\)
Vậy...
b) \(\left|5x-2\right|\le0\)
mà \(\left|5x-2\right|\ge0\)
\(\Rightarrow\)\(\left|5x-2\right|=0\)
\(\Leftrightarrow\)\(5x-2=0\)
\(\Leftrightarrow\)\(x=\frac{2}{5}\) (loại)
Vậy...
Tìm x: (6x+11).(5x-12)-42x+66=0
\(\Leftrightarrow30x^2-72x+55x-132-42x+66=0\\ \Leftrightarrow30x^2-59x-66=0\\ \Delta=3481-4\cdot\left(-66\right)\cdot30=11401\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{59-\sqrt{11401}}{60}\\x=\dfrac{59+\sqrt{11401}}{60}\end{matrix}\right.\)