tìm x: -7/ x+3 /=49
Bài 3. Tìm x. x/36 = 3/4 ; x/7 = 56/49 ; 15/27 = 5/x ; 3/7 = 42/x
Tìm x:49/x-3=7/-2
`#3107.101107`
`43/(x - 3) = 7/(-2)`
`=> 7(x - 3) = 43 * (-2)`
`=> 7(x - 3) = -86`
`=> x - 3 = -86/7`
`=> x = -86/7 + 3`
`=> x = -65/7`
Vậy, `x = -65/7.`
Tìm x:
a, 49 : x = 7 b, x : 3= 312
a, 49 : x = 7 b, x : 3 = 312
x = 49 : 7 (0,5đ) x = 312 x 3 (0,5đ)
x = 7 (0,25đ) x = 936 (0,25đ)
Tìm x:
25x^2 - 49 = (5x - 7)(x + 3)
\(\Leftrightarrow\left(5x-7\right)\left(5x+7-x-3\right)=0\)
\(\Leftrightarrow\left(5x-7\right)\left(4x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{5}\\x=-1\end{matrix}\right.\)
\(25x^2-49=\left(5x-7\right)\left(x+3\right)\)
\(\Rightarrow\left(5x\right)^2-7^2=\left(5x-7\right)\left(x+3\right)\)
\(\Rightarrow\left(5x-7\right)\left(5x+7\right)-\left(5x-7\right)\left(x+3\right)=0\)
\(\Rightarrow\left(5x-7\right)\left(5x+7-x-3\right)=0\)
\(\Rightarrow\left(5x-7\right)\left(4x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-7=0\\4x+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}5x=7\\4x=-4\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{5}\\x=-1\end{matrix}\right.\)
vậy \(x\in\left\{\dfrac{7}{5};-1\right\}\)
tích cho mk nhé
x/7+9/49=3/14 tìm x
\(\frac{x}{7}+\frac{9}{49}=\frac{3}{14}\)
\(\Rightarrow\frac{x}{7}=\frac{3}{14}-\frac{9}{49}=\frac{3}{98}\)
\(\Rightarrow x=3.7:98=\frac{3}{14}\)
Vậy \(x=\frac{3}{14}\)
Dạng 2 : Tìm x Bài 1: Tìm x biết :
a) ( x – 16 ) – 74 = 0 b) (3 x – 5) .7 mũ 3 = 7 mũ 4
c) 560 – 13x = 365 d) 275 – 7( x + 1) = 100
e) 3 x 7 14 3.2 mũ 3 f) 7x – 49 = 105
g) 5x – 16 = 14 h) 3x – 138 = 23 . 2 2
Tìm x thuộc z biết : (x^3-7>x^3-49)>0
Tìm các số nguyên x biết
a)4x-15=-75-x
b)72-3x=5x+8
c)3/x-7/=21
d)-7/x+3/=-49
a, 4x -15=-75-x b,72-3x= 5x+8
4x+x=-75+15 -3x-5x=8-72
5x=-60 -8x=-64
x=-60:5 8x=64
x=-14 x=64:8
x=8
c,3Ix-7I=21 d,-7Ix+3I=-49
Ix-7I=21:3 Ix+3I=-49:-7
Ix-7I=7 Ix+3I=7
x-7=7 hoặc x-7=-7 x+3=7 hoặc x+3=-7
x=14 hoặc x=0 x=4 hoặc x=-10
a) \(4x-15=-75-x\)
\(5x=-60\)
\(x=-12\)
b) \(72-3x=5x+8\)
\(-8x=-64\)
\(x=8\)
c) \(3\left|x-7\right|=21\)
Khi \(x\ge7\) , ta có
\(3\left(x-7\right)=21\)
\(x-7=7\)
\(x=14\)
Khi \(x< 7\), ta có
\(-3\left(x-7\right)=21\)
\(x-7=-7\)
\(x=0\)
d) \(-7\left|x+3\right|=-49\)
Khi \(x\ge-3\), ta có
\(-7\left(x+3\right)=-49\)
\(x+3=7\)
\(x=4\)
Khi \(x< 3\), ta có
\(7\left(x+3\right)=-49\)
\(x+3=-7\)
\(x=-10\)
bài 7 tìm x
3,(x+1)=(x+1) 4,x(2x-3)-2(3-2x)=0
6,
3: =>x(x+1)=0
=>x=0 hoặc x=-1
4: =>(2x-3)(x+2)=0
=>x=3/2 hoặc x=-2
6: =>6x=7 hoặc 6x=-7
=>x=7/6 hoặc x==7/6