Tìm x:
\(\left(x-3,5\right):3\frac{1}{2}-2,5=-1\frac{3}{4}\)
Những câu hỏi liên quan
Tìm x biết
a)\(\frac{x+4}{2009}+\frac{x+3}{2010}=\frac{x+2}{2011}+\frac{x+1}{2012}\)
b)\(\left(\frac{1}{4}x-1\right)\)+\(\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+5\right)=3,5\)
Anh chỉ giải câu a thôi, câu b anh thấy nó bình thường mà.
Cộng vào mỗi phân số thêm 1 đơn vị được:
\(\frac{x+2013}{2009}+\frac{x+2013}{2010}=\frac{x+2013}{2011}+\frac{x+2013}{2012}\).
Tới đây tự làm tiếp nhá.
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1.Tìm x biếta) left(frac{2}{5}-xright):1frac{1}{3}+frac{1}{2}-4b) left(-3+frac{3}{x}-frac{1}{3}right):left(1+frac{2}{5}+frac{2}{3}right)-frac{5}{4}c) frac{-3x}{4}.left(frac{1}{x}+frac{2}{7}right)0d) 3-frac{1-frac{1}{2}}{1+frac{1}{x}}2frac{2}{3}e)left(2x+frac{1}{3}right)^2frac{9}{16}f) 4^x+4^{x+3}4160g) left(x-2,5right):1frac{1}{2}x:2h) left(frac{1}{3}+xright):left(x+frac{3}{4}right)frac{7}{9}i) 0,81:frac{x}{2}frac{16}{x^4}:left(-0,9right)2. Tìm x, biết:a)left(152frac{2}{4}-148frac{3}{8}right):0,...
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1.Tìm x biết
a) \(\left(\frac{2}{5}-x\right)\):\(1\frac{1}{3}+\frac{1}{2}=-4\)
b) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
c) \(\frac{-3x}{4}.\left(\frac{1}{x}+\frac{2}{7}\right)=0\)
d) 3-\(\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
e)\(\left(2x+\frac{1}{3}\right)^2=\frac{9}{16}\)
f) \(4^x+4^{x+3}=4160\)
g) \(\left(x-2,5\right):1\frac{1}{2}=x:2\)
h) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
i) 0,81:\(\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
2. Tìm x, biết:
a)\(\left(152\frac{2}{4}-148\frac{3}{8}\right):0,2=x:0,3\)
b) \(\left[\left(6\frac{3}{5}-3\frac{3}{14}\right):2,5\right]:\left(21-1,25\right)=x:5\frac{5}{6}\)
a ) \(\left(\frac{2}{5}-x\right):1\frac{1}{3}+\frac{1}{2}=-4\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}+\frac{1}{2}=-4\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}=-4-\frac{1}{2}\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}=-\frac{9}{2}\)
\(\frac{2}{5}-x=-\frac{9}{2}.\frac{4}{3}\)
\(\frac{2}{5}-x=-3\)
\(x=\frac{2}{5}-\left(-3\right)\)
\(x=\frac{2}{5}+3\)
\(x=\frac{3}{5}-\frac{15}{5}\)
\(x=-\frac{12}{5}\)
Vay \(x=-\frac{12}{5}\)
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b ) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(\frac{15}{15}+\frac{6}{15}+\frac{10}{15}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(\frac{15+6+10}{15}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\frac{31}{15}=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right)=-\frac{5}{4}.\frac{31}{15}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right)=-\frac{1}{4}.\frac{31}{3}\)
\(-3+\frac{3}{x}-\frac{1}{3}=-\frac{31}{12}\)
\(-3+\frac{3}{x}=-\frac{31}{12}+\frac{1}{2}\)
\(-3+\frac{3}{x}=-\frac{31}{12}+\frac{6}{12}\)
\(-3+\frac{3}{x}=\frac{-25}{12}\)
\(\frac{3}{x}=\frac{-25}{12}+3\)
\(\frac{3}{x}=\frac{-25}{12}+\frac{36}{12}\)
\(\frac{3}{x}=\frac{5}{6}\)
\(\frac{18}{6x}=\frac{5x}{6x}\)
Đèn dây , bạn tự làm tiếp nhé , de rồi chứ
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Tìm x trong biểu thức sau
\(\left(3\frac{3}{4}:\frac{1}{4}-2\frac{2}{5}\cdot1\frac{1}{4}\right)-\left(3\frac{1}{2}:2,5-\frac{1}{5}\right)-\frac{1}{5}\cdot x=\frac{51}{5}\)
(15/4.4-12/5.5/4)-(7/2:5/2-1/5)-1/5.x=51/5
(15-3)-(7/5-1/5)-1/5.x=51/5
12-6/5-1/5.x=51/5
54/5-1/5.x=51/5
1/5x=54/5-51/5
1/5x=3/5
x=3
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I,Rút gọn biểu thức chứa dấu GTTĐ
1.A= |x-3,5|+|4,1-x|
2.B= |-x+3,5|+|x-4,1|
II,Rút gon BT khi \(\frac{-3}{5}< x< \frac{1}{7}\)
\(1,A=\left|x-\frac{1}{7}\right|-\left|x+\frac{3}{5}\right|+\frac{4}{5}\)
\(2,B=\left|-x+\frac{1}{7}\right|+\left|-x-\frac{3}{5}\right|-\frac{2}{6}\)
Tìm x biết :
a, ( 4x - 9 ) . ( 2,5 + \(\frac{-7}{3}\). x ) = 0
b, \(\frac{1}{x\cdot\left(x+1\right)}\cdot\frac{1}{\left(x+1\right)\cdot\left(x+2\right)}\cdot\frac{1}{\left(x+2\right)\cdot\left(x+3\right)}-\frac{1}{x}=\frac{1}{2015}\)
a)
( 4x - 9 ) ( 2,5 + (-7/3) . x ) = 0
\(\Rightarrow\orbr{\begin{cases}4x-9=0\\2,5+\frac{-7}{3}x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{4}\\x=\frac{15}{14}\end{cases}}\)
P/s: đợi xíu làm câu b
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b) \(\frac{1}{x\left(x+1\right)}\cdot\frac{1}{\left(x+1\right)\left(x+2\right)}\cdot\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2015}\)
\(\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}-\frac{1}{x}=\frac{1}{2015}\)
\(\frac{-1}{x+3}=\frac{1}{2015}\)
\(\Leftrightarrow x+3=-2015\)
\(\Leftrightarrow x=-2018\)
Vậy,.........
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A/ Ta có số nào nhân với 0 cx = 0
Vậy từ đó suy ra 2 trường hợp
TH1\(4x-9=0\)
\(=>x=\frac{9}{4}\)
TH2 \(2,5+-\frac{7}{3}x=0\)
\(=>x=\frac{15}{14}\)
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tìm x biết :
a) \(\frac{1}{4}+\frac{1}{3}:2x=-5\)
b) \(\left(3x+\frac{1}{4}\right).\left(x+\frac{1}{2}\right)=0\)
c) \(\left|2x-3,5\right|=28\)
a.
\(\frac{1}{4}+\frac{1}{3}\div2x=-5\)
\(\frac{1}{3}\div2x=-5-\frac{1}{4}\)
\(\frac{1}{3}\div2x=-\frac{20}{4}-\frac{1}{4}\)
\(\frac{1}{3}\div2x=-\frac{21}{4}\)
\(2x=\frac{1}{3}\div\left(-\frac{21}{4}\right)\)
\(2x=\frac{1}{3}\times\left(-\frac{4}{21}\right)\)
\(2x=-\frac{4}{63}\)
\(x=-\frac{4}{63}\div2\)
\(x=-\frac{4}{63}\times\frac{1}{2}\)
\(x=-\frac{2}{63}\)
b.
\( \left(3x+\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)
TH1:
\(3x+\frac{1}{4}=0\)
\(3x=-\frac{1}{4}\)
\(x=-\frac{1}{4}\div3\)
\(x=-\frac{1}{4}\times\frac{1}{3}\)
\(x=-\frac{1}{12}\)
TH2:
\(x+\frac{1}{2}=0\)
\(x=-\frac{1}{2}\)
Vậy \(x=-\frac{1}{12}\) hoặc \(x=-\frac{1}{2}\)
c.
\(\left|2x-3,5\right|=28\)
\(2x-3,5=\pm28\)
TH1:
\(2x-3,5=28\)
\(2x=28+3,5\)
\(2x=31,5\)
\(x=31,5\div2\)
\(x=15,75\)
TH2:
\(2x-3,5=-28\)
\(2x=-28+3,5\)
\(2x=-24,5\)
\(x=-24,5\div2\)
\(x=-12,25\)
Vậy \(x=-12,25\) hoặc \(x=-15,75\)
Chúc bạn học tốt
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tìm x
1, \(0,4\cdot x-\frac{1}{5}x=\frac{3}{4}\)
2, \(x\div1\frac{2}{7}=-3,5\)\
3, \(\left(\frac{2x}{5}-2\right)\div\left(-5\right)=\frac{3}{7}\)
4, x+ 20% x = -4,8
5, \(x-15\%x=-2\frac{11}{20}\)
6, \(\left(x\cdot25\%-\frac{2}{3}\right)\div2\frac{1}{3}=1\frac{5}{8}\)
1. 0,4x - 1/5x = 3/4
=> 1/5x = 3/4
=> x = 3/4 : 1/5
=> x = 15/4
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2.
x : 1 2/7 = -3,5
=> x = -3,5 . 9/7
=> x = -9/2
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3. ( 2x/5 - 2 ) : -5 = 3/7
=> 2x/5 - 2 = 3/7 . (-5)
=> 2x/5 - 2 = -15/7
=> 2x/5 = -15/7 + 2 = -1/7
=> 2x = -1/7 . 5 = -5/7
=> x = -5/7 : 2
=> x = -5/14
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Xem thêm câu trả lời
Tìm x biết : 1) frac{x+1}{2}+frac{x+1}{3}+frac{x+1}{4}frac{x+1}{5}+frac{x+1}{6}2) left(x-2,5right):1frac{1}{2}x:23) left(frac{1}{3}+xright):left(x+frac{3}{4}right)frac{7}{9}4) 0,81:frac{x}{2}frac{16}{x^4}:left(-0,9right)giúp mình nhé
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Tìm x biết :
1) \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2) \(\left(x-2,5\right):1\frac{1}{2}=x:2\)
3) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
4) \(0,81:\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
giúp mình nhé 
1)\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
\(\Leftrightarrow\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}-\frac{x+1}{5}-\frac{x+1}{6}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)=0\)
\(\Leftrightarrow\left(x+1\right)=0\).Do \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\ne0\)
\(\Leftrightarrow x=-1\)
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\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\\ \Leftrightarrow\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}-\frac{x+1}{5}-\frac{x+1}{6}=0\\ \Leftrightarrow\left(x+1\right)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)=0\)
Gọi \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)\)là A
Vì A ≠0
⇒\(x+1=0\Rightarrow x=-1\)
Vậy \(x=-1\)
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a,\(x:4\frac{1}{3}=2,5\)
b,\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
c,\(\left(\frac{3}{7}x+1\right):\left(-4\right)=-\frac{1}{28}\)
d,\(\frac{2}{3}+\frac{1}{3}.\left(2x-1\right)=-5\)
help me
please !!!