Tính hợp lý:
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}16^9}\)
tính hợp lí
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.4^2.2^{32}}{2^{35}\left(11-2\right)}\)
\(=\frac{3^2.4^2.2^{32}}{2^{35}.3^2}\)
\(=\frac{4^2}{2^3}\)
\(=\frac{2^4}{2^3}\)
\(=2\)
Hk tốt
\(\text{Thực hiện các phép tính sau một cách hợp lý:}\)
\(a\)) \(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(b\)) \(1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
\(c\)) \(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(d\)) \(1152-\left(374+1152\right)+\left(-65+374\right)\)
\(e\)) \(13-12+11+10-9+8-7-6+5-4+3+2-1\)
Tính bằng cách hợp lí
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)
Tính hợp lí phép tính sau
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{35}.2}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{35}.2}{2^{35}.9}\)
\(=2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{35}.2}\)
= \(\frac{3^2.2^4.2^{32}}{2^{35}.\left(11-2\right)}\)
= \(\frac{3^2.2^{36}}{2^{35}.9}\)
= \(\frac{9.2^{35}.2}{2^{35}.9}\)
= \(2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
=\(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
=\(\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)
=\(\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
=\(\frac{3^2.2^{36}}{2^{35}.9}\)
=\(\frac{3^22^{36}}{2^{35}.3^2}\)
=2
Chúc bn học tốt
tính
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{9.\left(2^2\right)^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{9.2^4.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{9.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{35}.2}{2^{35}.9}\)
\(=2\)
Tính
a, B = \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16.2}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{34}}{11.2^{35}-2^{36}}=\frac{3.2^{34}}{2^{34}\left(11.2-2^2\right)}\)
\(=\frac{3}{11.2-2^2}=\frac{3}{11.2-4}=\frac{3}{22-4}=\frac{3}{18}=\frac{1}{6}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
= 3^2 . 2^4 . 2^32 / 11.2^13 .2^22 - 2^36
=3^2 . 2^36 / 11.2^35 - 2^36
=3^2 . 2^36 / 2^35 . ( 11+2)
= 9 . 2^36 / 2^35 . 13
= 9 . 2 / 13 = 18/13
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)