5x(x-2)-10y(x-2)
a, x^2 - 4xy +y^2 + 5x - 10y
b, x ( 3x - 1 ) - 12 + x = 0
x^2-5x-4y^2+10y
Ta có: \(x^2-5x-4y^2+10y\)
\(=\left(x^2-4y^2\right)-\left(5x-10y\right)\)
\(=\left[x^2-\left(2y\right)^2\right]-5\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x+2y\right)-5\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x+2y-5\right)\)
Giải Giúp Mik nhék
x^2-7xy+10y^2
x^2-5x-10
5x^2+6xy+y^2
a)x^2-7xy+10y^2
=(2y-x)(5y-x)
b)x^2-5x-10
c)5x^2+6xy+y^2
=(y+x)(y+5x)
Câu 1 :2/5xy(x^2y-5x+10y)
Câu 2:3x(x^2+x-1)
Câu 1
2/5.xy(x2y-5x+10y)
=2/5.xy.x2y-2/5.xy.5x+2/5.xy.10y
=2/5.x3y2-2x2y+4xy2
Câu 2
3x(x2+x-1)
=3x.x2+3x.x-3x.1
=3x3+3x2-3x
x^2-5x+2xy-10y
\(x^2-5x+2xy-10y\)
\(=x^2+2xy+y^2-y^2-5x-10y\)
\(=\left(x+y\right)^2-y^2-5\left(x+2y\right)\)
\(=x\left(x+2y\right)-5\left(x+2y\right)\)
\(=\left(x-5\right)\left(x+2y\right)\)
xong!
CMR:
a,\(x^2+5y^2+2x-4xy-10y+10>0\forall x,y\)
b,\(5x^2+10y^2-6xy-4x-2y+3>0\forall x,y\)
Phân tích đa thức thành nhân tử a) x^2 -5x+6 b) 3x^2+9x -30 c)3x^2 -5x-2 d) x^3-7x-6 e) x^4+2x^2+6x-9 f) x^2-7xy+10y^2
Tìm x và y: 5x^2+10y^2-6xy-4x-2y+3=0
a, x2-5xy+2x-10y
b, x2-5x+4
a) \(x^2-5xy+2x-10y\)
\(=\left(x^2-5xy\right)+\left(2x-10y\right)\)
\(=x.\left(x-5y\right)+2.\left(x-5y\right)\)
\(=\left(x-5y\right).\left(x+2\right)\)
b) \(x^2-5x+4\)
\(=x^2-4x-x+4\)
\(=\left(x^2-4x\right)-\left(x-4\right)\)
\(=x.\left(x-4\right)-\left(x-4\right)\)
\(=\left(x-4\right).\left(x-1\right)\)
Chúc bạn học tốt!