thực hiện phép tính:9.5^20.27^9-3.9^15.25^9/7.3^29.125^6-3.3^9.15^19
9.5^20.27^9-3.9^15.25^9/7.3^29.125^6-3.3^9.15^19
1 tính :
a,2^3.3^3.5^3.7.8/3.2^4.5^3.14
b,9.5^20.27^9-3.9^15.25^9/7.3^29.125^6-3.3^9.15^19
mk cần gấp nhé ngay trong tối nay mong nhận sự giúp đỡ của các bn càng sớm càng tốt
a) 2^3.3^3.5^3.7.8/ 3.2^4.5^3.14= 2^6 . 3^3 . 5^3 . 7/ 3. 2^5. 7. 5^3
rút gọn sau đó ra kết quả: 2. 3^2=18
b) 9. 520. 279- 3.915.259/ 7.329. 1256- 3.39. 1519= 32. 520- 3.330.518/7.329.518- 310.319.519
=32. 520-331.518/ 7.329.518 - 329.519= 32. 518 ( 25-329) / 329. 518.2
tiếp theo em tu giai nhe
`Answer:`
a. \(\frac{2^3.3^3.5^3.7.8}{3.2^4.5^3.14}\)
\(=\frac{3^2.7.2.2.2}{2.7.2}\)
\(=\frac{3^2.2}{1}\)
\(=18\)
b. \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
Ta xét tử số: \(9.5^{20}.27^9-3.9^{15}.25^9\)
\(=3^2.5^{20}.\left(3^3\right)^9-3.\left(3^2\right)^{15}.\left(5^2\right)^9\)
\(=3^2.5^{20}.3^{27}-3.3^{30}.5^{18}\)
\(=5^{20}.3^{29}-3^{31}.5^{18}\)
\(=3^{29}.5^{18}.\left(5^2-3^2\right)\)
\(=3^{29}.5^{18}.16\)
Ta xét mẫu số: \(7.3^{29}.125^6-3.3^9.15^{19}\)
\(=7.3^{29}.\left(5^3\right)^6-3^{10}.\left(3.5\right)^{19}\)
\(=7.3^{29}.5^{18}-3^{10}.3^{19}.5^{19}\)
\(=7.3^{29}.5^{18}-3^{29}.5^{19}\)
\(=3^{29}.5^{18}.\left(7-5\right)\)
\(=3^{29}.5^{18}.2\)
`=>` Phân số trở thành: \(\frac{3^{29}.5^{18}.16}{3^{29}.5^{18}.2}\)\(=\frac{16}{2}=8\)
Thực hiện phép tính:
9.5^20.27^9 - 3.9^15.25^9
7.3^19.125^6 - 3.3^9.15^19
a)A= -1-2-3-...........-2012
b)C=10101(5/111111+5/222222-4/3x7x11x13x37)
c)D=9.5^20.27^9-3.9^15.25^9/7x3^29.125^6-3.3^9.15^19
d)B=1/6+1/12+1/20+1/30+1/42+...+1/90
Giúp tớ với ^^
\(N=\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
Hãy tình giá trị của N
32.520.(33)9-3.(32)15.(52)9
7.329.(53)
Rút gọn các biểu thức sau:
E = \(\dfrac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\dfrac{3^2\cdot5^{20}\cdot3^{27}-3\cdot3^{30}\cdot5^{18}}{7\cdot3^{29}\cdot5^{13}-3^{29}\cdot5^{19}}=\dfrac{3^{29}\cdot5^{20}-5^{18}\cdot3^{31}}{3^{29}\cdot5^{13}\cdot7-3^{29}\cdot5^{19}}\)
\(=\dfrac{3^{29}\cdot5^{18}\left(5^2-3^2\right)}{3^{29}\cdot5^{13}\left(7-5^6\right)}=5^5\cdot\dfrac{4^2}{7-5^6}\)
\(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
Mình biết cách làm rồi nha, ai làm đúng và nhanh nhất thì mình tick cho!!
\(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{3^2.5^{20}.3^{27}-3.3^{30}.5^{18}}{7.3^{29}.5^{18}-3^{10}.3^{19}.5^{19}}\)
\(=\frac{3^{29}.5^{18}.5^2-3^2.3^{29}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{18}.5}\)
\(=\frac{3^{29}.5^{18}.\left(5^2-3^2\right)}{3^{29}.5^{18}.\left(7-5\right)}\)
\(=\frac{25-9}{2}\)
\(=\frac{16}{2}=8\)
N=\(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
Mình cần cách làm nha đáp án bằng 8 rồi nên cần cách làm thôi.Gấp nha.Cảm ơn nhìu
Bài giải
\(N=\frac{9\cdot5^{20}\cdot27^9-3\cdot9^{15}\cdot25^9}{7\cdot3^{29}\cdot125^6-3\cdot3^9\cdot15^{19}}=\frac{3^2\cdot5^{20}\cdot\left(3^3\right)^9-3\cdot\left(3^2\right)^{15}\cdot\left(5^2\right)^9}{7\cdot3^{29}\cdot\left(5^3\right)^6-3\cdot3^9\cdot\left(3\cdot5\right)^{19}}=\frac{3^2\cdot5^{20}\cdot3^{27}-3\cdot3^{30}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{10}\cdot3^{19}\cdot5^{19}}\)
\(=\frac{3^{29}\cdot5^{20}-3^{31}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{29}\cdot5^{19}}=\frac{3^{29}\cdot5^{18}\left(5^2-3^2\right)}{3^{29}\cdot5^{18}\left(7-5\right)}=\frac{25-9}{7-5}=\frac{16}{2}=8\)
1 rút gọn
\(\dfrac{9.5^{20}.27^9-3.9^{15}:25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{-4}\right)^{^{20}}\)
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
1. \(\dfrac{9.5^{20}.27^9-3.9^{15}:25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\dfrac{3^2.5^{20}.3^{27}-3.3^{30}.5^{18}}{7.3^{29}.5^{18}-3^{10}.3^{19}.5^{19}}\)
\(=\dfrac{3^{29}.5^{20}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}\)
\(=\dfrac{3^{28}.5^{18}.\left(5^2-3^2\right)}{3^{29}.5^{18}.\left(7-5\right)}\)
\(=\dfrac{5^2-3^2}{7-5}=\dfrac{16}{2}=8\)
2.\(\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{-4}\right)^{20}=\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{4}\right)^{20}\)
\(=\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{2}^2\right)^{20}=\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{2}\right)^{40}\)
\(=\left(\dfrac{1}{2}\right)^{55}\)
3.\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=\dfrac{1-3}{1+5}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
Chúc học tốt!!