Bài 1 : tính hợp lí nếu có
a) 11+6+(-11)+(-3)
b)25.7.(-5).(-4).2
c)3.25-7.(-25)
Thực hiện phép tính (tính hợp lí nếu có thể):
a) \(\dfrac{5}{3}.\dfrac{7}{25}+\dfrac{5}{3}.\dfrac{21}{25}-\dfrac{5}{3}.\dfrac{7}{25}\) b) 250% + \(19\dfrac{3}{11}.\dfrac{7}{26}-6\dfrac{3}{11}.\dfrac{7}{26}\)
\(\dfrac{5}{3}\cdot\dfrac{7}{25}+\dfrac{5}{3}\cdot\dfrac{21}{25}-\dfrac{5}{3}\cdot\dfrac{7}{25}\)
\(=\dfrac{5}{3}\cdot\left(\dfrac{7.}{25}+\dfrac{21}{25}-\dfrac{7}{25}\right)\)
\(=\dfrac{5}{3}\cdot\dfrac{21}{25}=\dfrac{7}{5}\)
b) \(250\%+19\dfrac{3}{11}\cdot\dfrac{7}{26}-6\dfrac{3}{11}\cdot\dfrac{7}{26}\)
\(=\dfrac{5}{2}+\dfrac{212}{11}\cdot\dfrac{7}{26}-\dfrac{69}{11}\cdot\dfrac{7}{26}\)
\(=\dfrac{7}{26}\cdot\left(\dfrac{212}{11}-\dfrac{69}{11}\right)+\dfrac{5}{2}\)
\(=\dfrac{7}{26}\cdot13+\dfrac{5}{2}\)
\(=\dfrac{7}{2}+\dfrac{5}{2}\)
\(=\dfrac{12}{2}=6\)
1)
Tính hợp lí nếu có thể
a 11.(7-25)+7.(25-11)
b -5/7+-3/-5+5/7
c -2/3+10/14.-7/15
đ -2/5-3/7+10/7-(-7)/5
2)
Tìm x biết
a |2.x-6|=2009+(-2009)
b -3/4-x=1/2.2/4.4/5
1 Tính 1 cách hợp lí (nếu có thể)
D=-25.(35+147)+35.(25.7)
E=125.9.(-4).(-8).25.7
G=(-3)2+(-5)3 : giá trị tuyệt đối của -5
D=-25.(35+147)+35.(25+147)
=-25.35+(-25).147+35.25+35.147
=35.[(-25)+25]+147.[(-25)+35]
=35.0+147.10
=0+1470
=1470
E=125.9.(-4).(-8).25.7
=[125.(-8)].[(-4).25].9.7
=(-1000).(-100).63
=6 300 000
G=(-3)2+(-5)3:|-5|
=9+(-125):5
=9+(-25)
=-16
toán lớp 6 ms cs giá trị tuyệt đối chứ
1 Tính 1 cách hợp lí (nếu có thể)
D=-25.(35+147)+35.(25.7)
E=125.9.(-4).(-8).25.7
G=(-3)2+(-5)3 : giá trị tuyệt đối của -5
D=1575;E=6300000;G=9
tck minh nha moi nguoi
1 Tính 1 cách hợp lí (nếu có thể)
D=-25.(35+147)+35.(25.7)
E=125.9.(-4).(-8).25.7
G=(-3)2+(-5)3 : giá trị tuyệt đối của -5
Bài 1: a/ -2/5+1/3
b/ 3/5:12/25
c/ 3/5.-11/7
d/ (1/3+5/4): 38/6
e/ -5/6+1/6
f/ 1/3-5/4.4/15
g/ 4.(-5)^2+(-2)^3.25
h/ -2/7+1/5:7/15
bít ồi mà tớ gửi cho thủy làm thủy bị mất đề
Tính hợp lí
a, -2/5×4/7+-3/5×2/7+-3/5
b,5/9×14/17+1/17×5/9+2/9+5/12
c,-4/25÷11/79+15/11÷25/79
d, (2/101÷5/9+-3/7)×(6/5÷1/3)
a)\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{3}{7}.\dfrac{-2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\dfrac{-3}{5}\)
=\(\dfrac{-2}{5}.1+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{5}{5}\) = -1
\(\dfrac{5}{9}.\dfrac{14}{17}+\dfrac{1}{17}.\dfrac{5}{9}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\left(\dfrac{14}{17}+\dfrac{1}{17}\right)+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\dfrac{15}{17}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{25}{51}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{691}{612}\)
\(-\dfrac{4}{25}:\dfrac{11}{79}+\dfrac{15}{11}:\dfrac{25}{79}\)
=\(-\dfrac{4}{25}.\dfrac{79}{11}+\dfrac{15}{11}.\dfrac{79}{25}\)
=\(-\dfrac{4}{25}.\dfrac{79}{11}+\dfrac{15}{25}.\dfrac{79}{11}\)
=\(\left(-\dfrac{4}{25}+\dfrac{15}{25}\right).\dfrac{79}{11}\)
=\(\dfrac{11}{25}.\dfrac{79}{11}\)
=\(\dfrac{79}{25}\)
Tính giá trị biểu thức sau (hợp lí nếu có thể)
a) \(\dfrac{\left(-3\right)^7.2^8}{6^7}\) b) \(\dfrac{5^3.3^5}{5^3.0,5+125.2,5}\)
c) \(\dfrac{5.7^4+7^3.25}{7^5.125-7^3.50}\)
-3^7.2^8/2^.3^7
=-3.2
=-6
5^3.3^5/5^3(0,5+2,5)
=5^3.3^5/5^3.3\
3^4
=81
5.7^4+7^3.25/7^5.125-7^3.50
=5.7^3(7+5
5.7^4+7^3.25/7^5.125-7^3.50
=5.7^4+7^3.5^2/7^5.5^3-7^3.11.5
=5.7^3(1.7+1.5)/7^3.5(7^2.25-11)
12/1250
Thực hiện các phép tính sau ( tính hợp lí nếu có thể):
a,2/9-(1/20+2/9) b,-3/14+2/13+(-25)/14+(-15)/13
c,(-3/11)+11/8-3/8+(-8/11) d, 3/8+(-1)/4-(7/12-1/6)
e, (1/3+12/67+13/41)-(79/67-28/41)
a) 2/9 - (1/20 + 2/9)
= 2/9 - 1/20 - 2/9
= (2/9 - 2/9) - 1/20
= 0 - 1/20
= -1/20
b) -3/14 + 2/13 + (-25/14) + (-15/13)
= (-3/14 - 25/14) + (2/13 - 15/13)
= -2 - 1
= -3
c) -3/11 + 11/8 - 3/8 + (-8/11)
= (-3/11 - 8/11) + (11/8 - 3/8)
= -1 + 1
= 0
d) 3/8 + (-1/4) - (7/12 - 1/6)
= 1/8 - 5/12
= -7/24
e) (1/3 + 12/67 + 13/41) - (79/67 - 28/41)
= 1/3 + 12/67 + 13/41 - 79/67 + 28/41
= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)
= 1/3 - 1 + 1
= 1/3