\(\frac{5}{3}\)=\(\frac{10}{?}\)=\(\frac{?}{9}\)=\(\frac{20}{?}\)
Những câu hỏi liên quan
1/ \(-\frac{4}{5}:\left(\frac{20}{9}-\frac{8}{15}\right)+\frac{3}{5}\left|\frac{10}{-9}\right|-\frac{1}{2}\left(\frac{4}{3}-\frac{2}{5}\right)\)
\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=?\)
\(=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{2}{10}+\frac{7}{20}=\frac{4}{20}+\frac{7}{20}=\frac{11}{20}\)
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\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{2}{10}+\frac{7}{20}=\frac{4+7}{20}=\frac{11}{20}\)
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\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{1}{5}+\frac{7}{20}=\frac{11}{20}\)
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Xem thêm câu trả lời
\(\frac{3}{5}=\frac{ }{10}=\frac{9}{ }=\frac{ }{20}\)
ARE YOU UNDERSTAND?
YES, I UNDERSTAND!
3/5 = 6/10 = 9/15 = 12/20
k nha
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\(\frac{3}{5}\) \(=\) \(\frac{6}{10}\) \(=\) \(\frac{9}{15}\) \(=\) \(\frac{12}{20}\)
I can understand!
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\(\frac{3}{5}=\frac{6}{10}=\frac{9}{15}=\frac{12}{20}\)
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\(\frac{2}{3}+\frac{6}{5}+\frac{9}{10}+\frac{14}{15}+\frac{20}{21}+\frac{27}{28}+\frac{35}{36}+\frac{44}{45}+\frac{44}{55}\)
Chứng minh rằng:
1)B=\(\frac{4}{3}+\frac{10}{9}+\frac{28}{27}+...+\frac{3^{98}+1}{3^{98}}< 100\)
2)C=\(\frac{5}{5.8.11}+\frac{5}{8.11.14}+...+\frac{5}{302.305.308}\)<\(\frac{1}{48}\)
3)D=\(\frac{11}{9}+\frac{18}{16}+\frac{27}{25}+...+\frac{1766}{1764}\)
\(40\frac{20}{43}< D< 40\frac{20}{21}\)
tính hợp lí ( nếu có thể )
a) \(\frac{-5}{2}+\frac{1}{7}+\frac{6}{7}+\frac{1}{2}+\frac{3}{4}\)
b) \(\frac{4}{10}+\frac{-2}{9}+\frac{-3}{-5}+\frac{21}{-27}+\frac{-10}{20}\)
b) \(\frac{4}{10}+\frac{-2}{9}+\frac{-3}{-5}+\frac{21}{-27}+\frac{-10}{20}\)
\(=\frac{2}{5}-\frac{2}{9}+\frac{3}{5}-\frac{7}{9}-\frac{1}{2}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)-\left(\frac{2}{9}+\frac{7}{9}\right)-\frac{1}{2}\)
\(=1-1-\frac{1}{2}=-\frac{1}{2}\)
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a) \(-\frac{5}{2}+\frac{1}{7}+\frac{6}{7}+\frac{1}{2}+\frac{3}{4}\)
\(=\left(\frac{-5}{2}+\frac{1}{2}\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+\frac{3}{4}\)
\(=-2+1+\frac{3}{4}\)
\(=-1+\frac{3}{4}\)
\(=-\frac{1}{4}\)
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\(\frac{2}{3}x\frac{5}{6}x\frac{9}{10}x\frac{14}{15}x\frac{20}{21}x\frac{27}{28}\)
\(\frac{9^{10}.5^{30}}{5^{15}.15^{15}}=\frac{3^{10}.3^{10}.5^{30}}{5^{30}.3^{15}}=\frac{3^{20}}{3^{15}}=3^5\)
a,left(9,75.21frac{3}{7}+frac{39}{4}.18frac{4}{7}right).frac{15}{78}
b,frac{-7}{21}+left(1+frac{1}{3}right) c,frac{2}{15}+left(frac{5}{9}+frac{-6}{9}right)
d,left(frac{-1}{5}+frac{3}{12}right)+frac{-3}{4}
e,frac{4}{20}+frac{16}{42}+frac{6}{15}+frac{-3}{5}+frac{2}{21}+frac{-10}{21}+frac{3}{20}
Đọc tiếp
\(a,\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}\)
\(b,\frac{-7}{21}+\left(1+\frac{1}{3}\right)\) \(c,\frac{2}{15}+\left(\frac{5}{9}+\frac{-6}{9}\right)\)
\(d,\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(e,\frac{4}{20}+\frac{16}{42}+\frac{6}{15}+\frac{-3}{5}+\frac{2}{21}+\frac{-10}{21}+\frac{3}{20}\)
Tìm x : \(\frac{6:\frac{3}{5}-1\frac{1}{16}\cdot\frac{6}{7}}{4\frac{1}{5}\cdot\frac{10}{11}+5\frac{2}{11}}\)\(-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right)\cdot\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\)