\(4^0\cdot9^3-6^9\cdot\dfrac{120}{8^4\cdot3^{12}+6^{11}}\) hay \(4^0\cdot9^3-6^9\cdot\dfrac{120}{8^4}\cdot3^{12}+6^{11}\)?

Đề mik chẳng hiểu tý gì luôn

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)

\(=\dfrac{4}{5}\)

utroi vt j z

C

M=4⁸:9⁸+6⁹x120/8⁴x3¹²-6¹¹

M=(2²)⁸:(3²)⁸+6⁹x2³x3x5/(2³)⁴x3¹²-6¹¹

M=2¹⁶:3¹⁶+6⁹x2³x3x5/2¹²x3¹²-6¹¹

M=(2¹⁹:3¹⁷+6⁹⁾x5 / 2¹²x3¹²-6¹¹

M=2⁷:3⁵x5/6²

M=128/243x5:36

M=640/243:36

M=160/2187

tính vế trên trước: 2^12 x 3^5 - 4^6 x 9^2 = 4096 x 243 - 4096 x 81 = 4096 x ( 243 - 81 ) = 663552.

tính vế dưới sau : ( 2^2 x 3 )^6 + 8^4 x 3^5 = ( 4 x 3 )^6 + 4096 x 243 = 12^6 + 995328 = 2985984 + 995328 = 3981312.

Vậy được: 663552/3981312 = 1/6.

1= 2/3:3/4*3=8/3

2=1/8:5/6:1/3=9/20

3=2/5:6/5*2/3=2/9

Chúc bạn học tốt!

1.8/3

2.9/20

3.2/9