\(A=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(A=\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)

\(A=\left(\frac{38}{45}-\frac{8}{45}\right)+\frac{1}{3}+\frac{3}{11}\)

\(A=\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{3}{11}\)

\(A=1+\frac{3}{11}\)

\(A=\frac{11}{11}+\frac{3}{11}=\frac{14}{11}\)

\(B=\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{99}+1\right)\)

\(B=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.\frac{6}{5}...\frac{100}{99}\)

\(B=\frac{3.4.5.6...100}{2.3.4.5...99}\)

\(B=\frac{100}{2}\)

\(B=50\)

Biết lên mạng mà ko biết vào máy tính ak

Biết lên mạng mà ko biết vào máy tính ak

\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(=\left(\frac{38}{45}-\frac{8}{45}\right)-\left(\frac{17}{51}-\frac{3}{11}\right)\)

\(=\frac{2}{3}-\frac{2}{33}\)

\(=\frac{20}{33}\)

Học tốt # ^-<

\(C=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\\ =\frac{38}{45}-\frac{8}{45}+\frac{1}{3}+\frac{3}{11}\\ =\frac{30}{45}+\frac{1}{3}+\frac{3}{11}\\ =\frac{2}{3}+\frac{1}{3}+\frac{3}{11}\\ =1+\frac{3}{11}=\frac{14}{11}\)

Chúc bạn học tốt nha.

\(C=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(C=\frac{38}{45}-\left(-\frac{212}{495}\right)\)

\(C=\frac{14}{11}.\)

Chúc bạn học tốt!

\(C=\frac{28}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(\Leftrightarrow C=\frac{28}{45}-\frac{8}{45}+\frac{1}{3}+\frac{3}{11}\)

\(\Leftrightarrow C=\frac{30}{45}+\frac{1}{3}+\frac{3}{11}=\frac{2}{3}+\frac{1}{3}+\frac{3}{11}\)

\(\Leftrightarrow C=1+\frac{3}{11}=\frac{14}{11}\)

Vậy : \(C=\frac{14}{11}\).

Trả lời

b)(1/3+12/67+13/41)-(79/67-28/41)

=1/3+12/67+13/41-79/67+28/41

=1/3+(12/67-79/67)+(13/41+28/41)

=1/3+(-67/67)+41/41

=1/3+(-1)+1

=1/3+0

=1/3.

c)38/45-(8/45-17/51-3/11)

=38/45-8/45+17/51+3/11

=30/45+1/3+3/11

=2/3+1/3+3/11

=3/3+3/11

=1+3/11

=1 3/11.

d)(17/28+18/29-19/30-30/31).(-5/12+1/4+1/6)

=(17/28+18/29+19/30+30/31).(-5+3+2/12)

=(17/28+18/29+19/30+30/31).0

=0.

a)   \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)=\frac{31}{23}-\frac{7}{32}-\frac{8}{23}=1-\frac{7}{32}=\frac{25}{32}\)

b)   \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

\(=\frac{1}{3}-\left(\frac{79}{67}-\frac{12}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

\(=\frac{1}{3}-1+1=\frac{1}{3}\)

d)   \(\frac{1}{7}.\frac{1}{3}+\frac{1}{7}.\frac{-1}{3}+\frac{17}{19}=\frac{1}{7}.\left(\frac{1}{3}-\frac{1}{3}\right)+\frac{17}{19}=\frac{17}{19}\)

e)  \(\frac{3}{5}.\frac{7}{9}+\frac{7}{5}.\frac{2}{9}=\frac{7}{5}.\left(\frac{3}{9}+\frac{2}{9}\right)=\frac{7}{5}.\frac{5}{9}=\frac{7}{9}\)

a)

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

= \(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

= \(\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

= \(\frac{1}{3}+\left(-1\right)+1\)

= \(\frac{1}{3}+0=\frac{1}{3}\)

b)

\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

= \(\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)

= \(\left(\frac{38}{45}-\frac{8}{45}\right)+\left(\frac{17}{51}+\frac{3}{11}\right)\)

= \(\frac{2}{3}+\frac{20}{33}\)

= \(\frac{14}{11}\)

a) 31/23 - ( 7/32 + 8/22)

= 31/23 - 7/32 + 8/23

= ( 31/23 + 8/23 ) - 7/32

= 32/22 - 7/32

= 39/32

Ccá ý khác làm tương tự

=(31\23-8\23)+7\32

=23\23+7\32

=1+7\32

=39\32

\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(A=49\frac{8}{23}-5\frac{7}{32}+14\frac{8}{23}\)

\(A= \left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(A=\left[\left(49-14\right)-\left(\frac{8}{23}-\frac{8}{23}\right)\right]-5\frac{7}{32}\)

\(A=\left[35-0\right]-5\frac{7}{32}\)

\(A=35-5\frac{7}{32}\)

\(A=\frac{953}{32}\)

\(B=71\frac{38}{45}-\left(43\frac{38}{45}-1\frac{17}{57}\right)\)

\(B=71\frac{38}{45}-\frac{36377}{855}\)

\(B=\frac{1670}{57}\)

\(C=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right):\frac{4}{5}\)

\(C=\left[\left(19\frac{5}{8}-13\frac{1}{4}\right):\frac{7}{12}\right]:\frac{4}{5}\)

\(C=\left[\frac{51}{8}:\frac{7}{12}\right]:\frac{4}{5}\)

\(C=\frac{153}{14}:\frac{4}{5}\)

\(C=\frac{765}{56}\)

\(D=\left[\left(\frac{10}{15}-\frac{2}{3}\right):\frac{1}{7}\right]\cdot0,15-\frac{1}{4}\)

\(D=\left[0:\frac{1}{7}\right]\cdot\frac{3}{20}-\frac{1}{4}\)

\(D=0\cdot\frac{3}{20}-\frac{1}{4}\)

\(D=0-\frac{1}{4}\)

\(D=-\frac{1}{4}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot2\frac{1}{2}-\left[\left(\frac{1}{2}+\frac{1}{3}\right):\frac{53}{90}\right]:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\left[\frac{5}{6}:\frac{53}{90}\right]:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\frac{75}{53}:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{14}{9}-\frac{3}{2}\)

\(\)\(E=\frac{22}{45}\)

CHUC BAN HOC TOT >.<