Uchiha Itachi

-1138

(55-737)-(463-45+38) 

=682 -(463-45+38)

 = 682-456

=  226

(55 – 737) – ( 463 – 45 + 38)                                                                                                =-682 - 456                                                                                                                                   =  -1138

\(A=\dfrac{7^5}{7+7^2+7^3+7^4}=\dfrac{7^5}{\left(7+7^4\right)+\left(7^2+7^3\right)}=\dfrac{7^5}{7^5+7^5}=7^5\)

\(B=\dfrac{5^5}{5+5^2+5^3+5^4}=\dfrac{5^5}{\left(5+5^4\right)+\left(5^2+5^3\right)}=\dfrac{5^5}{5^5+5^5}=5^5\)

Vì 7 > 5 nên \(7^5>5^5\)

Vậy A > B

(Nhớ cho mik một tick nha cảm ơn bạn nhìu :3)

3²+x=81

      x=81-3²

      x= 81-9

      x= 72

Học tốt!

\(3^2+x=81\)

\(\Rightarrow9+x=81\)

\(\Rightarrow x=81-9\)

\(\Rightarrow x=72\)

Vậy \(x=72\)

CHÚC BẠN HỌC TỐT NHÉ

3.(⅓x - ¼)² = ⅓ 

=> (\(\dfrac{1}{3x}\)- \(\dfrac{1}{4}\) )² = \(\dfrac{1}{9}\)

=>\(\left[{}\begin{matrix}\dfrac{1}{3x}-\dfrac{1}{4}=\dfrac{-1}{3}\\\dfrac{1}{3x}-\dfrac{1}{4}=\dfrac{1}{3}\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}\dfrac{1}{3x}=\dfrac{-1}{12}\\\dfrac{1}{3x}=\dfrac{7}{12}\end{matrix}\right.\)        => \(\left[{}\begin{matrix}x=-4\\x=\dfrac{12}{21}=\dfrac{4}{7}\end{matrix}\right.\)

Vậy, tập nghiệm x thỏa mãn là S=\(\left\{-4;\dfrac{4}{7}\right\}\)

X²=3                              x²=25     

=> X=\(\pm\sqrt{3}\)             => x=5

X²=36                           

=> x=6

2.(x-1)²+5⁰= 9

2.(x-1)²+1= 9

2.(x-1)²= 8

(x-1)² = 8/2

(x-1)² = 4 

(x-1)² = (2)²

x-1=(\(\pm\)2)

TH1: x-1= 2              TH2: x-1=-2

        x=2+1                       x =(-2)+1

        x= 3                          x = -1

Vậy x\(\in\)\(\left\{3;1\right\}\)

a) \(\dfrac{3}{4}+\dfrac{9}{5}\div\dfrac{3}{2}-1=\dfrac{3}{4}+\dfrac{18}{15}-1=\dfrac{39}{20}-1=\dfrac{19}{20}\)

b) \(\dfrac{6}{7}\cdot\dfrac{8}{13}+\dfrac{6}{13}\cdot\dfrac{9}{7}-\dfrac{4}{13}\cdot\dfrac{6}{7}=\dfrac{48}{91}+\dfrac{54}{91}-\dfrac{24}{91}=\dfrac{48+51-24}{91}=\dfrac{78}{91}=\dfrac{6}{7}\)

c) \(\dfrac{-3}{7}+\left(\dfrac{3}{-7}-\dfrac{3}{-5}\right)\)\(=\dfrac{-3}{7}+\left(\dfrac{-3}{7}-\dfrac{-3}{5}\right)=\dfrac{-3}{7}+\dfrac{6}{35}=-\dfrac{9}{35}\)

=>6/x=32/35

=>x=6:32/35=6*35/32=210/32=105/16

De ma lam nhu the nay

2 tuan le Mai hoc het so thoi gian la

\(\left(25\cdot2\right)\cdot40=2000\)phút (chú ý dấu chấm là dấu nhân)

dap so:\(2000\) phut

a quen to lam bai 1 con day la bai 2

lam nhu the nay

phai mat so thoi gian de dong goi het 12000 hop la:

\(5\cdot\left(12000:60\right)=1000\)phút(chu y dau cham  la dau phay)

dap so:.......

la dau nhan nha o bai 2 to ghi lon