7450-x:5=765x8
7450-x:5=765x8
7450-x:5=765x8
7450-x:5=6120
x:5=7450-6120
x:5=1330
x=1330x5
x=6650
Vậy x=6650
7450-(x:5)=765x8
7450-(x:5)=6120
x:5 = 7450 - 6120
x:5 = 1330
x = 1330:5
x = 266
7450 - x : 5 = 765 x 8
7450 - x : 5 = 6120
x : 5 = 7450 - 6120
x : 5 = 1330
x = 1330 x 5
x = 6650
Chúc bạn học tốt nha !!!
tim x:7450-X:5=765X8
x:7450-x:5=765x8
x:7450-x:5=6120
x:(7450-5)=6120
x:7445=6120
x=45563400
7450 - x : 5 = 765 x 8
7450 - x : 5 = 765 x 8
7450-x:5 =6120
x:5=7450-6120
x:5=1420
x=1420x5
x=7100
7540 - x : 5 = 6120
x : 5 = 7540 - 6120
x : 5 = 1420
x = 1420 x 5
x = 7100
7450-x=765*8
7450-x=6120
x=7450-6120
x=1330
luu y:* la dau nhan
7450 - x : 5 = 765 x 8
7450-x:5=765x8
7450-x:5=6120
x:5=7450-6120
x:5=1330
x=1330x5
x=6650
(x+1)+(x+2)+(x+3)+....+(x+100) = 7450
(x+1)+(x+2)+(x+3)+....+(x+100) = 7450
=> 100x+ (100+1).100:2=7450
<=> 100x+ 5050=7450
<=> 100x= 2400
<=> x=24
Giải:
(x+1)+(x+2)+(x+3)+...+(x+100)=7450
100x+(1+100).100:2 =7450
100x+5050 =7450
100x =7450-5050
100x =2400
x =2400:100
x =24
Chúc bạn học tốt!
(x+1)+ (x+2)+...+(x+100)=7450
( x + 1 ) + ( x + 2 ) + ... + ( x + 100 ) = 7450
x . 100 + ( 1 + 2 + ... + 100 ) = 7450
x . 100 + [ ( 1 + 100 ) . ( 100 : 2 ) ] = 7450
x . 100 + ( 101 . 50 ) = 7450
x . 100 + 5050 = 7450
x . 100 = 7450 - 5050
x . 100 = 2400
x = 2400 : 100
x = 24
Ta có: (x+1)+(x+2)+...+(x+100)=7450
Nên: (x+x+x+...+x)+(1+2+3+...+100)=7450
Số số hạng của tổng:
(100-1):1+1=100
Tổng :
(100-1). 100 : 2=4950
x+x+x+...+x=7450-4950
x+x+x+...+x=2500
x =2500:100
x = 25
x+(x+1)+(x+2)+...+(x+100)=7450
\(\Rightarrow\)(x+x+x+...+x)+(1+2+..+100)=7450
\(\Rightarrow\)101x+(100+1)*100/2=7450
\(\Rightarrow\)101x+101*50=7450
\(\Rightarrow\)101x+5050=7450
\(\Rightarrow\)101x=7450-5050
\(\Rightarrow\)101x=2400
\(\Rightarrow\)x=2400/101
mik ra k chia hết
nhưng kb vs mik nha ,mik là A.R.M.Y
=> x+x+1+x+2+......+x+100 = 7450
=> 100x + 5050 = 7450
=> 100x = 7450 - 5050 = 2400
=> x = 2400 : 100 = 24
Vậy x = 24
Tk mk nha
x+(x+1)+(x+2)+.........+(x+100) = 7450
(x+x+x+............+x) + (1+2+.........+100) = 7450
100x + 5050 = 7450
100x = 7450 - 5050
100x = 2400
x = 2400 : 100
x = 24
Vậy x = 24
(x+1)+ (x+2)+(x+3)+...+(x+100)=7450
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=7450\)
\(100x+\left(1+2+3+...+100\right)=7450\)
\(100x+\frac{100.101}{2}=7450\)
\(100x+5050=7450\)
\(100x=2400\)
\(\Rightarrow x=24\)
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+......+\left(x+100\right)=7450\)
\(=>100x+\left(1+2+3+4+5+.....+100\right)=7450\)
\(=>100x+\frac{100.101}{2}=7450\)
\(=>100x=2400\)
\(=>x=24\)
Ủng hộ nha
Thanks
(1+2+3+...+100) + (x+x+x+...+x)=7450
A B
Số số hạng của tổng A là: (100-1):1+1= 100 (số)
suy ra tổng B cũng có 100 số hạng
Tổng A là: (100+1).100:2=5050
Ta có:
5050+(x.100)=7450
x.100 =7450-5050
x.100 =2400
x =2400:100
x = 24
tìm x
câu 9 : (x+1)+(x+2)+(x+3)+...+(x+100)=7450
(x +1) + (x + 2) + (x + 3) + (x + 100) = 7450
100x + (1 + 2 + 3 + ... + 100) = 7450
100x + 5050 = 7450
100x = 7450 - 5050
100x = 2400
x = 2400 : 100
x = 24