\(x+\frac{31}{10}=x+\frac{12}{10}+\frac{19}{10}=14,5+\frac{12}{10}\)

\(x+\frac{19}{10}=14,5\)

\(x+1,9=14,5\)

\(x=14,5-1,9=12,6\)

x+\(\frac{31}{10}\)=\(\frac{157}{10}\)

x=\(\frac{157}{10}-\frac{31}{10}\)

x=\(\frac{63}{5}\)

Bấm máy tính

=

ket bn nha cau

mk dng ko co bn olm

\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}.....\frac{30}{62}.\frac{31}{64}=4^x\)

\(\Leftrightarrow\)\(\frac{1.2.3.4.5.....30.31}{4.6.8.10.12.....62.64}=4^x\)

\(\Leftrightarrow\)\(\frac{2.3.4.5.....30.31}{2\left(2.3.4.5.....30.31\right).64}=4^x\)

\(\Leftrightarrow\)\(\frac{1}{128}=4^x\)

\(\Leftrightarrow\)\(2^{2x}=2^{-7}\) ( trong sgk có phần đọc thêm nói về cái này nhé ) 

\(\Leftrightarrow\)\(2x=-7\)

\(\Leftrightarrow\)\(x=\frac{-7}{2}\)

Vậy \(x=\frac{-7}{2}\)

Chúc bạn học tốt ~ 

\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}.....\frac{30}{62}.\frac{31}{64}=4^x\)

\(=\frac{1}{2.2}.\frac{2}{2.3}.\frac{3}{2.4}.\frac{4}{2.5}.\frac{5}{2.6}....\frac{30}{2.31}.\frac{31}{2.32}=4^x\)

\(=\frac{1}{2^{31}.2^5}=4^x\)

\(=\frac{1}{2^{36}}=4^x\)

\(=\frac{1}{2^{36}}=2^{2x}\)

\(=2^{-36}=2^{2x}\)

\(=-36=2.x\)

\(x.2=-36\)

\(x=-36:2\)

\(x=-18\)

\(\frac{23}{10}+\frac{255}{10}=\frac{23+255}{10}=\frac{278}{10}=\frac{139}{5}\)

278/10

k nha

23/10 + 225/10 = 248/10 = 124/5

mình nhầm câu b:

Áp dụng....

A=10^11-1/10^12-1<10^11-1+11/10^12-1+11=10^11+10/10^12+10=10.(10^10+1)/10.(10^11+1)

 =10^10+1/10^11+1=B

Vậy A<B(câu này mới đúng còn câu b mình làm chung với câu a là sai)

a) Với a<b=>a+n/b+n >a/b

    Với a>b=>a+n/b+n<a/b

    Với a=b=>a+n/b+n=a/b

b) Áp dụng t/c a/b<1=>a/b<a+m/b+m(a,b,m thuộc z,b khác 0)ta có:

A=(10^11)-1/(10^12)-1=(10^11)-1+11/(10^12)-1+11=(10^11)+10/(10^12)+10=10.[(10^10)+1]/10.[(10^11)+1]

    =(10^10)+1/(10^11)+1=B

Vậy A=B

\(x+\frac{31}{10}=14,5+\frac{12}{10}\)

\(x+\frac{31}{10}=\frac{29}{2}+\frac{12}{10}\)

\(x+\frac{31}{10}=\frac{157}{10}\)

\(x=\frac{157}{10}-\frac{31}{10}\)

\(x=\frac{63}{5}\)

Học tốt #

\(x+\frac{31}{10}=14,5+\frac{12}{10}\)

\(\Rightarrow x+\frac{31}{10}=\frac{157}{10}\)

\(\Rightarrow x=\frac{157}{10}-\frac{31}{10}\)

\(\Rightarrow x=\frac{63}{5}\)

Vậy  \(x=\frac{63}{5}\)

_Chúc bạn học tốt_

x+31/10=14,5+12/10

x+31/10=29/2 + 12 /10

x+31/10=145/10+12/10

x+31/10=157/10

x=157/10-31/10

x=63/5

Vậy x=63/5

A, 11/12

B, 12,6

a,

x- 7/12 = 1/3

x = 1/3 + 7/12

x = 11/12

b,

x + 31/10 = 14,5

x = 14,5 - 31/10

x = 57/5

\(a,\\ x=\dfrac{1}{3}+\dfrac{7}{12}=\dfrac{11}{12}\\ b,\\ x+\dfrac{31}{10}=\dfrac{157}{10}\\ x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{63}{5}\)