a,
x- 7/12 = 1/3
x = 1/3 + 7/12
x = 11/12
b,
x + 31/10 = 14,5
x = 14,5 - 31/10
x = 57/5
\(a,\\ x=\dfrac{1}{3}+\dfrac{7}{12}=\dfrac{11}{12}\\ b,\\ x+\dfrac{31}{10}=\dfrac{157}{10}\\ x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{63}{5}\)
\(a,x=\dfrac{1}{3}+\dfrac{7}{12}\) \(b,x+\dfrac{31}{10}=\dfrac{157}{10}\)
\(x=\dfrac{4}{12}+\dfrac{7}{12}=\dfrac{11}{12}\) \(x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{126}{10}=\dfrac{63}{5}\)
a) x - 7/12 = 1/3
x = 1/3 + 7/12
x = 11/12
b) x + 31/10 = 14,5 + 12/10
x + 31/10 = 157/10
x = 157/10 - 31/10
x = 126/10
a) x = 1/3 + 7/12
x = 11/12
vậy x =...
b) x + 31/10 = 157/10
x = 157/10 - 31/10
x - 63/5
vậy x =...