làm giúp mình từ câu 1_8
tính bằng cachs thuận tiên
1_2 : 0,5 - 1_4 : 0,25 + 1_5 : 0,2 - 1_8 : 0,125 nêu cách làm ra nhé
ví vụ 1_8 là 1 phần tám
= 0.5 :0.5 -0.25:0.25+0.2:0.2 -0.125:0.125
= 1-1+1-1
=0+ 0
=0
làm cho mình từ câu 21 đến câu 30 nha giúp mình với
21. didn’t go
22. isn’t painting
23. aren’t planting
24. Are they making
25. is repairing
26. is taking
27. is explaining
28. is studying
29. tries/ don’t think
30. passes
21. didn’t go
22. isn’t painting
23. aren’t planting
24. Are they making
25. is repairing
26. is taking
27. is explaining
28. is studying
29. tries/ don’t think
30. passes
giúp mình làm nhé từ câu 51 đến câu 64
giúp mình làm bài từ câu 40 đến câu 64 nhé
có ai có thể giúp mình làm bài này đc ko
Giúp mình làm từ câu 1-52 nha
Mai mình cần rồi:(((
1 Letters are typed by Mary in the office
2 You will be helped by his father tomorrow
3 Human life has completely been changed by science and technology
4 This bottle was broken by Peter
5 English is being learned in the room
6 Maths will be being studied this time next week
7 English has been learning by me for 8 years
8 Max's car was being fixed by him from 3 pm to 5 pm yesterday
9 My mind can't be changed
10 I hadn't been told about it
11 He isn't liked
12 Her telephone number isn't known by ,e
13 The children will be brought home by my students
14 I was sent a present last week
15 We were given more information by her
làm giúp mình từ câu 12 trở đi
16)\(\dfrac{5x+3}{12}\)=\(\dfrac{1+2x}{9}\)
=>\(\dfrac{\left(5x+3\right)x3}{12x3}\)=\(\dfrac{\left(1+2x\right)x3}{9x3}\)
Khử mẫu
=>5x4+3x3=x3+2x4
=>5x4+3x3-x3+2x4=0
=>7x4+2x3=0
=>x3(7x+2)=0
=>x=0 hoặc 7x+2=0=>x=-2/7
Làm giúp mình với ạ, mìn đang cần gấp. Làm từ câu 4 ạ
Tất cả k dưới đây đều là \(k\in Z\)
6.
\(\Leftrightarrow\sqrt{3}cot\left(3x-\dfrac{\pi}{3}\right)=1\)
\(\Leftrightarrow cot\left(3x-\dfrac{\pi}{3}\right)=\dfrac{1}{\sqrt{3}}\)
\(\Leftrightarrow cot\left(3x-\dfrac{\pi}{3}\right)=cot\left(\dfrac{\pi}{3}\right)\)
\(\Leftrightarrow3x-\dfrac{\pi}{3}=\dfrac{\pi}{3}+k\pi\)
\(\Leftrightarrow3x=\dfrac{2\pi}{3}+k\pi\)
\(\Leftrightarrow x=\dfrac{2\pi}{9}+\dfrac{k\pi}{3}\)
7.
\(\Leftrightarrow\sqrt{3}tan\left(3x-15^0\right)=-1\)
\(\Leftrightarrow tan\left(3x-15^0\right)=-\dfrac{1}{\sqrt{3}}\)
\(\Leftrightarrow tan\left(3x-15^0\right)=tan\left(-30^0\right)\)
\(\Leftrightarrow3x-15^0=-30^0+k180^0\)
\(\Leftrightarrow3x=-15^0+k180^0\)
\(\Leftrightarrow x=-3^0+k60^0\)
8.
\(\Leftrightarrow\sqrt{3}cot\left(3x-30^0\right)=1\)
\(\Leftrightarrow cot\left(3x-30^0\right)=\dfrac{1}{\sqrt{3}}\)
\(\Leftrightarrow cot\left(3x-30^0\right)=cot\left(60^0\right)\)
\(\Leftrightarrow3x-30^0=60^0+k180^0\)
\(\Leftrightarrow3x=90^0+k180^0\)
\(\Leftrightarrow x=30^0+k60^0\)
Làm giúp mình từ câu 7 trở đi với <3
Mn làm giúp mình từ câu 9 - 12 với ạ
9. NaHCO3 + HCl → NaCl + H2O + CO2
=> PT ion : \(HCO_3^-+H^+\rightarrow CO_2+H_2O\)
10. NaHCO3 + NaOH → Na2CO3 + H2O
=> PT ion : \(HCO_3^-+OH^-\rightarrow CO_3^{2-}+H_2O\)
11. NH4Cl + NaOH → NH3 + H2O + NaCl
=> PT ion :\(NH_4^++OH^-\rightarrow NH_3+H_2O\)
12. Na2SO4 + FeCl3 -----//---->