Bài 1: 

a: \(=-10x^3+20x^4-5x\)

b: \(=\dfrac{1}{3}a^2b+7a^5-1\)

c: \(=a^3+8+25-a^3=33\)

d: \(=x^2-16+8-x^3=-x^3+x^2-8\)

e: \(=a^3+1+8-a^3=9\)

f: \(=\dfrac{7-2x+4x-8}{2x+3}=\dfrac{2x-1}{2x+3}\)

g: \(=\dfrac{3}{2\left(x+3\right)}-\dfrac{2}{x\left(x+3\right)}\)

\(=\dfrac{3x-4}{2x\left(x+3\right)}\)

Bài 3: 

a: \(A=\dfrac{3\left(x+4\right)}{\left(x+4\right)\left(x-4\right)}=\dfrac{3}{x-4}\)

b: Để A nguyên thì \(x-4\in\left\{1;-1;3;-3\right\}\)

hay \(x\in\left\{5;3;7;1\right\}\)

Bài 2: 

a: \(=y\left(6x-y\right)\)

b: \(=x\left(y-2\right)+2\left(y-2\right)=\left(y-2\right)\left(x+2\right)\)

c: =(x+2)(x+5)

\(A=\left(1-\dfrac{1}{4}\right)\left(1-\dfrac{1}{9}\right)\cdot...\cdot\left(1-\dfrac{1}{9801}\right)\)

\(=\left(1-\dfrac{1}{2}\right)\left(1+\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1+\dfrac{1}{3}\right)\cdot...\left(1-\dfrac{1}{99}\right)\left(1+\dfrac{1}{99}\right)\)

\(=\left(\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot...\cdot\dfrac{98}{99}\right)\cdot\left(\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{100}{99}\right)\)

\(=\dfrac{1}{99}\cdot\dfrac{100}{2}=\dfrac{50}{99}\)

Bài 1:

a. 

$-12-(-46)=-12+46=46-12=34$

b.

$-(-8)-54=8-54=-(54-8)=-46$

c.

$-15-(-72)=-15+72=72-15=57$

Bài 2:

a. $(156-812)-(156-12)=156-812-156+12$

$=(156-156)-(812-12)=0-800=-800$

b.

$-(-72+83)-(72+17)=72-83-72-17=(72-72)-(83+17)$

$=0-100=-100$

c.

$-(-23-78)+(77-178)=23+78+77-178$

$=(23+77)-(178-78)=100-100=0$

d.

$(-213-156)-(-213+44)=-213-156+213-44=(-213+213)-(156+44)$

$=0-200=-200$

\(\Leftrightarrow3x-125=1\)

hay x=42

2 và 2/5 x 25/18=12/5 x 25/18=10/3

9/11 : 2 và 5/2 x 2 và 3/4=9/11 : 9/2 x 11/4

                                          =2/11 x 11/4

                                          =1/2