17/15>29/32

12/18<13/17

16/51>31/96

21/25>19/29>60/81

a 

oki

_{Làm ơn giúp mình với !}

=> A < B

chắc vại-.-

tui hok giỏi toán lém

\(a,\dfrac{2021}{2020}>1;\dfrac{8954}{88939}< 1\\ nên:\dfrac{8954}{88939}< 1< \dfrac{2021}{2020}\\ Vậy:\dfrac{2021}{2020}>\dfrac{8954}{88939}\)

\(b,\dfrac{14}{21}=\dfrac{14:7}{21:7}=\dfrac{2}{3}\\ \dfrac{51}{85}=\dfrac{51:17}{85:17}=\dfrac{3}{5}\\ Ta.có:\dfrac{2}{3}=\dfrac{10}{15};\dfrac{3}{5}=\dfrac{9}{15}\\ Vì:\dfrac{10}{15}>\dfrac{9}{15}\Rightarrow\dfrac{2}{3}>\dfrac{3}{5}\\ Vậy:\dfrac{14}{21}>\dfrac{51}{85}\)

a) \(\dfrac{3}{4}=\dfrac{3x4}{4x4}=\dfrac{12}{16},\dfrac{6}{7}=\dfrac{6x2}{7x2}=\dfrac{12}{14}\)

Do 16 > 14 => \(\dfrac{12}{16}< \dfrac{12}{14}hay\dfrac{3}{4}< \dfrac{6}{7}\)

1216<1214hay34<67

a/

2020.2021=(2019+1)(2022-1)=

=2019.2022-2019+2022-1=2019.2022+2>2019.2022

b/

\(4^7=\left(2^2\right)^7=2^{14}< 2^{15}\)

c/

\(199^{20}< 200^{20}=\left(8.25\right)^{20}=\left(2^3.5^2\right)^{20}=2^{60}.5^{40}\)

\(2000^{15}=\left(16.125\right)^{15}=\left(2^4.5^3\right)^{15}=2^{60}.5^{45}\)

\(\Rightarrow2000^{15}=2^{60}.5^{45}>2^{60}.5^{40}>199^{20}\)

d/

\(31^{31}< 32^{31}=\left(2^5\right)^{31}=2^{155}\)

\(17^{39}>16^{39}=\left(2^4\right)^{39}=2^{156}\)

\(\Rightarrow17^{39}=2^{156}>2^{155}>31^{31}\)