1) 3n ⋮ 2n - 5

=> 2(3n) - 3(2n - 5)  ⋮ 2n - 5

=> 6n - 6n + 15 ⋮ 2n - 5

=> 15 ⋮ 2n - 5

=> 2n-5 ϵ Ư(15)

Ư(15) = {1;-1;3;-3;5;-5;15;-15}

=> n={3;2;4 ;1;5;0;10;-5}

nhớ nha

1) 3n ⋮ 2n - 5

=> 2(3n) - 3(2n - 5)  ⋮ 2n - 5

=> 6n - 6n + 15 ⋮ 2n - 5

=> 15 ⋮ 2n - 5

=> 2n-5 ϵ Ư(15)

Ư(15) = {1;-1;3;-3;5;-5;15;-15}

=> n={3;2;4 ;1;5;0;10;-5}

a: =>4n-2-3 chia hết cho 2n-1

=>\(2n-1\in\left\{1;-1;3;-3\right\}\)

=>\(n\in\left\{1;0;2\right\}\)

b: =>6n-4+11 chia hết cho 3n-2

=>\(3n-2\in\left\{1;-1;11;-11\right\}\)

=>\(n\in\left\{1\right\}\)

\(1,3n+7=3n+3+4=3\left(n+1\right)+4⋮\left(n+1\right)\\ =>n+1\inƯ\left(4\right)\\ Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\\ TH1,n+1=1\\ =>n=0\\ TH2,n+1=-1\\ =>n=-2\\ TH3,n+1=2\\ =>n=1\\ TH3,n+1=-2\\ =>n=-3\\ TH4,n+1=4\\ =>n=3\\ TH5,n+1=-4\\ =>n=-5\)

a)

\(n+3⋮n-1\Leftrightarrow\left(n-1\right)+4⋮n-1\)

\(\Rightarrow4⋮n-1\) (vì n-1 chia hết cho n-1)

\(\Rightarrow n-1\inƯ\left(4\right)=\left\{1;2;4\right\}\)

\(n-1=1\Rightarrow n=2\)

\(n-1=2\Rightarrow n=3\)

\(n-1=4\Rightarrow n=5\)

Vậy \(n\in\left\{2;3;5\right\}\)

n=1

vì 5-2*1=3

3/3=1