Tính hợp lý: 4 6 . 9 5 + 6 9 . 120 8 4 . 3 12 − 6 11
Tính bằng cách hợp lý :
2/5 + 6/9 + 7/4 + 3/5 + 1/3 + 1/4
= (2/5 + 3/5) + (6/9 + 1/3) + (7/4 + 1/4)
= 1 + (6/9 + 3/9) + 2 = 1 + 1 + 2 = 4
\(\dfrac{2}{5}+\dfrac{6}{9}+\dfrac{7}{4}+\dfrac{3}{5}+\dfrac{1}{3}+\dfrac{1}{4}\\ =\left(\dfrac{2}{5}+\dfrac{3}{5}\right)+\left(\dfrac{7}{4}+\dfrac{1}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\\ =1+2+1=4\)
\(\dfrac{2}{5}+\dfrac{6}{9}+\dfrac{7}{4}+\dfrac{3}{5}+\dfrac{1}{3}+\dfrac{1}{4}\)
=\(\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{7}{4}+\dfrac{3}{5}+\dfrac{1}{3}+\dfrac{1}{4}\)
=\(\left(\dfrac{2}{5}+\dfrac{3}{5}\right)+ \left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\left(\dfrac{7}{4}+\dfrac{1}{4}\right)\)
=1+1+2
=4
Tính hợp lý
A=A=7/4*5-9/4*5+11/5*6-11/6*7+13/7*8-15/8*9+17/9*10-19/10*11
tính hợp lý :240÷(5^3-5^3÷5^2)- 3^6÷3^4 +15 x 11x(13 - 9 )
\(240:\left(5^3-5^3:5^2\right)-3^6:3^4+15\cdot11\cdot\left(13-9\right)\)
\(=240:\left(5^3-5\right)-3^{6-4}+15\cdot11\cdot4\)
\(=240\cdot\left(125-5\right)-3^2+60\cdot11\)
\(=240:120-9+60\cdot\left(10+1\right)\)
\(=2-9+600+60\)
\(=653\)
tính hợp lý: (3^11*5+4*9^6)/(27^3*25-3^9*8)
Tính hợp lý bài toán sau đây
4/9 × -7 + 6 4/5 × -7
tính hợp lý : (7^3 + 7^5) x (5^4 + 5^6) x (3^3 x 3 - 9^2)
3. Tính bằng cách hợp lý: A) 4/9 + 2/5 + 5/9. B) 6/13 + 5/8 + 7/13. C) 5/11 + 6/25 + 66/121. D) 1/2 + 1/3 + 1/4 + 1/6 + 1/12 + 1/24.
`a, 4/9 + 2/5 + 5/9= (4/9 +5/9) + 2/5= 1 + 2/5= 5/5 + 2/5= 7/5`
`b, 6/13 + 5/8 + 7/13=(6/13 + 7/13) + 5/8=1+5/8= 8/8 + 5/8= 13/8`
`c, 5/11 + 6/25 + 66/121 = ( 5/11 + 66/121 ) + 6/25=1 + 6/25 = 25/25 + 6/25 = 31/25`
`d, 1/2 + 1/3 + 1/4 + 1/6 + 1/12 + 1/24= (1/2 + 1/4) +(1/3 + 1/6) + (1/12 + 1/24)= 3/4 + 1/2 + 1/8= 6/8 + 4/8 + 1/8= 11/8`
`@ yl`
tính hợp lý: (7^3 + 7^5) x (5^4 + 5^6) x (3^3 x 3 - 9^2)
Cứu mình với!!: tính hợp lý:
(4 ^ 10 x 9 ^ 6 + 3 ^ 12 x 8 ^ 5 / 6 ^ 13 x 4 - 2 ^ 16 x 3 ^ 12)
tính hợp lý:2^12*243-4^6*9^2/(2^2*3)^6+8^4*3^5
vẹ em với^-^
em lớp 6
\(\frac{2^{12}.243-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(=\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5.\left(3-1\right)}\)
\(=\frac{1}{3}\)
HT