tớ 0 biết làm

a: =2-81-24-81=-22-162=-184

a) Bạn Nguyễn Lê Phước Thịnh giải rồi nha bạn :)

b) (-9-x+2)+9

=-9-x+2+9

=-9+(-x)+2+9

=(-x)+(-9+2+9)

=(-x)+2

c) 66-(12-x)+(12-66)

=66-12+x+12-66

=x

d) 15-(15-x+93)+93

=15-15+x-93+93

=x

bla bla bla bla bla

thu gọn 7^3*7^5

Oh no nhiều kí tự đặc biệt quá

dễ quá mình ko làm  đc 

\(a,\frac{45}{60}=\frac{45:15}{60:15}=\frac{3}{4}\)

\(b,\frac{39}{12}=\frac{39:3}{12:3}=\frac{13}{4}\)

\(c,\frac{81}{90}=\frac{81:9}{90:9}=\frac{9}{10}\)

\(d,\frac{360}{720}=\frac{360:360}{720:360}=\frac{1}{2}\)

\(e,\frac{24}{20}=\frac{24:4}{20:4}=\frac{6}{5}\)

\(g,\frac{66}{65}=\frac{66}{65}\)

\(...,\frac{66}{55}=\frac{66:11}{55:11}=\frac{6}{5}\)

a) 45/60 = 3/4

b)  39/12 = 13/4

c) 81/90 = 9/10

d) 360/720 = 1/2

e) 24/20 = 6/5

g) 66/65 = 66/65

h) 66/55 = 6/5

mik nha !~

Bài 4:

a: xy=-2

=>\(x\cdot y=1\cdot\left(-2\right)=\left(-2\right)\cdot1=\left(-1\right)\cdot2=2\cdot\left(-1\right)\)

=>\(\left(x,y\right)\in\left\{\left(1;-2\right);\left(-2;1\right);\left(-1;2\right);\left(2;-1\right)\right\}\)

b: \(\left(x-1\right)\left(y+2\right)=-3\)

=>\(\left(x-1\right)\cdot\left(y+2\right)=1\cdot\left(-3\right)=\left(-3\right)\cdot1=-1\cdot3=3\cdot\left(-1\right)\)

=>\(\left(x-1;y+2\right)\in\left\{\left(1;-3\right);\left(-3;1\right);\left(-1;3\right);\left(3;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(2;-5\right);\left(-2;-1\right);\left(0;1\right);\left(4;-3\right)\right\}\)

Bài 3:

a: \(x\left(x+9\right)=0\)

=>\(\left[{}\begin{matrix}x=0\\x+9=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=0\\x=-9\end{matrix}\right.\)

b: \(\left(x-5\right)^2=9\)

=>\(\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=3+5=8\\x=-3+5=2\end{matrix}\right.\)

c: \(\left(7-x\right)^2=-64\)

mà \(\left(7-x\right)^2>=0\forall x\)

nên \(x\in\varnothing\)

Bài 2:

a: \(\left(-31\right)\cdot x=-93\)

=>\(31\cdot x=93\)

=>\(x=\dfrac{93}{31}=3\)

b: \(\left(-4\right)\cdot x=-20\)

=>\(4\cdot x=20\)

=>\(x=\dfrac{20}{4}=5\)

c: \(5x+1=-4\)

=>\(5x=-4-1=-5\)

=>\(x=-\dfrac{5}{5}=-1\)

d: \(-12x+1=-4\)

=>\(-12x=-4-1=-5\)

=>\(12x=5\)

=>\(x=\dfrac{5}{12}\)

a)x+(-81)-(11-81)

=x-81-11+81

=x-11

b)(-1-x+2)+1

=-1-x+2+1

=-x+2

c)15-(11-x)+(11-15)

=15-11+x+11-15

=x

d)15-(15-x+202)+202

=15-15+x-202+202

=x

a) \(x+\left(-81\right)-\left(11-81\right)=x-81-11+81=x-11\)

b) \(\left(-1-x+2\right)+1=\left(-1\right)-x+2+1=-x+2=2-x\)

c) \(15-\left(11-x\right)+\left(11-15\right)=15-11-x+11-15\)

\(=\left(15-15\right)+\left(11-11\right)+x=0+0+x=x\)

d) \(15-\left(15-x+202\right)=15-15+x-202=x-202\)

a)x-81-11+81=x-11
b)(-1-x+2)+1=-1-x+2+1=2-x
c)15-(11-x)+(11-15)=15-11+x+11-15=x
d)15-(15-x+202)+202=15-15+x-202+202=x

Sorry câu cuối là \(15-15+x-202+202=\left(15-15\right)+x+\left(202-202\right)=x\) nhé

1. Từ bé đến lớn: \(\frac{3}{10};\frac{8}{15};\frac{9}{6};\frac{13}{5};\frac{16}{3}\)

2. 

a, Ta có: \(\frac{24}{36}=\frac{6}{9}\)  ;  \(\frac{15}{27}=\frac{5}{9}\)

Vì \(\frac{6}{9}>\frac{5}{9}\)nên \(\frac{24}{36}>\frac{15}{27}\)

P/s: Các câu còn lại tương tự :>