\(\frac{3}{4}x+1=-2\)

=>\(\frac{3}{4}x=-2-1\)

=>\(x=-3:\frac{3}{4}\)

=>\(x=\frac{-3.4}{3}=-4\)

=>x=-4

gia tri x<0 thoa man 

x^2:(-1/2)^3=-1/2 là -1/4

gia tri x thoa man 

(x-1/2)^20=0 là 0 có

\(\Delta'=\left(m+1\right)^2-\left(m^2+2m\right)=1>0\)

\(\Rightarrow\) Phương trình luôn có 2 nghiệm: \(\left\{{}\begin{matrix}x_1=m+1-1=m\\x_2=m+1+1=m+2\end{matrix}\right.\)

\(\left|x_1\right|=3\left|x_2\right|\Leftrightarrow\left|m\right|=3\left|m+2\right|\)

\(\Leftrightarrow\left[{}\begin{matrix}3m+6=-m\\3m+6=m\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}m=-\dfrac{3}{2}\\m=-3\end{matrix}\right.\)

<=>(x+9)*7=(x+5)*2

<=>(x+9)7=7(x+9)

=>(x+5)2=2(x+5)

=>7(x+9)=2(x+5)

=>7x+63=2x+10

=>5x-53

=>x=\(\frac{-53}{5}\)

\(\frac{x+9}{x+5}=\frac{x+5+4}{x+5}=1+\frac{4}{x+5}=\frac{2}{7}\)

\(\frac{4}{x+5}=\frac{2}{7}-1=-\frac{5}{7}\)  

\(\frac{4}{x+5}=-\frac{5}{7}\Leftrightarrow4.\left(-7\right)=5\left(x+5\right)\)

\(\Leftrightarrow-28=5x+25\)

\(\Leftrightarrow-28-25=5x\Leftrightarrow5x=-53\Leftrightarrow x=-\frac{53}{5}\)

2^2x*3^2x=36^24

=>(2*3)^2x=36^24

=>6^2x=36^24

=>36^x=36^24

=>x=24 ok nha