a, Ta có: 10 = 2.5; 12 =  2 2 .3

BCNN(10,12) = 2 2 .3.5 = 60

b, Ta có: 24 =  2 3 .3; 56 =  2 3 .7

BCNN(24;56) =  2 3 .3.7 = 168

c, Ta có: 84 =  2 2 .3.7; 108 =  2 2 . 3 3

BCNN(84;108) =  2 2 . 3 3 .7

d, Ta có: 33 = 3.11; 44 = 4.11; 55 = 5.11

BCNN(33;44;55) = 3.4.5.11 = 660

e, Ta có: 8 =  2 3 ; 18 = 2. 3 2 ; 30 = 2.3.5

BCNN(8,18,30) =  2 3 . 3 2 . 5 = 360

f, Ta có: 40 =  2 3 . 5 ; 28 =  2 2 .7; 140 =  2 2 .5.7

BCNN(40;28;140) =  2 3 . 5 . 7 = 280

a: BCNN(15;18)=90

a)15va 18  

15=3.5

18=3^2.2

BCNN(15;18)=2.3^2.5=90

d)33;44va55

33=3.11

44=4.11

55=5.11

BCNN(33;44;55)=3.4.5.11=660

c)4;14 va 26

4=2^2

14=2.7

26=2.13

BCNN(4;14;26)=2^2.7.13=364

\(a.15=3.5;18=2.3^2\)

\(BCNN\left(15;18\right)=2.3^2.5=90\)
 

\(b.33=3.11;44=2^2.11;55=5.11\)

\(BCNN\left(33;44;55\right)=2^2.3.5.11=660\)

\(c.4=2^2;14=2.7;26=2.13\)

\(BCNN\left(4;14;26\right)=2^2.7.13=364\)

a: \(42=2\cdot3\cdot7;70=2\cdot5\cdot7\)

=>\(BCNN\left(42;70\right)=2\cdot3\cdot5\cdot7=210\)

=>\(BC\left(42;70\right)=B\left(210\right)=\left\{0;210;420;...\right\}\)

b: \(70=2\cdot5\cdot7;180=3^2\cdot5\cdot2^2\)

=>\(BCNN\left(70;180\right)=2^2\cdot3^2\cdot5\cdot7=1260\)

=>\(BC\left(70;180\right)=\left\{1260;2520;...\right\}\)

c: \(5=5;7=7;8=2^3\)

=>\(BCNN\left(5;7;8\right)=5\cdot7\cdot8=280\)

=>\(BC\left(5;7;8\right)=\left\{280;560;...\right\}\)

d: \(12=2^2\cdot3;18=3^2\cdot2\)

=>\(BCNN\left(12;18\right)=2^2\cdot3^2=36\)

=>\(BC\left(12;18\right)=\left\{36;72;...\right\}\)

e: \(15=3\cdot5;18=3^2\cdot2\)

=>\(BCNN\left(15;18\right)=3^2\cdot2\cdot5=90\)

=>\(BC\left(15;18\right)=\left\{90;180;...\right\}\)

f: \(84=2^2\cdot3\cdot7;108=3^3\cdot2^2\)

=>\(BCNN\left(84;108\right)=2^2\cdot3^3\cdot7=756\)

=>\(BC\left(84;108\right)=\left\{756;1512;...\right\}\)

j: \(33=3\cdot11;44=2^2\cdot11;55=5\cdot11\)

=>\(BCNN\left(33;44;55\right)=3\cdot2^2\cdot5\cdot11=660\)

=>\(BC\left(33;44;55\right)=\left\{660;1320;...\right\}\)

g: \(1=1;12=2^2\cdot3;27=3^3\)

=>\(BCNN\left(1;12;27\right)=1\cdot2^2\cdot3^3=108\)

=>\(BC\left(1;12;27\right)=\left\{108;216;...\right\}\)

n: \(5=5;9=3^2;11=11\)

=>\(BCNN\left(5;9;11\right)=5\cdot3^2\cdot11=495\)

=>\(BC\left(5;9;11\right)=\left\{495;990;...\right\}\)

giúp mik với nha

khó thế

1) Tìm ƯCLN và viết tập hợp các ƯC của:

a) 18 và 24

Ta có:

18 = 2.3²

24 = 2³.3

=> ƯCLN (18;24) = 2.3 = 6

=> ƯC (18;24) = Ư (6) = {1;2;3}

b) 40;70 và 110

Ta có:

40 = 2³.5

70 = 2.5.7 

110 = 2.5.11

=> ƯCLN (40;70;110) = 2.5 = 10

=> ƯC (40;70;110) = Ư (10) = {1;2;5;10}

c) 200; 240 và 300

Ta có :

200 = 2³.5²

240 = 2^4.3.5

300 = 2².3².5

=> ƯCLN (200;240;300) = 2².5 = 20

=> ƯC (200;240;300) = Ư (20) = {1;2;3;4;5;10;20}

2) Tìm BCNN và viết tập hợp các BC của:

a) 12 và 15

Ta có:

12 = 2².3

15 = 3.5

=> BCNN (12;15) = 2².3.5 = 30

=> BC (12;15) = B (30) = {0;30;60;90;120;150;180;...}

b) 15; 20 và 30

Ta có:

15 = 3.5

20 = 2².5

30 = 2.3.5

=> BCNN (15;20;30) = 2².3.5 = 60

=> BC (15;20;30) = B (60) = {0;60;120;180;...}

c) 24;36 và 48

Ta có:

24 = 2³.3

36 = 2².3²

48 = 2^4.3

=> BCNN (24;36;48) = 2^4.3² = 16

=> BC (24;36;48) = B (16) = {0;16;32;48;...}

Bạn nhớ TICK MÌNH NHA!!!!!!

Mn giúp tui vs nha

a: UCLN(24;9)=3

BCNN(24;9)=72

b: UCLN(98760;6780)=60

BCNN(98760;6780)=11159880

1: UCLN(12;18)=6

BCNN(12;18)=36

2: UCLN(24;48)=24

BCNN(24;48)=48