a) \(\dfrac{3}{4}=\dfrac{3x4}{4x4}=\dfrac{12}{16},\dfrac{6}{7}=\dfrac{6x2}{7x2}=\dfrac{12}{14}\)

Do 16 > 14 => \(\dfrac{12}{16}< \dfrac{12}{14}hay\dfrac{3}{4}< \dfrac{6}{7}\)

1216<1214hay34<67

a ) 3 4 = 6 8 < 6 7 b ) 17 − 21 = 51 − 63 > 51 − 31

c ) − 4 9 = 12 27 < − 12 52 = − 3 13 d ) − 4 − 11 = 12 33 > 12 38 = − 6 − 19

a)  − 4 9 = − 12 27 < − 12 52 = − 3 13

b)  − 4 − 11 = 12 33 > 12 38 = − 6 − 19

a ) 2 3 < 4 5 b ) 13 − 27 > 39 − 37 ; c ) − 3 7 < − 2 9 d ) − 2 − 7 < − 5 − 17

Co j góc lệch cùng trời cuối đất cú mèo

b, \(\dfrac{7}{13}\) và \(\dfrac{17}{23}\) 

\(\dfrac{7}{13}\) <  \(\dfrac{7+10}{13+10}\) = \(\dfrac{17}{23}\)

Vậy \(\dfrac{7}{13}\) < \(\dfrac{17}{23}\) 

\(\dfrac{12}{48}\) =  \(\dfrac{12:12}{48:12}\)  = \(\dfrac{1}{4}\) 

\(\dfrac{13}{47}\) > \(\dfrac{13}{52}\) = \(\dfrac{13:13}{52:13}\) = \(\dfrac{1}{4}\) 

Vậy  \(\dfrac{12}{48}\) < \(\dfrac{13}{47}\) 

+ Quy đồng mẫu các phân số: \(\dfrac{3}{4}\) và \(\dfrac{5}{6}\):

\(BCNN\left( {6,4} \right) = 12\)

Thừa số phụ: \(12:4 = 3; 12:6=2\)

Ta có: \(\dfrac{3}{4} = \dfrac{{3.3}}{{4.3}} = \dfrac{9}{{12}}\\\dfrac{5}{6} = \dfrac{{5.2}}{{6.2}} = \dfrac{{10}}{{12}}\)

+ So sánh hai phân số cùng mẫu:

Vì 9 < 10 nên \(\dfrac{9}{{12}} < \dfrac{{10}}{{12}}\) nên \(\dfrac{3}{4} < \dfrac{5}{6}\).