Bài này giống toán lớp 6 hơn

m = 3/(1x4) + 3/(4x7) +  ... + 3/(19x22)

    = (4-1)/(1x4) + (7-4)/(4x7) +  ... + (22-19)/(19x22)

    = 4/(1x4) - 1/(1x4) + 7/(4x7) - 4/(4x7) + ... +  22/(19x22) - 19/(19x22)

    = 1 - 1/4 + 1/4 - 1/7 + ... + 1/19 - 1/22

    = 1-1/22

    = 21/22

câu a 

quá dễ

=1/1-1/4+1/4-1/7+1/7-1/10+1/10-1/13+1/13-1/16

=1-1/16=15/16

3/(1×4)+3/(4×7)+3/(7×10)+3/(10×13)+3/(13×16)

=1-1/4+1/4-1/7+1/7-1/10+1/10-1/13+1/13-1/16

=1-1/16

=15/16

31 x 434 x 737 x 10310 x 13 = 1.3289876e+12

mik phải dùng máy tính chứ có sịp nhân mới trả lời đc 

nhỉ ?????

ko có 3/13x16 nha bn

=1-1/4+1/4-1/7+1/7-...+1/37-1/40

=1-1/40=39/40

Mình cần gấp ạ. Mốt mik thi rồi

Mình đang gấp lắm ạ

=1−14 +14 −110 +...+119 −122 

=1−122 

 =  \(\frac{21}{22}\)

k cho mình nha chắc chắn đúng 100 %

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{10}+...+\frac{1}{19}-\frac{1}{22}\)

\(=1-\frac{1}{22}\)

\(=\frac{21}{22}\)

\(=\frac{1}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{16.19}+\frac{3}{19.22}\right)\)

\(=\frac{1}{3}\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{20}\right)\)

\(=\frac{1}{3}\left(1-\frac{1}{20}\right)\)

\(=\frac{1}{3}.\frac{19}{20}\)

\(=\frac{19}{60}\)

\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{94.97}\)

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{94}-\frac{1}{97}\)

\(=1-\frac{1}{97}\)

\(=\frac{96}{97}\)

Bài làm:

Ta có: \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{94.97}\)

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{94}-\frac{1}{97}\)

\(=1-\frac{1}{97}\)

\(=\frac{96}{97}\)

Ta có \(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{94.97}=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{94}-\frac{1}{7}=1-\frac{1}{7}=\frac{6}{7}\)

P/S : Dấu "." là dấu "x" nha !

k mk  đi , mk k lại cho

\(A=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+....+\frac{3}{197\times200}\)

\(A=\frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10}+.....+\frac{1}{197\times200}\)

\(A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+....\frac{1}{197}-\frac{1}{200}\)

\(A=\frac{1}{1}-\frac{1}{200}\)

\(A=\frac{199}{200}\)

a = 1/1- 1 /197 - 1 /200

a = 1/1 - 1/200

a = 199/200