Tìm x: x - 306 = 504
Tìm x:
a) x - 306 = 504;
b) x + 254 = 680.
a) x - 306 = 504
x = 504 + 306
x = 810
b) x + 254 = 680
x = 680 - 254
x = 426
Tìm x. (X+X×2):34=504
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Nhớ k cho mình nah
( X +X x 2 ) :34 = 504
X x 3 = 504 x 34
X x 3 = 17136
X= 17136 :3
X= 5712
tìm x :
a) 504 : ( 16 - 3 x X ) = 72 d) 272 - (4 x X + 15) = 45
`a, 504 : (16-3x)=72`
`<=> 16-3x=7`
`<=>3x=9`
`<=>x=3`
`b,272-(4x+15)=45`
`<=>4x+15=227`
`<=>4x=212`
`<=>x=53`
a: =>16-3x=504:72=7
=>3x=9
=>x=3
b: =>4x+15=272-45=227
=>4x=212
=>x=53
a) 504 : (16 - 3\(\times\)x) = 72
=> 16 - 3\(\times\)x = 7
=> 3\(\times\)x = 9
=> x = 3
d) 272 - (4\(\times\)x + 15) = 45
=> 4\(\times\)x + 15 = 227
=> 4\(\times\)x = 212
=> x = 53
tìm x
2. x +4.x+8.x=504
Ta có: 2. x +4.x+8.x=504
=> 14x = 504
=> x = 504 : 14
=> x = 36
|x|=|-1\3|
tìm các số nguyên x {|x|+2017} x {504|x|-2016} <0
\(\left|x\right|=\left|-\frac{1}{3}\right|\)
\(\left|x\right|=\frac{1}{3}\)
\(\Rightarrow\text{ }x\in\left\{-\frac{1}{3}\text{ ; }\frac{1}{3}\right\}\)
\(\left|x\right|=\left|-\frac{1}{3}\right|\)
\(\left|x\right|=\frac{1}{3}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{3}\\x=\frac{1}{3}\end{cases}}\)
\(\Rightarrow\text{ }x\in\left\{-\frac{1}{3}\text{ ; }3\right\}\)
tìm các số x,y,z biết
x ( x-1)^2019+|y/4-504|: ( x-1 ) ^2019
Phần tự luận
Tìm x.
x - 306 = 480
Tìm x:
2x + 4x + 8x =504
2x + 4x + 8x = 504
=> 14x = 504
x = 504 : 14
x = 36
1/2×3 + 1/ 3×4 + 1/4×5 + ........ + 1/ X- 1×X= 504/ 1009
Tìm X
Sửa đề :
\(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x}+\frac{1}{x\left(x+1\right)}=\frac{504}{1009}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2018}\)
\(\Leftrightarrow x=2018-1\)
\(\Leftrightarrow x=2017\)
Vậy ...
Sửa đề \(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+....+\frac{1}{x}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{504}{1009}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2018}\)
\(\Leftrightarrow x=2017\)