a, 2 x 4 x 8 x 0,5 x 0,125 x 0,25 x ( 0,4321 + 0,5679 )

= ( 2 x 0,5 ) x ( 4 x 0,25 ) x ( 0,125 x 8 ) x ( 0,4321 + 0,5679 )

= 1 x 1 x 1 x ( 0,4321 + 0,5679 )

= 1 x ( 0,4321 + 0,5679 ) 

= 1 x 1 = 1

b, 3,7 x 3,8 + 8,3 x 3,7 - 0,4 x 3,7 x 5

= 3,7 x ( 3,8 + 8,3 ) - ( 0,4 x 5 ) x 3,7

= 3,7 x 12,1 - 2 x 3,7

= 3,7 x ( 12,1 - 2 )

= 3,7 x 10,1 = 37,37

1/2 : 0.5 - 1/4 : 0.25 + 1/8 : 0.125 - 1/10 : 0. 1

= 1 - 1  +  1 - 1

= 0 + 0

= 0

\(\frac{1}{2}:0,5-\frac{1}{4}:0,25+\frac{1}{8}:0,125-\frac{1}{10}:0,1\)

\(=\frac{1}{2}:\frac{1}{2}-\frac{1}{4}:\frac{1}{4}+\frac{1}{8}:\frac{1}{8}-\frac{1}{10}:\frac{1}{10}\)

\(=1-1+1-1=0\)

bằng 0

1/2:0,5-1/4:0,25+1/8:0,125-1/10:0,1

=1-1+1-1

=0

\(\dfrac{1}{10}+\dfrac{1}{2}:0,5-\dfrac{1}{4}:0,25+\dfrac{1}{8}:0,125\)

\(=\dfrac{1}{10}+\dfrac{1}{2}\times2-\dfrac{1}{4}\times4+\dfrac{1}{8}\times8\)

\(=\dfrac{1}{10}+1-1+1\)

\(=\dfrac{1}{10}+1=\dfrac{1}{10}+\dfrac{10}{10}=\dfrac{11}{10}\)

\(\dfrac{1}{10}+\dfrac{1}{2}\div0,5-\dfrac{1}{4}\div0,25+\dfrac{1}{8}\div0,125\)

= 0,1 + 0,5 x 2 - 0,25 x 4 + 0,125 x 8

= 0,1 + 1 - 1 + 1

= 1,1 - 1 +1

= 0,1 + 1

= 1,1

`#3107.101107`

\(\dfrac{1}{10}+\dfrac{1}{2}\cdot0,5-\dfrac{1}{4}\div0,25+\dfrac{1}{8}\div0,125\)

\(=\dfrac{1}{10}+\left(\dfrac{1}{2}\div0,5\right)-\left[\left(\dfrac{1}{2}\right)^2\div\left(0,5\right)^2\right]+\left(\dfrac{1}{2}\right)^3\div\left(0,5\right)^3\)

\(=\dfrac{1}{10}+\left(\dfrac{1}{2}\div0,5\right)-\left(\dfrac{1}{2}\div0,5\right)^2+\left(\dfrac{1}{2}\div0,5\right)^3\)

\(=\dfrac{1}{10}+1-1^2+1^3\)

\(=\dfrac{1}{10}+1\)

\(=\dfrac{11}{10}\)

`25%+3/4+1/2:0,5-1/4:0,15+1/8:0,125`

`=1/4+3/4+1/2xx2-1/4xx4+1/8xx8`

`(1/4+3/4)+(1/2xx2)-(1/4xx4)+(1/8xx8)`

`=1+1-1+1`

`=2`