\(S=1+2+2^2+2^3+2^4+2^5+2^6+2^7\)

\(\Rightarrow S=\left(1+2\right)+\left(2^2+2^3\right)+\left(2^4+2^5\right)+\left(2^6+2^7\right)\)

\(\Rightarrow S=\left(1+2\right)+2^2\left(1+2\right)+2^4\left(1+2\right)+2^6\left(1+2\right)\)

\(\Rightarrow S=\left(1+2\right)\left(1+2^2+2^4+2^6\right)\)

\(\Rightarrow S=3\left(1+2^2+2^4+2^6\right)⋮3\)

S=(1+2)+...+2^6(1+2)=3(1+...+2^6)⋮3

Bài 3:

\(A=5+5^2+..+5^{12}\)

\(5A=5\cdot\left(5+5^2+..5^{12}\right)\)

\(5A=5^2+5^3+...+5^{13}\)

\(5A-A=\left(5^2+5^3+...+5^{13}\right)-\left(5+5^2+...+5^{12}\right)\)

\(4A=5^2+5^3+...+5^{13}-5-5^2-...-5^{12}\)

\(4A=5^{13}-5\)

\(A=\dfrac{5^{13}-5}{4}\)

S = 1 + 2 + 2² + 2³ + 2⁴ + 2⁵ + 2⁶ + 2⁷

S = ( 1 + 2 ) + ( 2² + 2³ ) + ( 2⁴ + 2⁵ ) + ( 2⁶ + 2⁷ )

S = 3 + 2² . ( 1 + 2 ) + 2⁴ . ( 1 + 2 ) + 2⁶ . ( 1 + 2 )

S = 3 + 2² . 3 + 2⁴ . 3 + 2⁶ . 3

S = 3 . ( 1 + 2² + 2⁶ ) chia hết cho 3

cái lòn con gái banh ra , con kẹt con trai thụt vào rồi liếm vào đó...........( tự hiểu, phê chưa)

S = 1 + 2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7

S = ( 1 + 2 ) + ( 2^2 + 2^3 ) + ( 2^4 + 2^5 ) + ( 2^6 + 2^7 )

S =      3       + 2^2 . ( 1 + 2 ) + 2^4 . ( 1 + 2 ) + 2^6 . ( 1 + 2 )

S =      3       + 2^2 .      3      + 2^4 .       3      + 2^6 .    3

S =      3 . ( 2^2 + 2^4 + 2^6 )

Vi 3 chia het cho 3 nen 3 . ( 2^2 + 2^4 + 2^6 ) chia het cho 3

hay S chia het cho 3

\(S=1+2+2^2+2^3+2^4+2^5+2^6+2^7\)

\(\Rightarrow S=\)\(S=(1+2)+(2^2+2^3)+(2^4+2^5)+(2^6+2^7)\)

\(\Rightarrow S=\left(1+2\right)+2^2\left(1+2\right)+2^4\left(1+2\right)+2^6\left(1+2\right)\)

\(\Rightarrow S=3\cdot\left(1+2^2+2^4+2^6\right)⋮3\)

VẬY \(S⋮3\left(đpcm\right)\)

S = 1 + 2 + 2² + 2³ +...+2⁷ ( có 8 số hạng)

S = (1+2) + (2² + 2³) + ...+ (2⁶ +2⁷)

S = 3 + 2².(1+2) + ...+ 2⁶.(1+2)

S = 3.(1+2²+...+2⁶) chia hết cho 3

S=(1+2)+(2²+2³)+.....+(2⁶+2⁷)

S=   3   +2²(1+2)+....+2⁶(1+2)

S=   3   +2².3+.....+2⁶.3

S=   3(1+2²+.....+2⁶)chia hết cho 3

Tick mình đầu tiên nha

giup minh voi sap phai nop roi

câu a Achia hết cho 128