a) 19/23

b) -5/11

a) 8/3 x 2/5 x 3/8 x 10 x 19/92

= ( 8/3 x 3/8 ) x ( 2/5 x 10 ) x 19/92

=     1 x 4 x 19/92

=     4 x 19/92   =   76/92  =  19/23

b) N = 5/7 x 5/11 + 5/7 x 2/11 - 5/7 x 14/11

       = 5/7 x ( 5/11 + 2/11 - 14/11 )

       = 5/7 x ( -7/11 )

       =   -5/11

Ban Tran Nguyen Dam Nhien trinh bay cach giai duoc khong?

c) 5 . 25 . 2 . 16 . 4 = (5 . 2)(25.4) . 16 = 10 . 100. 16 = 16000

\(M=\dfrac{8}{3}\cdot\dfrac{2}{5}\cdot\dfrac{3}{8}\cdot10\cdot\dfrac{19}{92}\\ =\dfrac{8\cdot2\cdot3\cdot10\cdot19}{3\cdot5\cdot8\cdot92}\\ =\dfrac{8\cdot2\cdot3\cdot2\cdot5\cdot19}{3\cdot5\cdot8\cdot2\cdot2\cdot23}\\ =\dfrac{19}{23}\)

\(N=\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}-\dfrac{5}{7}\cdot\dfrac{14}{11}\\ =\dfrac{5}{7}\cdot\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\\ =\dfrac{5}{7}\cdot\left(-\dfrac{7}{11}\right)\\ =-\dfrac{5}{11}\)

\(Q=\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\\ =\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\\ =\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot\left(\dfrac{1}{6}-\dfrac{1}{6}\right)\\ =\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot0\\ =0\)

Áp dụng tính chất phân phối của phép nhân đối với phép cộng: a(b+c)=ab+ac ta có:

25.12 = 25.(10 + 2) = 25.10 + 25.2 = 250 + 50 = 300.

34.11 = 34.(10 + 1) = 34.10 + 34 = 340 + 34 = 374.

47.101 = 47.(100 + 1) = 47.100 + 47.1 = 4700 + 47 = 4747.

Áp dụng tính chất kết hợp của phép nhân a.b.c = a.(b.c) =(a.b).c ta có:

15.4 = (3.5).4 = 3.(5.4) = 20.3 = 60 hoặc 15.4 = 15.(2.2) = (15.2).2 = 30.2 = 60.

25.12 = 25.(4.3) = (25.4).3 = 100.3 = 300.

125.16 = 125.(8.2) = (125.8).2 = 1000.2 = 2000

\(...=57.\left(12+15+63\right)=57.90=5130\)

\(12.57+57.15+63.57\\ \Rightarrow57.\left(12+15+63\right).\\ \Rightarrow57.90=5130.\)

12.57+57.15+63.75

=57.(12+15+63)

=57.90

=5130

a) \(\frac{17}{23}.\frac{18}{16}.\frac{23}{17}-\left(-80\right)-\frac{3}{4}\)

= \(\frac{17.18.23}{23.16.17}+80-\frac{3}{4}\)

= \(\frac{9}{8}+80-\frac{3}{4}\)

= \(\frac{3}{8}+80=\frac{643}{8}\)

b) \(\frac{5}{11}.\frac{18}{29}-\frac{5}{11}.\frac{8}{29}+\frac{5}{11}.\frac{19}{29}\)

= \(\frac{5}{11}.\left(\frac{18}{29}-\frac{8}{29}+\frac{19}{29}\right)\)

= \(\frac{5}{11}.1=\frac{5}{11}\)

c) \(\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).\left(\frac{1}{3}+\frac{1}{4}-\frac{7}{12}\right)\)

= \(\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).0\)

= \(0\)

25.5.4.27.2 = (25.4).(5.2).27 = 100.10.27 = 27000