sắp xếp từ bé đén lớn :

\(\frac{3}{4};\frac{5}{4};\frac{4}{3};\frac{5}{3}\)

tk mình nha mình kp vs bạn r đóa

a: -10/8<-1

-19/19=-1

-1<-2/10<0

0<5/12<1<17/15

=>17/15>1>5/12>-2/10>-19/19>-10/8

b: -1/3=-4/12; -5/12=-5/12; -3/4=-9/12; -1/4=-3/12; -7/12=-7/12

=>-3/4<-7/12<-5/12<-1/3<-1/4

Theo thứ tự từ lớn đến bé:\(\dfrac{17}{15};1;\dfrac{5}{12};0;\dfrac{2}{-10};-\dfrac{19}{19};-\dfrac{10}{8}\)

Theo thứ tự từ bé đến lớn : \(-\dfrac{3}{4};-\dfrac{7}{12};-\dfrac{5}{12};-\dfrac{1}{3};\dfrac{1}{-4}\)

a, 9; 7; 5; 2

b, 1; 6; 4; 8

a) 9, 7, 5 2

b) 1, 4, 6, 8

a. 9-7-5-2

b. 1-4-6-8

Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\)     ;    \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\)     ;     \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\) 

\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\)     ;    \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)

⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)
 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 . 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 .

4/3;9/20;4/5;9/10

\(\frac{4}{5}< \frac{5}{6}< \frac{7}{8}< \frac{6}{5}\)

\(\frac{4}{5};\frac{5}{6};\frac{7}{8};\frac{6}{5}\)

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4fdbn bn

\(\frac{3}{4}< \frac{3}{2}< \frac{5}{3}< \frac{5}{2}< \frac{6}{1}< \frac{29}{4}\)

thanks

5/9,8/9,4/4,5/4