Trả lời:

x³ - 8x + 2x ( x - 2 )

= x³ - 8x + 2x² - 4x

= x ( x² - 8 + 2x - 4 )

= x ( x² + 2x - 12 )

cần gấp nha , mik chọn cho

a: \(x^4-2x^3+x^2-2x\)

\(=\left(x^4-2x^3\right)+\left(x^2-2x\right)\)

\(=x^3\left(x-2\right)+x\left(x-2\right)\)

\(=x\left(x-2\right)\left(x^2+1\right)\)

b: \(x^4+x^3-8x-8\)

\(=\left(x^4+x^3\right)-\left(8x+8\right)\)

\(=x^3\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3-8\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right)\)

Trả lời:

2x³ - 8x² - 8x 

= 2x ( x² - 4x - 4 )

\(8x^2-2x-3=8x^2+4x-6x-3=4x\left(2x+1\right)-3\left(2x+1\right)=\left(4x-3\right)\left(2x+1\right)\)

\(8x^2-2x-3=\left(4x-3\right)\left(2x+1\right)\)

2x³ - x² - 8x + 4 = x²(2x - 1) - 4(2x - 1) = (2x - 1)(x - 2)(x + 2)

2x³-x² -8x+4=(2x³-x²)-(8x+4)

                     =x²(2x-1)-4(2x-1)

                     = (2x-1)(x²-4)

                    = (2x-1)(x-2)(x+2)

\(2x^3-5x^2+8x-3\)

\(\Leftrightarrow2x^3-x^2-4x^2+2x+6x+3\)

\(\Leftrightarrow x^2\cdot\left(2x-1\right)-2x\cdot\left(2x-1\right)+3\cdot\left(2x+1\right)\)

\(\Leftrightarrow\left(2x-1\right)\cdot\left(x^2-2x+3\right)\)

\(2x^3-5x^2+8x-3\)

\(=2x^3-x^2-4x^2+2x+6x-3\)

\(=x^2\left(2x-1\right)-2x\left(2x-1\right)+3\left(2x-1\right)\)

\(=\left(2x-1\right)\left(x^2-2x+3\right)\)

 = 2x^3  - 4x^2 - x^2 + 2x + 6x - 3 

 = 2x^2 ( x - 1/2 ) - x ( x - 1/2 ) +3 ( x - 1/2 )

= ( x - 1/2 )( 2x^2 - x + 3 )