Các kao nhân giúp toi vs
B1 Tính
A=(0,125)^100*8^111
B=2^13*9^4/6^6*8^3
B2Tìm x
a.
9(x-1)^2-4/9:2/9=1/4
b.(3*x-1)^6=(3x-1)^4
Cảm ơn nhìu!!!!!
Tui cần hơi hơi gấp ạ :((
giúp toi vs :((( toi cần gấp :((((
Tìm x
a.
9(x-1)^2-4/9:2/9=1/4
b.(3*x-1)^6=(3x-1)^4
Cảm ơn nhìu :((
a) \(9\left(x-1\right)^2-\frac{4}{9}\div\frac{2}{9}=\frac{1}{4}\)
\(\Leftrightarrow9\left(x-1\right)^2-2=\frac{1}{4}\)
\(\Leftrightarrow9\left(x-1\right)^2=\frac{9}{4}\)
\(\Leftrightarrow\left(x-1\right)^2=\frac{1}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{1}{2}\\x-1=-\frac{1}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{2}\end{cases}}\)
b) \(\left(3x-1\right)^6=\left(3x-1\right)^4\)
\(\Leftrightarrow\left(3x-1\right)^6-\left(3x-1\right)^4=0\)
\(\Leftrightarrow\left(3x-1\right)^4\cdot\left[\left(3x-1\right)^2-1\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(3x-1\right)^4=0\\\left(3x-1\right)^2=1\end{cases}}\Leftrightarrow x\in\left\{0;\frac{1}{3};\frac{2}{3}\right\}\)
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
a.x/5=2/5 , b.3/-8=6/-x , c.1/9=-2x/10 , d.3/x-5=-9/x+2 , e.x/-2=-8/x , g.(x+2)mụ2=-8/x , h.-24/-6=1/3=4/y muj2 mik đg cần gấp ạ ,cảm ơn nhiều
a) \(\dfrac{x}{5}=\dfrac{2}{5}\)
\(\Rightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy x = 2
b) ĐKXĐ: \(x\ne0\)
\(\dfrac{3}{-8}=\dfrac{6}{-x}\)
\(\Rightarrow-3x=-48\)
\(\Leftrightarrow x=16\)
Vậy x = 16
c) \(\dfrac{1}{9}=\dfrac{-2x}{10}\)
\(\Rightarrow-18x=10\)
\(\Leftrightarrow x=-\dfrac{5}{9}\)
Vậy \(x=-\dfrac{5}{9}\)
d) ĐKXĐ: \(x\ne0\)
\(\dfrac{3}{x}-5=\dfrac{-9}{x}+2\)
\(\Leftrightarrow\dfrac{3-5x}{x}=\dfrac{-9+2x}{x}\)
\(\Rightarrow3-5x=-9+2x\)
\(\Leftrightarrow7x=12\)
\(\Leftrightarrow x=\dfrac{12}{7}\)
Vậy \(x=\dfrac{12}{7}\)
e) ĐKXĐ: \(x\ne0\)
\(\dfrac{x}{-2}=\dfrac{-8}{x}\)
\(\Rightarrow x^2=16\)
\(\Leftrightarrow x=\pm4\)
Vậy \(x=\pm4\)
a) Ta có: \(\dfrac{x}{5}=\dfrac{2}{5}\)
\(\Leftrightarrow x=\dfrac{2\cdot5}{5}=2\)
Vậy: x=2
b) Ta có: \(\dfrac{3}{-8}=\dfrac{6}{-x}\)
\(\Leftrightarrow-x=\dfrac{6\cdot\left(-8\right)}{3}=-16\)
hay x=16
Vậy: x=16
Bài 1 : Tính
a) (2^3 x 9^4 + 9^3 x 45 ) : ( 9^2 x 10 - 9^2)
b) 100 - [75 - ( 7 - 2)^2 ]
c) ( 20 x 2^4 + 12 x 2^4 ) - 48 x 2^2 ) : 8^2
Bài 2: tìm X
a) 390 - ( X - 7 ) = 169 : 13
b) ( X - 140 ) : 7 = 3^3 - 2^3 x 3
c) X - 6 : 2 - ( 48 - 42) : 2 : 6 - 3 = 0
d) X + 5 - 2 - ( 23 +16 x 3 : 6 -15 ) = 0
e) ( 19X + 2 x 5^2 ) :14 = ( 13 - 8 ) 2 - 4^2
f) 2 x 3X = 10 x 2^12 + 8 x 27^4
CÁC BẠN ƠI, GIÚP MÌNH VỚI , MÌNH ĐANG CẦN GẤP , BẠN NÀO LÀM XONG MỖ NGÀY MÌNH SẼ TICK CHO 1 CÁI
CÁC BẠN ƠI GIÚP MK ĐI MÀ, LÀM ƠN ĐÓ
a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)
=\(9^4.13:9^3=13.9=117\)
b) 100-(75-25)=100-50=50
\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)
\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)
\(< =>\left(52488+32805\right):\left(810-81\right)\)
\(< =>85293:729\)
\(< =>117\)
\(b,100-\left[75-\left(7-2\right)^2\right]\)
\(< =>100-\left[75-\left(5\right)^2\right]\)
\(< =>100-\left[75-25\right]\)
\(< =>100-50\)
\(< =>50\)
\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)
\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)
\(< =>\left[2^4\cdot32\right]-192:8^2\)
\(< =>\left[16\cdot32\right]-192:64\)
\(< =>512-3\)
\(< =>509\)
Bài 1: Tính nhanh
a,6/1*3*7+6/3*7*9+6/7*9*13+6/9*13*15+6/13*15*19
b,1/1*3*7+1/3*7*9+1/7*9*13+1/9*13*15+1/13*15*19
c,1/2*4*6+1/4*6*8+1/6*8*10+1/8*10*12*14+...+1/96*98*100
d,5/1*5*8+5/5*8*12+5/8*12*15+...+5/33*36*40
giúp mik vs các bạn anh chị gì đó ghi hết cách làm và kết quả ra nha
Lưu ý:* là dấu nhân / là phần
\(a,=\frac{7-1}{1.3.7}+\frac{9-3}{3.7.9}+\frac{13-7}{7.9.13}+\frac{15-9}{9.13.15}\)\(+\frac{19-13}{13.15.19}\)
\(=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}\)
\(=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}\)
\(b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)\)
làm giống như trên
\(c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}\)
\(d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}\)
P/S: . là nhân nha
sxasxsxxsxsxssxsxsxsxsx232332321322
Là B bạn nha
Vì dãy số tự nhiên không giới hạn nha bạn
tính:
a. 1/2 x ( 4/3 + 2/5 ) - 3/4 x ( 8/9 + 13/3 )
b. 1/5 : 1/10 - 1/3 x ( 6/5 - 9/4 )
c. -3/4 x ( 20/9 - 8/15 ) - 5/3 x 9/-10
p/s: các bạn làm hộ mình nha, mình đang cần gấp. cảm ơn rất nhiều
a)=1/2 . 8/15 - 3/4.47/9
=4/15 - 47/12
=-73/20
b)=2-1/3 . -21/20
=2+7/20
=47/20
Bài 1: Tính
a) -3/20 + -7/4
b) 6 2/3 - 4 2/3
c) -3/10 + 7/12
d) 35/-9 . 81/7
e) -2/5 - -3/4
f) 5/23 . 7/26 + 5/23 . 9/26
g) -3/12 : 4/15
h) 1 1/6 - 3 1/3
i) -2/5 . (-3) + 3/8 . 4/-10
j) -13/17 + (13/-21 + -4/17)
a) \(\dfrac{-3}{20}\) + \(\dfrac{-7}{4}\) =\(\dfrac{-3}{20}\) + \(\dfrac{-35}{20}\) = -2
b) 6 và \(\dfrac{2}{3}\) - 4 và \(\dfrac{2}{3}\) = 2
c) \(\dfrac{-3}{10}\) + \(\dfrac{7}{12}\) = \(\dfrac{-18}{60}\) + \(\dfrac{35}{60}\) =\(\dfrac{17}{60}\)
d) \(\dfrac{35}{-9}\) . \(\dfrac{81}{7}\) = \(\dfrac{-35}{9}\) . \(\dfrac{81}{7}\) = 45
e) \(\dfrac{-2}{5}\) - \(\dfrac{-3}{4}\) = \(\dfrac{-8}{20}\) - \(\dfrac{-15}{20}\) = \(\dfrac{-8}{20}\) + \(\dfrac{15}{20}\) =\(\dfrac{7}{20}\)
f) \(\dfrac{5}{23}\) . \(\dfrac{7}{26}\) + \(\dfrac{5}{23}\) .\(\dfrac{9}{26}\) = \(\dfrac{5}{23}\) . ( \(\dfrac{7}{26}\) + \(\dfrac{9}{26}\) )= \(\dfrac{5}{23}\) . \(\dfrac{8}{13}\) = \(\dfrac{40}{299}\)
g) \(\dfrac{-3}{12}\) : \(\dfrac{4}{15}\) =\(\dfrac{-3}{12}\) . \(\dfrac{15}{4}\) =\(\dfrac{-5}{8}\)
h) 1 và \(\dfrac{1}{6}\) - 3 và \(\dfrac{1}{3}\) =\(\dfrac{7}{6}\) -\(\dfrac{10}{3}\) = \(\dfrac{-13}{6}\)
i) \(\dfrac{-2}{5}\) . (-3) + \(\dfrac{3}{8}\) . \(\dfrac{4}{-10}\) =(\(\dfrac{-2}{5}\) .\(\dfrac{-4}{10}\)) + [(-3) . \(\dfrac{3}{8}\)
= \(\dfrac{4}{25}\) + \(\dfrac{-9}{8}\) = \(\dfrac{32}{200}\) + \(\dfrac{-225}{200}\) = \(\dfrac{-193}{200}\)
j) \(\dfrac{-13}{17}\) + (\(\dfrac{13}{-21}\) + \(\dfrac{-4}{17}\) )
= ( \(\dfrac{-13}{17}\) + \(\dfrac{-4}{17}\) )+\(\dfrac{-13}{21}\)
= -1+\(\dfrac{-13}{21}\)
= \(\dfrac{-21}{21}\) + \(\dfrac{-13}{21}\) = \(\dfrac{-34}{21}\)
Khôi nguyễn
2 phần 3 + 3 phần 4 + 4 phần 5 =
8 phần 5 + 7 phần 6 + 10 phần 9 + 1 phần 2 =
15 phần 17 - 11 phần 13 + 1 phần 2 mươi 6 =
9 phần 12 x 4 phần 3 : 8 phần 5 =
4 phần 5 x 15 phần 8 : 5 phần 7 =
Mong các bạn giúp mình mik đag cần gấp ạ
Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)