a)= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x 0

=0 ( vì 0 nhân với số nào cũng bằng 0)

b)= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 9-9)

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x 0

= 0 ( vì 0 nhân với số nào cũng bằng 0)

c)=( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x 0

=0 ( vì 0 nhân với số nào cũng bằng 0 )

a ) ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x ( 32 x 11 - 3200 x 0 , 1 - 32 )

= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x ( 352 - 320 - 32 )

= ( 81 , 6 x 27 , 3 – 17 , 3 x 81 , 6 ) x 0

= 0.

b ) ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 1 , 8 x 5 – 0 , 9 x 10 )

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x ( 9 - 9 )

= ( 13 , 75 – 0 , 48 x 5 ) x ( 42 , 75 : 3 + 2 , 9 ) x 0

= 0

c ) ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x ( 11 x 9 – 900 x 0 , 1 – 9 )

= ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x ( 99 - 90 - 9 )

= ( 792 , 81 x 0 , 25 + 792 , 81 x 0 , 75 ) x 0

= 0.

Hok tốt !

a)32 x 11 -3200x 0,1 -32

=32x11-32x100x0,1-32

=32x(11-10-1)=32x0=0

nên(81,6x27,3-17,3x81,6)x(32x11-3200x0,1-32)

=(81,6x27,3-17,3x81,6)x0

=0

b)1,8x5 -0,9x10=1,8x5-0,9x2x5

=1,8x5-1,8x5

=0

nên (13,75-0,48 x 5)x(42,75:3+2,9)x(1,8x5-0,9x10)=0

c)(792,81x0,25+792,81x0,75)x(11x9-900x0,1-9)

=792,81x(0,25+0,75)x(99-90-9)

=792,81x1x0

=0

a/ /1-2x/=125+75=200

=> 1-2x=200 hoac 1-2x=-200

=> x=-199/2 hoac x=201/2

b/ /x+4/=5-8+2004=2001

=> x+4=2001 hoac x+4=-2001

=> x=1992 hoac x=-2005

c/ /x-9/-1=(-45)-81+2006=1880

=> /x-9/ = 1880+1=1881

=> x-9=1881 hoac x-9=-1881

=> x=1990 hoac x=-1872

a,  3^9:3^2=3^7

b,  (3/5)^15:(3/5)^10=(3/5)^5

c,  (5.3.3)^10.5^10 / (5.5.3)^10=5^10.3^10.3^10.5^10 / 5^10.5^10.3^10=5^20.3^20 / 5^20.3^10=3^10

\(a) \sqrt{4x^2− 9} = 2\sqrt{x + 3}\)

\(ĐK:x\ge\dfrac{3}{2}\)

\(pt\Leftrightarrow4x^2-9=4\left(x+3\right)\)

\(\Leftrightarrow4x^2-9=4x+12\)

\(\Leftrightarrow4x^2-4x-21=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1-\sqrt{22}}{2}\left(l\right)\\x=\dfrac{1+\sqrt{22}}{2}\left(tm\right)\end{matrix}\right.\)

\(b)\sqrt{4x-20}+3.\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)

\(ĐK:x\ge5\)

\(pt\Leftrightarrow2\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)

\(\Leftrightarrow2\sqrt{x-5}=4\Leftrightarrow\sqrt{x-5}=2\)

\(\Leftrightarrow x-5=4\Leftrightarrow x=9\left(tm\right)\)

\(c)\dfrac{2}{3}\sqrt{9x-9}-\dfrac{1}{4}\sqrt{16x-16}+27.\sqrt{\dfrac{x-1}{81}}=4\)

ĐK:x>=1

\(pt\Leftrightarrow2\sqrt{x-1}-\sqrt{x-1}+3\sqrt{x-1}=4\)

\(\Leftrightarrow4\sqrt{x-1}=4\Leftrightarrow\sqrt{x-1}=1\)

\(\Leftrightarrow x-1=1\Leftrightarrow x=2\left(tm\right)\)

\(d)5\sqrt{\dfrac{9x-27}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{81}}=0\)

\(ĐK:x\ge3\)

\(pt\Leftrightarrow3\sqrt{x-3}-\dfrac{14}{3}\sqrt{x-3}-7\sqrt{x^2-9}+6\sqrt{x^2-9}=0\)

\(\Leftrightarrow-\dfrac{5}{3}\sqrt{x-3}-\sqrt{x^2-9}=0\Leftrightarrow\dfrac{5}{3}\sqrt{x-3}+\sqrt{x^2-9}=0\)

\(\Leftrightarrow(\dfrac{5}{3}+\sqrt{x+3})\sqrt{x-3}=0\)

\(\Leftrightarrow\sqrt{x-3}=0\)    (vì \(\dfrac{5}{3}+\sqrt{x+3}>0\))

\(\Leftrightarrow x-3=0\Leftrightarrow x=3\left(nhận\right)\)

9 + 18 + 27 + 36 + 45 + 54 + 63 + 72 + 90 = 414

kết quả là :

   414 

      đs...

1 x 9 = 9

2 x 9 = 18

3 x 9 = 27

4 x 9 = 36

5 x 9 = 45

6 x 9 = 54

7 x 9 = 63 

8 x 9 =72

9 x 9 = 81

10 x 9 = 90

Câu hỏi là : 9 + 18 + 27 + 36 + 45 + 54 + 63 + 72 + 81 +90 =414

giúp mik với mik sắp phải nộp rồi!!!

a) 27 . 3² . 3^x+1 = 3⁵ . 81

3³ . 3² . 3^x+1 = 3⁵ . 3⁴

3⁵ . 3^x+1 = 3⁵ . 3⁴

=> 3^x+1 = 3⁴

=> x + 1 = 4

x = 4 - 1

x = 3

Vậy x = 3

b) 2² . x + 3 . 2³ = 45 . 100⁰

2² . (x + 3 . 2) = 45 . 1

4 . (x + 6) = 45

x + 6 = 45 : 4

x + 6 = 11,25

x = 11,25 - 6

x = 5,25

Vậy x = 5,25

Ủng hộ mk nha !!! ^_^

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