\(2xy-x-y=3\)

\(\Rightarrow4xy-2x-2y=6\)

\(\Rightarrow2x\left(2y-1\right)-\left(2y-1\right)=7\)

\(\Rightarrow\left(2y-1\right)\left(2x-1\right)=7=1\left(-7\right)=\left(-1\right)7=\left(-7\right)1=7\left(-1\right)\)

Làm nốt

\(\frac{y}{3}-\frac{1}{x}=\frac{1}{3}\)

\(\Rightarrow\frac{xy-3}{3x}=\frac{1}{3}\)

\(\Rightarrow3xy-9=3x\)

\(\Rightarrow3xy-3x=9\)

\(\Rightarrow3x\left(y-1\right)=9=3\cdot3=\left(-3\right)\left(-3\right)=9\cdot1=\left(-9\right)\left(-1\right)=\left(-1\right)\left(-9\right)=1\cdot9\)

Làm nốt.

\(xy-x+2y=3\)

\(\Rightarrow x\left(y-1\right)+2\left(y-1\right)=1\)

\(\Rightarrow\left(y-1\right)\left(x+2\right)=1=1\cdot1=\left(-1\right)\left(-1\right)\)

Tới đây bí=((

\(\dfrac{x}{3}=\dfrac{y}{7};\dfrac{y}{2}=\dfrac{z}{5}\Rightarrow\dfrac{x}{6}=\dfrac{y}{14}=\dfrac{z}{35}\)

Áp dung t/c dãy tỉ số = nhau, ta có :

\(\dfrac{x}{6}=\dfrac{y}{14}=\dfrac{z}{35}=\dfrac{x+y+z}{6+14+35}=\dfrac{-110}{55}=-2\)

\(\Rightarrow\dfrac{x}{6}=-2\Rightarrow x=-12\)

\(\dfrac{y}{14}=-2\Rightarrow y=-28\)

\(\dfrac{z}{35}=-2\Rightarrow z=-70\)

x = - 12

y = - 28

z = - 70

giúp mik zứi😭😭😭

a; 60 \(\times\) (\(\dfrac{7}{12}\) + \(\dfrac{4}{15}\)) 

 =  60 \(\times\) \(\dfrac{7}{12}\) + 60 \(\times\) \(\dfrac{4}{15}\)

= 35 + 16

= 51

b; \(\dfrac{1}{2}\) \(\times\)\(\dfrac{2}{3}\) \(\times\) \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{5}\) \(\times\) \(\dfrac{5}{6}\) \(\times\) \(\dfrac{7}{8}\) \(\times\) \(\dfrac{8}{9}\)

= \(\dfrac{2\times3\times4\times5\times6\times7\times8}{2\times3\times4\times5\times6\times7\times8}\) \(\times\) \(\dfrac{1}{9}\)

= 1 \(\times\) \(\dfrac{1}{9}\)

= \(\dfrac{1}{9}\)

20,7 + 1,47 : 7 - 0,23 x 5

= 20,7 + 0,21 - 1,15

= 20,91 - 1,15 

= 19,76

=20,7+0,21-1,15

=20,91-1,15

=19,76

k mình đi

Ta có: \(\frac{3}{x}=\frac{y}{35}\)

\(\Leftrightarrow x.y=3.35\)

\(\Leftrightarrow x.y=105\). Phân tích 105 ra thừa số nguyên tố. Ta có:

105 = 3 x 5 x 7

Tách 3 và 5 x 7 thành một cặp

Đặt 3 = x  (1)

5 x 7 = y

Suy ra y = 35  (2)

Thế (1) , (2) vào, ta có:

\(\frac{3}{x}=\frac{y}{35}\Leftrightarrow\frac{3}{3}=\frac{35}{35}\)(đúng)

Có \(\frac{3}{x}=\frac{y}{35}\)

\(\Rightarrow\)\(xy=3.35\)

\(\Rightarrow xy=105\)

Ta có:

105 = 3 . 5 . 7

\(\Rightarrow\)x . y = 3 . 5 . 7

Chia 3 và 5 . 7 vào x và y

\(\Rightarrow\)x = 3 ; y = 5 . 7 = 35

Thay vào ta có:

\(\frac{3}{3}=\frac{35}{35}\)( thỏa mãn )

Vậy x = 3 ; y = 35

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