Áp dụng tính chất của dãy tỷ số bằng nhau

\(\frac{3x-1}{40-5x}=\frac{25-3x}{4x-34}=\frac{\left(3x-1\right)+\left(25x-3x\right)}{\left(40-5x\right)+\left(5x-34\right)}=4\)

\(\Rightarrow\frac{3x-1}{40-5x}=4\)

\(\Rightarrow3x-1=3\left(40-5x\right)\)

\(\Rightarrow3x-1=160-20x\)

\(\Rightarrow23x=161\)

\(\Rightarrow x=161:23\)

\(\Rightarrow x=7\)

cái gì đấy lỗi à

lỗi

Lỗi rồi nha! -_-

=>(2x+3).(10x+2)=(5x+2).(4x+5)

=>(2x.10x)+(2x.2)+(3.10x)+(3.2)=(5x.4x)+(5x.5)+(2.4x)+(2.5)

=>20x²+4x+30x+6=20x²+25x+8x+10

=>20x²-20x²+4x-8x+30x-25x=10-6

=>0+4x-8x+30x-25x=4

=>-4x+30x-25x=4

=>26x-25x=4

=>x=4

B)=>(3x-1).(5x-34)=(40-5x).(25-3x)

=>15x²-102x-5x+34=1000-120x-125x+15x²

=>15x²-107x+34=1000-245x+15x²

=>15x²-15x²-107x+245x=1000-34

=>0-107x+245x=966

=>138x=966

=>x=7

A,=>(2x+3).(10x+2)=(5x+2).(4x+5)

=>(2x.10x)+(2x.2)+(3.10x)+(3.2)=(5x.4x)+(5x.5)+(2.4x)+(2.5)

=>20x2+4x+30x+6=20x2+25x+8x+10

=>20x2-20x2+4x-8x+30x-25x=10-6

=>0+4x-8x+30x-25x=4

=>-4x+30x-25x=4

=>26x-25x=4

=>x=4

a)2/3x=41/18

x=41/12

b)lxl=13/4

=>x=+-13/4

c)lx-1/2l=4

=>x+1/2=+-4

th1x+1/2=-4

=>x=-9/2

th2 x+1/2=4

=>x=3.5

d)x^2=9/17

câu này mk bó tay

e: \(\dfrac{17}{5}:x=\dfrac{34}{5}:\dfrac{4}{3}=\dfrac{34}{5}\cdot\dfrac{3}{4}=\dfrac{102}{20}=\dfrac{51}{10}\)

\(\Leftrightarrow x=\dfrac{17}{5}:\dfrac{51}{10}=\dfrac{17}{5}\cdot\dfrac{10}{51}=\dfrac{10}{5}\cdot\dfrac{17}{51}=2\cdot\dfrac{1}{3}=\dfrac{2}{3}\)

f: \(x:\dfrac{4}{5}=\dfrac{25}{8}:\dfrac{5}{4}=\dfrac{25}{8}\cdot\dfrac{4}{5}=\dfrac{100}{40}=\dfrac{5}{2}\)

\(\Leftrightarrow x=\dfrac{5}{2}\cdot\dfrac{4}{5}=\dfrac{4}{2}=2\)

g: \(\left(0.25x+2012\right)\cdot2013=\left(50+2012\right)\cdot2013\)

\(\Leftrightarrow0.25x+2012=50+2012\)

\(\Leftrightarrow0.25x=50\)

hay x=200

h: \(\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{3}=\dfrac{7}{4}-1=\dfrac{3}{4}\)

\(\Leftrightarrow x-\dfrac{1}{2}=\dfrac{3}{4}:\dfrac{5}{3}=\dfrac{9}{20}\)

\(\Leftrightarrow x=\dfrac{9}{20}+\dfrac{1}{2}=\dfrac{9}{20}+\dfrac{10}{20}=\dfrac{19}{20}\)