a: \(=\left(1.25\right)^{16}\cdot8^{16}\cdot8=8\cdot10^{16}\)

b: \(=\left(\dfrac{5}{2}\right)^{13}\cdot4^{13}\cdot4^2=10^{13}\cdot4^2\)

c: \(=\left(0.25\right)^4\cdot8^4\cdot8^2=2^4\cdot8^2=64\cdot16=1024\)

d: \(=\left(\dfrac{1}{2}\right)^{15}\cdot2^{18}=2^3=8\)

e: \(=\left(\dfrac{1}{3}\cdot6\right)^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=2^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=\dfrac{1}{2}\)

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b: \(\left[\left(6+\dfrac{3}{5}-3-\dfrac{3}{14}\right)\cdot\dfrac{2}{5}\right]:\left(21-1.25\right)=x:\left(5+\dfrac{5}{6}\right)\)

\(\Leftrightarrow x:\dfrac{35}{6}=\dfrac{237}{175}:\dfrac{79}{4}\)

\(\Leftrightarrow x:\dfrac{35}{6}=\dfrac{12}{175}\)

\(\Leftrightarrow x=\dfrac{2}{5}\)

Giải:

a) \(25\%-\dfrac{5}{4}+\dfrac{11}{6}\)

\(=\dfrac{1}{4}-\dfrac{5}{4}+\dfrac{11}{6}\)

\(=-1+\dfrac{11}{6}\)

\(=\dfrac{5}{6}\)

Vậy ...

b) \(75\%:\dfrac{11}{5}-\left(0,5\right)^2.\left(-7\right)+2,5\left(\dfrac{23}{3}-\dfrac{17}{3}\right)\)

\(=\dfrac{3}{4}:\dfrac{11}{5}-\dfrac{1}{4}.\left(-7\right)+2,5.2\)

\(=\dfrac{15}{44} +\dfrac{7}{4}+5\)

\(=\dfrac{23}{11}+5\)

\(=\dfrac{78}{11}\)

Vậy ...

c) \(45:\dfrac{18}{7}+50\%-1,25\)

\(=45:\dfrac{18}{7}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=\dfrac{35}{2}+\dfrac{1}{2}-\dfrac{5}{4}\)

\(=18-\dfrac{5}{4}\)

\(=\dfrac{67}{4}\)

Vậy ...

Mk ko ghi lại đề nhé

1 = \(350-4.19+4.7\)

\(=350-4.\left(19+7\right)\)

\(=350+4.26\)

\(=350-104=246\)

2 Câu này mình vẫn chưa hiểu là bạn ghi 27  3/5 tức là 27.3/5 hay 27\(\dfrac{3}{5}\)nên mk bỏ qua nhé

3 Cái đoạn 1 1/3 y chang câu 2 

4 \(=\dfrac{2}{3}+\dfrac{1}{3}.\dfrac{7}{18}.\dfrac{12}{7}\)

\(=\dfrac{2}{3}+\dfrac{7}{54}.\dfrac{12}{7}\)

\(=\dfrac{2}{3}+\dfrac{2}{9}=\dfrac{8}{9}\)

5 \(=2^2+10^2-\left[9.\left(112:8\right)-11\right].1\)

\(=4+100-\left(9.14-11\right)\)

\(=104-115\)\(=-11\)

6 Đoạn 6 3/5 y chang 2,3

7 \(=\left(\dfrac{2}{3}-1\right)+\left(\dfrac{2}{7}-\dfrac{3}{7}\right)-\left(\dfrac{1}{14}-\dfrac{3}{28}\right)\)

\(=\dfrac{-1}{3}+\dfrac{-1}{7}-\dfrac{-1}{28}\)

\(=\dfrac{-196}{588}+\dfrac{-84}{588}-\dfrac{-21}{588}\)\(=\dfrac{259}{588}\)

Làm tạm tạm thôi xl vì có 3 câu ko hiểu 

1) 2,75 - 5/6 × 2/5 = 2,75 - (5/6) × (2/5) = 2,75 - 1/3 = 2,75 - 0,33 = 2,42

2) 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 3/4) - 3/5 = 1,25 - (5/6 - 9/12) - 3/5 = 1,25 - (10/12 - 9/12) - 3/5 = 1,25 - 1/12 - 3/5 = 1,25 - 0,08 - 0,6 = 1,25 - 0,68 = 0,57

3) 4/9 × 0,75 + 8/5 + 3,125 = (4/9) × 0,75 + 8/5 + 3,125 = 0,44 + 8/5 + 3,125 = 0,44 + 1,6 + 3,125 = 0,44 + 4,725 = 5,165

4) 1,125 - 4/7 - 0,12 = 1,125 - (4/7) - 0,12 = 1,125 - 0,57 - 0,12 = 0,435 - 0,12 = 0,315

5) (1/3 + 0,4) × 3,5 + (1/6 + 0,75) × 6/5

\(=\left[\left(6+\dfrac{3}{5}-3-\dfrac{3}{14}\right)\cdot\dfrac{35}{6}\right]:\left[19.75:2.5\right]\)

\(=\left[\left(3+\dfrac{27}{70}\right)\cdot\dfrac{35}{6}\right]:\dfrac{79}{10}\)

\(=\dfrac{97}{70}\cdot\dfrac{35}{6}\cdot\dfrac{10}{79}=\dfrac{485}{474}\)

\(\frac{\left[\left(6\frac{3}{5}-3\frac{3}{14}\right)\cdot5\frac{5}{6}\right]}{\left(21-1,25\right):2,5}\)

Đặt 2 biểu thức trên là A và B

Ta có : \(A=\left[\left(6\frac{3}{5}-3\frac{3}{14}\right)\cdot5\frac{5}{6}\right]\)

\(A=\left[\left(\frac{33}{5}-\frac{45}{14}\right)\cdot\frac{35}{6}\right]\)

\(A=\left[\frac{237}{70}\cdot\frac{35}{6}\right]=\frac{79}{4}\)

Vậy A = 79/4

\(B=\left[\left(21-1,25\right):2,5\right]\)

\(B=\left[\left(21-\frac{5}{4}\right):\frac{5}{2}\right]\)

\(B=\frac{79}{4}:\frac{5}{2}=\frac{79}{4}\cdot\frac{2}{5}=\frac{79}{10}\)

Vậy B = 79/10

Do đó \(\frac{A}{B}=\frac{\frac{79}{4}}{\frac{79}{10}}=\frac{79}{4}\cdot\frac{10}{79}=\frac{10}{4}=\frac{5}{2}\)

mk cảm ơn bn nhìu

[(33/5-45/14.)35/6]:[(21-1,25):2,5]

[237/70.35/6]:[(21-1/25):2,5]

79/4:[(21-1,25):2,5]

79/4:[19,75:2,5]

79/4:79/10

79/4.10/79

5/2