\(a,\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}\)

\(taco:\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)=\frac{35}{36}\cdot\frac{-36}{35}=-1\)

\(\left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}=\frac{13}{8}\cdot\frac{8}{13}=1\)

\(=>x=0\)

\(b,\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}< x< \frac{-1}{2}+2+\frac{5}{2}\)(dau <co dau gach ngang o duoi nha)

\(taco:\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}=\frac{-5}{6}+\frac{8}{3}+\frac{-29}{3}=\frac{-5}{6}+\frac{16}{6}+\frac{-58}{6}=\frac{-47}{6}=-7,8\)

\(\frac{-1}{2}+2+\frac{5}{2}=\frac{3}{2}+\frac{5}{2}=4\)

tu do \(=>x=-7,8;...;0;1;2;3;4\)
 

1) $(-35)\cdot18+28\cdot35$

$=35\cdot(-18)+28\cdot35$

$=35\cdot(-18+28)$

$=35\cdot10$

$=350$

2) $53\cdot29-47\cdot(-29)$

$=53\cdot29-47\cdot(-1)\cdot29$

$=53\cdot29+47\cdot29$

$=29\cdot(53+47)$

$=29\cdot100$

$=2900$

3) $125\cdot(-24)+24\cdot225$

$=(-125)\cdot24+24\cdot225$

$=24\cdot(-125+225)$

$=24\cdot100$

$=2400$

4) $26\cdot(-121)-121\cdot(-36)$

$=-121\cdot[26+(-36)]$

$=-121\cdot(26-36)$

$=-121\cdot(-10)$

$=121\cdot10$

$=1210$

5) $65\cdot(-25)+25\cdot(-23)$

$=-65\cdot25+25\cdot(-23)$

$=25\cdot(-65-23)$

$=25\cdot(-88)$

$=-2200$

6) $237\cdot(-26)+26\cdot137$

$=-237\cdot26+26\cdot137$

$=26\cdot(-237+137)$

$=26\cdot(-100)$

$=-2600$

7) $30\cdot(-125)+25\cdot30$

$=30\cdot(-125+25)$

$=30\cdot(-100)$

$=-3000$

8) $(-37)\cdot69+(-31)\cdot37$

$=37\cdot(-69)+37\cdot(-31)$

$=37\cdot(-69-31)$

$=37\cdot(-100)$

$=-3700$

9) $31\cdot72-31\cdot70-31\cdot2$

$=31\cdot(72-70-2)$

$=31\cdot(2-2)$

$=31\cdot0$

$=0$

10) $(-12)\cdot47+(-12)\cdot52+(-12)$

$=-12\cdot(47+52+1)$

$=-12\cdot100$

$=-1200$

$\text{#}Toru$

1000010000803

chúc bạn học tốt~

Sai rồi họk toán vs đamê à

dãy số dài như thế này dễ lẫn lắm bạn ạ

Đề bài thiếu : \(x\inℤ\)

Ta có : 

\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)

\(\Leftrightarrow\)\(\frac{-5+16-29}{6}\le x\le\frac{-1+4+5}{2}\)

\(\Leftrightarrow\)\(\frac{-18}{6}\le x\le\frac{8}{2}\)

\(\Leftrightarrow\)\(-3\le x\le4\)

\(\Rightarrow\)\(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

Vậy \(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

Chúc bạn học tốt ~ 

=> -3</ x </ 4

=> x thuộc { -3; -2; -1; 0; 1; 2; 3; 4}

\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)

\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)

\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)

\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)

\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)

\(\Rightarrow-1\le x< 6\)

\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)

Bài b tương tự

bạn ơi bạn giải câu b được ko. mk ko biết làm câu b

Ta có : \(-\frac{5}{6}+\frac{8}{3}+\frac{29}{-6}=-3\) và \(\frac{1}{2}+2+\frac{5}{2}=5\)

Vậy -3 < x < 5. Do x \(\in\) Z nên x \(\in\) {-2; -1; 0; 1; 2; 3; 4}